I have a list that looks like:
[('A', 1), ('B', 2), ('C', 3)]
I want to turn it into a dictionary that looks like:
{'A': 1, 'B': 2, 'C': 3}
What's the best way to go about this?
EDIT: My list of tuples is actually more like:
[(A, 12937012397), (BERA, 2034927830), (CE, 2349057340)]
This question is related to
python
list
dictionary
>>> dict([('A', 1), ('B', 2), ('C', 3)])
{'A': 1, 'C': 3, 'B': 2}
l=[['A', 1], ['B', 2], ['C', 3]]
d={}
for i,j in l:
d.setdefault(i,j)
print(d)
Here is a way to handle duplicate tuple "keys":
# An example
l = [('A', 1), ('B', 2), ('C', 3), ('A', 5), ('D', 0), ('D', 9)]
# A solution
d = dict()
[d [t [0]].append(t [1]) if t [0] in list(d.keys())
else d.update({t [0]: [t [1]]}) for t in l]
d
OUTPUT: {'A': [1, 5], 'B': [2], 'C': [3], 'D': [0, 9]}
If Tuple has no key repetitions, it's Simple.
tup = [("A",0),("B",3),("C",5)]
dic = dict(tup)
print(dic)
If tuple has key repetitions.
tup = [("A",0),("B",3),("C",5),("A",9),("B",4)]
dic = {}
for i, j in tup:
dic.setdefault(i,[]).append(j)
print(dic)
Another way using dictionary comprehensions,
>>> t = [('A', 1), ('B', 2), ('C', 3)]
>>> d = { i:j for i,j in t }
>>> d
{'A': 1, 'B': 2, 'C': 3}
Have you tried this?
>>> l=[('A',1), ('B',2), ('C',3)]
>>> d=dict(l)
>>> d
{'A': 1, 'C': 3, 'B': 2}
Source: Stackoverflow.com