Possible Duplicate:
How to split a string?
What is the right way to split a string into a vector of strings. Delimiter is space or comma.
std::vector<std::string> split(std::string text, char delim) {
std::string line;
std::vector<std::string> vec;
std::stringstream ss(text);
while(std::getline(ss, line, delim)) {
vec.push_back(line);
}
return vec;
}
split("String will be split", ' ')
-> {"String", "will", "be", "split"}
split("Hello, how are you?", ',')
-> {"Hello", "how are you?"}
EDIT: Here's a thing I made, this can use multi-char delimiters, albeit I'm not 100% sure if it always works:
std::vector<std::string> split(std::string text, std::string delim) {
std::vector<std::string> vec;
size_t pos = 0, prevPos = 0;
while (1) {
pos = text.find(delim, prevPos);
if (pos == std::string::npos) {
vec.push_back(text.substr(prevPos));
return vec;
}
vec.push_back(text.substr(prevPos, pos - prevPos));
prevPos = pos + delim.length();
}
}
You can use getline with delimiter:
string s, tmp;
stringstream ss(s);
vector<string> words;
while(getline(ss, tmp, ',')){
words.push_back(tmp);
.....
}
Tweaked version from Techie Delight:
#include <string>
#include <vector>
std::vector<std::string> split(const std::string& str, char delim) {
std::vector<std::string> strings;
size_t start;
size_t end = 0;
while ((start = str.find_first_not_of(delim, end)) != std::string::npos) {
end = str.find(delim, start);
strings.push_back(str.substr(start, end - start));
}
return strings;
}
If the string has both spaces and commas you can use the string class function
found_index = myString.find_first_of(delims_str, begin_index)
in a loop. Checking for != npos and inserting into a vector. If you prefer old school you can also use C's
strtok()
method.
vector<string> split(string str, string token){
vector<string>result;
while(str.size()){
int index = str.find(token);
if(index!=string::npos){
result.push_back(str.substr(0,index));
str = str.substr(index+token.size());
if(str.size()==0)result.push_back(str);
}else{
result.push_back(str);
str = "";
}
}
return result;
}
split("1,2,3",",") ==> ["1","2","3"]
split("1,2,",",") ==> ["1","2",""]
split("1token2token3","token") ==> ["1","2","3"]
I write this custom function this will help you. But make discussions about the Time complexity.
std::vector<std::string> words;
std::string s;
std::string separator = ",";
while(s.find(separator) != std::string::npos){
separatorIndex = s.find(separator)
vtags.push_back(s.substr(0, separatorIndex ));
words= s.substr(separatorIndex + 1, s.length());
}
words.push_back(s);
i made this custom function that will convert the line to vector
#include <iostream>
#include <vector>
#include <ctime>
#include <string>
using namespace std;
int main(){
string line;
getline(cin, line);
int len = line.length();
vector<string> subArray;
for (int j = 0, k = 0; j < len; j++) {
if (line[j] == ' ') {
string ch = line.substr(k, j - k);
k = j+1;
subArray.push_back(ch);
}
if (j == len - 1) {
string ch = line.substr(k, j - k+1);
subArray.push_back(ch);
}
}
return 0;
}
A convenient way would be boost's string algorithms library.
#include <boost/algorithm/string/classification.hpp> // Include boost::for is_any_of
#include <boost/algorithm/string/split.hpp> // Include for boost::split
// ...
std::vector<std::string> words;
std::string s;
boost::split(words, s, boost::is_any_of(", "), boost::token_compress_on);
Source: Stackoverflow.com