Random character generator with a range of A Z 0 9 and punctuation

Question

I need to create a random character generator that return a single character  The character should range within the letters of the alphabet  numbers 0 through 9  and some characters like     -  Any example would be appreciated

User · Answer

You should first make a String that holds all of the letters/numbers that you want.
Then, make a Random. e. g. Random rnd = new Random;
Finally, make something that actually gets a random character from your String containing your alphabet.
For example,

import java.util.Random;

public class randomCharacter {
    public static void main(String[] args) {
        String alphabet = "0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ?/.,";
        Random rnd = new Random();
        char char = alphabet.charAt(rnd.nextInt(alphabet.length()));
        // do whatever you want with the character
    }
}

See this.
It's where I got this info from.

User · Answer

See below link   http   www asciitable com       public static char randomSeriesForThreeCharacter         Random r   new Random        char random 3 Char    char   48   r nextInt 47        return random 3 Char      Now you can generate a character at one time of calling

User · Answer

random char              package com company            import java util concurrent ThreadLocalRandom            public class Main                public static void main String   args                   write your code here                 char hurufBesar  randomSeriesForThreeCharacter 65 90                   char angka   randomSeriesForThreeCharacter 48 57                   char simbol   randomSeriesForThreeCharacter 33 47                   char hurufKecil  randomSeriesForThreeCharacter 97 122                   char angkaLagi   randomSeriesForThreeCharacter 48 57                    System out println hurufBesar     angka     simbol     hurufKecil     angkaLagi                              public static char randomSeriesForThreeCharacter int min int max                    int randomNumber   ThreadLocalRandom current   nextInt min  max   1                   char random 3 Char    char   randomNumber                   return random 3 Char

User · Answer

Pick a random number between  0  x   where x is the number of different symbols  Hopefully the choice is uniformly chosen and not predictable  -  Now choose the symbol representing x  Profit    I would start reading up Pseudorandomness and then some common Pseudo-random number generators  Of course  your language hopefully already has a suitable  random  function  -

User · Answer

The easiest is to do the following    Create a String alphabet with the chars that you want  Say N   alphabet length   Then we can ask a java util Random for an int x   nextInt N  alphabet charAt x  is a random char from the alphabet   Here s an example       final String alphabet    0123456789ABCDE       final int N   alphabet length         Random r   new Random         for  int i   0  i  lt  50  i              System out print alphabet charAt r nextInt N

User · Answer

Why reinvent the wheel  RandomStringUtils from Apache Commons has functions to which you can specify the character set from which characters are generated  You can take what you need to your app   http   kickjava com src org apache commons lang RandomStringUtils java htm

User · Answer

Using some simple command line  bash scripting      cat  dev urandom   tr -cd  a-z0-9     -    head -c 30   xargs t315 qeqaszwz6kxv 761rf cj 7gc    cat  dev urandom   tr -cd  a-z0-9     -    head -c 1   xargs f    cat  dev urandom  get a random stream of char from the kernel tr  keep only char char we want head  take only the first n chars xargs  just for adding a   n  char

User · Answer

Random random   new Random    int n   random nextInt 69    32  if  n  gt  96        n    26    char c    char  n    I guess it depends which punctuation you want to include  but this should generate a random character including all of the punctuation on this ASCII table  Basically  I ve generated a random int from 32 - 96 or 123 - 126  which I have then casted to a char  which gives the ASCII equivalent of that number  Also  make sure youimport java util Random

User · Answer

Here is code for secure  easy  but a little bit more expensive session identifiers   import java security SecureRandom  import java math BigInteger   public final class SessionIdentifierGenerator      private SecureRandom random   new SecureRandom       public String nextSessionId           return new BigInteger 130  random  toString 32

[java] Random character generator with a range of (A..Z, 0..9) and punctuation

Examples related to java

Examples related to android

Examples related to random