Remove all occurrences of char from string

Question

I can use this   String str    TextX Xto modifyX   str   str replace  X        that does not work because there is no such character      Is there a way to remove all occurrences of character X from a String in Java   I tried this and is not what I want  str replace  X          replace with space

User · Answer

another lambda copying a new string from the original  but leaving out the character that is to delete String text    quot removing a special character from a string quot    int delete    e   int   arr   text codePoints   filter  c - gt  c    delete   toArray     String rslt   new String  arr  0  arr length     gives  rmoving a spcial charactr from a string

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You will need to put the characters needs to be removed inside the square brackets during the time of replacement  The example code will be as following    String s     116 42  replaceAll

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here is a lambda function which removes all characters passed as string  BiFunction lt String String String gt  deleteChars    fromString  chars  - gt      StringBuilder buf   new StringBuilder  fromString      IntStream range  0  buf length     forEach  i - gt        while  i  lt  buf length    amp  amp  chars indexOf  buf charAt  i      gt   0         buf deleteCharAt  i             return  buf toString           String str    TextX XYto modifyZ   deleteChars apply  str   XYZ             gt   Text to modify   This solution takes into acount that the resulting String     in difference to replace       never becomes larger than the starting String when removing characters  So it avoids the repeated allocating and copying while appending character-wise to the StringBuilder as replace   does  Not to mention the pointless generation of Pattern and Matcher instances in replace   that are never needed for removal  In difference to replace   this solution can delete several characters in one swoop

User · Answer

Try using the overload that takes CharSequence arguments  eg  String  rather than char   str   str replace  X

User · Answer

Hello Try this code below  public class RemoveCharacter        public static void main String   args           String str    MXy nameX iXs farXazX           char x    X           System out println removeChr str x               public static String removeChr String str  char x           StringBuilder strBuilder   new StringBuilder            char   rmString   str toCharArray            for int i 0  i lt rmString length  i                 if rmString i     x                  else                   strBuilder append rmString i                                    return strBuilder toString

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Using  public String replaceAll String regex  String replacement    will work    Usage would be str replace  X          Executing    Xlakjsdf Xxx  replaceAll  X          returns   lakjsdf xx

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package com acn demo action   public class RemoveCharFromString        static String input           public static void main String   args            input    abadbbeb34erterb           char token    b           removeChar token              private static void removeChar char token               TODO Auto-generated method stub         System out println input           for  int i 0 i lt input length   i                  if  input charAt i     token                input   input replace input charAt i                         System out println  MATCH FOUND                              input   input replaceAll                       System out println input

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You can use str   str replace  X        as mentioned before and you will be fine  For your information    is not an empty  or a valid  character but   0  is    So you could use str   str replace  X     0    instead

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String test    09-09-2012   String arr      test split  -    String ans        for String t   arr      ans  t    This is the example for where I have removed the character - from the String

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Use replaceAll instead of replace  str   str replaceAll  X        This should give you the desired answer

User · Answer

If you want to do something with Java Strings  Commons Lang StringUtils is a great place to look   StringUtils remove  TextX Xto modifyX    X

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Evaluation of main answers with a performance benchmark which confirms concerns that the current chosen answer makes costly regex operations under the hood  To date the provided answers come in 3 main styles  ignoring the JavaScript answer         Use String replace charsToDelete       which uses regex under the hood Use Lambda Use simple Java implementation   In terms of code size clearly the String replace is the most terse  The simple Java implementation is slightly smaller and cleaner  IMHO  than the Lambda  don t get me wrong - I use Lambdas often where they are appropriate   Execution speed was  in order of fastest to slowest  simple Java implementation  Lambda and then String replace    that invokes regex    By far the fastest implementation was the simple Java implementation tuned so that it preallocates the StringBuilder buffer to the max possible result length and then simply appends chars to the buffer that are not in the  chars to delete  string  This avoids any reallocates that would occur for Strings   16 chars in length  the default allocation for StringBuilder  and it avoids the  slide left  performance hit of deleting characters from a copy of the string that occurs is the Lambda implementation   The code below runs a simple benchmark test  running each implementation 1 000 000 times and logs the elapsed time   The exact results vary with each run but the order of performance never changes   Start simple Java implementation Time  157 ms Start Lambda implementation Time  253 ms Start String replace implementation Time  634 ms   The Lambda implementation  as copied from Kaplan s answer  may be slower because it performs a  shift left by one  of all characters to the right of the character being deleted  This would obviously get worse for longer strings with lots of characters requiring deletion  Also there might be some overhead in the Lambda implementation itself   The String replace implementation  uses regex and does a regex  compile  at each call  An optimization of this would be to use regex directly and cache the compiled pattern to avoid the cost of compiling it each time   package com sample   import java util function BiFunction  import java util stream IntStream   public class Main        static public String deleteCharsSimple String fromString  String charsToDelete                StringBuilder buf   new StringBuilder fromString length        Preallocate to max possible result length         for int i   0  i  lt  fromString length    i                if  charsToDelete indexOf fromString charAt i    lt  0                  buf append fromString charAt i         char not in chars to delete so add it         return buf toString               static public String deleteCharsLambda String fromString1  String charsToDelete                BiFunction lt String  String  String gt  deleteChars    fromString  chars  - gt                StringBuilder buf   new StringBuilder fromString               IntStream range 0  buf length    forEach i - gt                    while  i  lt  buf length    amp  amp  chars indexOf buf charAt i    gt   0                      buf deleteCharAt i                               return  buf toString                         return deleteChars apply fromString1  charsToDelete              static public String deleteCharsReplace String fromString  String charsToDelete                return fromString replace charsToDelete                   public static void main String   args                String str    XXXTextX XXto modifyX           String charsToDelete    X       Should only be one char as per OP s requirement          long start  end           System out println  Start simple            start   System currentTimeMillis             for  int i   0  i  lt  1000000  i                deleteCharsSimple str  charsToDelete            end   System currentTimeMillis            System out println  Time       end - start             System out println  Start lambda            start   System currentTimeMillis            for  int i   0  i  lt  1000000  i                deleteCharsLambda str  charsToDelete            end   System currentTimeMillis            System out println  Time       end - start             System out println  Start replace            start   System currentTimeMillis             for  int i   0  i  lt  1000000  i                deleteCharsReplace str  charsToDelete            end   System currentTimeMillis            System out println  Time       end - start

User · Answer

I like using RegEx in this occasion   str   str replace  X g         where g means global so it will go through your whole string and replace all X with     if you want to replace both X and x  you simply say   str   str replace  X x g          see my fiddle here  fiddle

[java] Remove all occurrences of char from string

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