Calculating Time Difference

Question

at the start and end of my program  I have   from time import strftime print int strftime   Y- m- d  H  M  S      Y1 int strftime   Y    m1 int strftime   m    d1 int strftime   d    H1 int strftime   H    M1 int strftime   M    S1 int strftime   S      Y2 int strftime   Y    m2 int strftime   m    d2 int strftime   d    H2 int strftime   H    M2 int strftime   M    S2 int strftime   S     print  Difference is   str Y2-Y1      str m2-m1      str d2-d1                  str H2-H1      str M2-M1      str S2-S1    But when I tried to get the difference  I get syntax errors     I am doing a few things wrong  but I m not sure what is going on     Basically  I just want to store a time in a variable at the start of my program  then store a 2nd time in a second variable near the end  then at the last bit of the program  compute the difference and display it  I am not trying to time a function speed  I am trying to log how long it took for a user to progress through some menus  What is the best way to do this

User · Answer

from time import time  start time   time        end time   time   seconds elapsed   end time - start time  hours  rest   divmod seconds elapsed  3600  minutes  seconds   divmod rest  60

User · Answer

Here is a piece of code to do so  def StringChallenge str1     str1   str1 1 -1  h1   0 h2   0 m1   0 m2   0  def time dif h1 m1 h2 m2       if h1    h2           return m2-m1     else          return   h2-h1-1  60    60-m1    m2  count min   0  if str1 1              h1 int str1  1       m1 int str1 2 4   else      h1 int str1  2       m1 int str1 3 5    if str1 -7      -       h2 int str1 -6       m2 int str1 -4 -2   else      h2 int str1 -7 -5       m2 int str1 -4 -2    if h1    12      h1   0 if h2    12      h2   0  if  quot am quot  in str1  8       flag1   0 else      flag1  1  if  quot am quot  in str1 7        flag2   0 else      flag2   1  if flag1    flag2      if h2  gt  h1 or  h2    h1 and m2  gt   m1           count min    time dif h1 m1 h2 m2      else          count min    1440 - time dif h2 m2 h1 m1  else      count min     12-h1-1  60     count min     60 - m1      count min     h2 60  m2   return count min

User · Answer

time monotonic    basically your computer s uptime in seconds  is guarranteed to not misbehave when your computer s clock is adjusted  such as when transitioning to from daylight saving time     gt  gt  gt  import time  gt  gt  gt   gt  gt  gt  time monotonic   452782 067158593  gt  gt  gt   gt  gt  gt  a   time monotonic    gt  gt  gt  time sleep 1   gt  gt  gt  b   time monotonic    gt  gt  gt  print b-a  1 001658110995777

User · Answer

The datetime module will do all the work for you    gt  gt  gt  import datetime  gt  gt  gt  a   datetime datetime now    gt  gt  gt       wait a while     gt  gt  gt  b   datetime datetime now    gt  gt  gt  print b-a  0 03 43 984000   If you don t want to display the microseconds  just use  as gnibbler suggested     gt  gt  gt  a   datetime datetime now   replace microsecond 0   gt  gt  gt  b   datetime datetime now   replace microsecond 0   gt  gt  gt  print b-a  0 03 43

User · Answer

You cannot calculate the differences separately     what difference would that yield for 7 59 and 8 00 o clock  Try  import time time time     which gives you the seconds since the start of the epoch    You can then get the intermediate time with something like  timestamp1   time time     Your code here timestamp2   time time   print  This took   2f seconds     timestamp2 - timestamp1

[python] Calculating Time Difference

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