Arrow functions in ES2015 provide a more concise syntax.
Examples:
Constructor function
function User(name) {
this.name = name;
}
// vs
const User = name => {
this.name = name;
};
Prototype methods
User.prototype.getName = function() {
return this.name;
};
// vs
User.prototype.getName = () => this.name;
Object (literal) methods
const obj = {
getName: function() {
// ...
}
};
// vs
const obj = {
getName: () => {
// ...
}
};
Callbacks
setTimeout(function() {
// ...
}, 500);
// vs
setTimeout(() => {
// ...
}, 500);
Variadic functions
function sum() {
let args = [].slice.call(arguments);
// ...
}
// vs
const sum = (...args) => {
// ...
};
This question is related to
javascript
ecmascript-6
arrow-functions
tl;dr: No! Arrow functions and function declarations / expressions are not equivalent and cannot be replaced blindly.
If the function you want to replace does not use this, arguments and is not called with new, then yes.
As so often: it depends. Arrow functions have different behavior than function declarations / expressions, so let's have a look at the differences first:
1. Lexical this and arguments
Arrow functions don't have their own this or arguments binding. Instead, those identifiers are resolved in the lexical scope like any other variable. That means that inside an arrow function, this and arguments refer to the values of this and arguments in the environment the arrow function is defined in (i.e. "outside" the arrow function):
// Example using a function expression
function createObject() {
console.log('Inside `createObject`:', this.foo);
return {
foo: 42,
bar: function() {
console.log('Inside `bar`:', this.foo);
},
};
}
createObject.call({foo: 21}).bar(); // override `this` inside createObject// Example using a arrow function
function createObject() {
console.log('Inside `createObject`:', this.foo);
return {
foo: 42,
bar: () => console.log('Inside `bar`:', this.foo),
};
}
createObject.call({foo: 21}).bar(); // override `this` inside createObjectIn the function expression case, this refers to the object that was created inside the createObject. In the arrow function case, this refers to this of createObject itself.
This makes arrow functions useful if you need to access the this of the current environment:
// currently common pattern
var that = this;
getData(function(data) {
that.data = data;
});
// better alternative with arrow functions
getData(data => {
this.data = data;
});
Note that this also means that is not possible to set an arrow function's this with .bind or .call.
If you are not very familiar with this, consider reading
2. Arrow functions cannot be called with new
ES2015 distinguishes between functions that are callable and functions that are constructable. If a function is constructable, it can be called with new, i.e. new User(). If a function is callable, it can be called without new (i.e. normal function call).
Functions created through function declarations / expressions are both constructable and callable.
Arrow functions (and methods) are only callable.
class constructors are only constructable.
If you are trying to call a non-callable function or to construct a non-constructable function, you will get a runtime error.
Knowing this, we can state the following.
Replaceable:
this or arguments..bind(this)Not replaceable:
this)arguments (see below))Lets have a closer look at this using your examples:
Constructor function
This won't work because arrow functions cannot be called with new. Keep using a function declaration / expression or use class.
Prototype methods
Most likely not, because prototype methods usually use this to access the instance. If they don't use this, then you can replace it. However, if you primarily care for concise syntax, use class with its concise method syntax:
class User {
constructor(name) {
this.name = name;
}
getName() {
return this.name;
}
}
Object methods
Similarly for methods in an object literal. If the method wants to reference the object itself via this, keep using function expressions, or use the new method syntax:
const obj = {
getName() {
// ...
},
};
Callbacks
It depends. You should definitely replace it if you are aliasing the outer this or are using .bind(this):
// old
setTimeout(function() {
// ...
}.bind(this), 500);
// new
setTimeout(() => {
// ...
}, 500);
But: If the code which calls the callback explicitly sets this to a specific value, as is often the case with event handlers, especially with jQuery, and the callback uses this (or arguments), you cannot use an arrow function!
Variadic functions
Since arrow functions don't have their own arguments, you cannot simply replace them with an arrow function. However, ES2015 introduces an alternative to using arguments: the rest parameter.
// old
function sum() {
let args = [].slice.call(arguments);
// ...
}
// new
const sum = (...args) => {
// ...
};
Related question:
Further resources:
Arrow functions => best ES6 feature so far. They are a tremendously powerful addition to ES6, that I use constantly.
Wait, you can't use arrow function everywhere in your code, its not going to work in all cases like this where arrow functions are not usable. Without a doubt, the arrow function is a great addition it brings code simplicity.
But you can’t use an arrow function when a dynamic context is required: defining methods, create objects with constructors, get the target from this when handling events.
They do not have this
It uses “lexical scoping” to figure out what the value of “this”
should be. In simple word lexical scoping it uses “this” from the
inside the function’s body.
They do not have arguments
Arrow functions don’t have an arguments object. But the same
functionality can be achieved using rest parameters.
let sum = (...args) => args.reduce((x, y) => x + y, 0)
sum(3, 3, 1) // output - 7
`
They cannot be used with new
Arrow functions can't be construtors because they do not have a prototype property.
map, reduce, or forEach.To use arrow functions with function.prototype.call, I made a helper function on the object prototype:
// Using
// @func = function() {use this here} or This => {use This here}
using(func) {
return func.call(this, this);
}
usage
var obj = {f:3, a:2}
.using(This => This.f + This.a) // 5
Edit
You don't NEED a helper. You could do:
var obj = {f:3, a:2}
(This => This.f + This.a).call(undefined, obj); // 5
Source: Stackoverflow.com