How do I print a double value without scientific notation using Java

Question

I want to print a double value in Java without exponential form   double dexp   12345678  System out println  dexp    dexp     It shows this E notation  1 2345678E7   I want it to print it like this  12345678  What is the best way to prevent this

User · Answer

This will work as long as your number is a whole number:

double dnexp = 12345678;
System.out.println("dexp: " + (long)dexp);

If the double variable has precision after the decimal point it will truncate it.

User · Answer

My solution  String str   String format     0f   yourDouble

User · Answer

I ve got another solution involving BigDecimal s toPlainString    but this time using the String-constructor  which is recommended in the javadoc      this constructor is compatible with the values returned by Float toString and Double toString  This is generally the preferred way to convert a float or double into a BigDecimal  as it doesn t suffer from the unpredictability of the BigDecimal double  constructor    It looks like this in its shortest form   return new BigDecimal myDouble toString    stripTrailingZeros   toPlainString      Pre Java 8  this results in  0 0  for any zero-valued Doubles  so you would need to add   if  myDouble doubleValue      0      return  0     NaN and infinite values have to be checked extra   The final result of all these considerations   public static String doubleToString Double d        if  d    null          return null      if  d isNaN      d isInfinite            return d toString            Pre Java 8  a value of 0 would yield  0 0  below     if  d doubleValue      0          return  0       return new BigDecimal d toString    stripTrailingZeros   toPlainString        This can also be copied pasted to work nicely with Float

User · Answer

use String format   quot   0f quot   number     0f for zero decimal  String numSring   String format   quot   0f quot   firstNumber   System out println numString

User · Answer

I think everyone had the right idea  but all answers were not straightforward   I can see this being a very useful piece of code   Here is a snippet of what will work   System out println String format    8f   EnterYourDoubleVariableHere      the   8  is where you set the number of decimal places you would like to show   I am using Eclipse and it worked no problem   Hope this was helpful  I would appreciate any feedback

User · Answer

The following code detects if the provided number is presented in scientific notation  If so it is represented in normal presentation with a maximum of  25  digits    static String convertFromScientificNotation double number           Check if in scientific notation     if  String valueOf number  toLowerCase   contains  e              System out println  The scientific notation number                     number                      detected  it will be converted to normal representation with 25 maximum fraction digits             NumberFormat formatter   new DecimalFormat            formatter setMaximumFractionDigits 25           return formatter format number         else         return String valueOf number

User · Answer

For integer values represented by a double  you can use this code  which is much faster than the other solutions  public static String doubleToString final double d           check for integer  also see https   stackoverflow com a 9898613 868941 and        https   github com google guava blob master guava src com google common math DoubleMath java     if  isMathematicalInteger d             return Long toString  long d         else              or use any of the solutions provided by others  this is the best         DecimalFormat df                new DecimalFormat  quot 0 quot   DecimalFormatSymbols getInstance Locale ENGLISH            df setMaximumFractionDigits 340      340   DecimalFormat DOUBLE FRACTION DIGITS         return df format d               Java 8  public static boolean isMathematicalInteger final double d        return StrictMath rint d     d  amp  amp  Double isFinite d

User · Answer

You could use printf   with  f  double dexp   12345678  System out printf  quot dexp   f n quot   dexp    This will print dexp  12345678 000000  If you don t want the fractional part  use System out printf  quot dexp    0f n quot   dexp    0 in   0f means 0 places in fractional part i e no fractional part  If you want to print fractional part with desired number of decimal places then instead of 0 just provide the number like this   8f  By default fractional part is printed up to 6 decimal places  This uses the format specifier language explained in the documentation  The default toString   format used in your original code is spelled out here

User · Answer

You can try it with DecimalFormat  With this class you are very flexible in parsing your numbers  You can exactly set the pattern you want to use  In your case for example   double test   12345678  DecimalFormat df   new DecimalFormat       df setMaximumFractionDigits 0   System out println df format test      12345678

User · Answer

I had this same problem in my production code when I was using it as a string input to a math Eval   function which takes a string like   x   20   50   I looked at hundreds of articles    In the end I went with this because of the speed  And because the Eval function was going to convert it back into its own number format eventually and math Eval   didn t support the trailing E-07 that other methods returned  and anything over 5 nbsp dp was too much detail for my application anyway   This is now used in production code for an application that has 1 000  users     double value   0 0002111d  String s   Double toString   int  value   100000 0d   100000 0d      Round to 5 dp  s display as   0 00021

User · Answer

In short   If you want to get rid of trailing zeros and Locale problems  then you should use   double myValue   0 00000021d   DecimalFormat df   new DecimalFormat  0   DecimalFormatSymbols getInstance Locale ENGLISH    df setMaximumFractionDigits 340      340   DecimalFormat DOUBLE FRACTION DIGITS  System out println df format myValue       Output  0 00000021   Explanation   Why other answers did not suit me    Double toString   or System out println or FloatingDecimal toJavaFormatString uses scientific notations if double is less than 10 -3 or greater than or equal to 10 7 By using  f  the default decimal precision is 6  otherwise you can hardcode it  but it results in extra zeros added if you have fewer decimals  Example   double myValue   0 00000021d  String format    12f   myvalue      Output  0 000000210000  By using setMaximumFractionDigits 0   or   0f you remove any decimal precision  which is fine for integers longs  but not for double   double myValue   0 00000021d  System out println String format    0f   myvalue       Output  0 DecimalFormat df   new DecimalFormat  0    System out println df format myValue       Output  0  By using DecimalFormat  you are local dependent  In French locale  the decimal separator is a comma  not a point   double myValue   0 00000021d  DecimalFormat df   new DecimalFormat  0    df setMaximumFractionDigits 340   System out println df format myvalue       Output  0 00000021   Using the ENGLISH locale makes sure you get a point for decimal separator  wherever your program will run    Why using 340 then for setMaximumFractionDigits   Two reasons    setMaximumFractionDigits accepts an integer  but its implementation has a maximum digits allowed of DecimalFormat DOUBLE FRACTION DIGITS which equals 340 Double MIN VALUE   4 9E-324 so with 340 digits you are sure not to round your double and lose precision

User · Answer

This may be a tangent     but if you need to put a numerical value as an integer  that is too big to be an integer  into a serializer  JSON  etc   then you probably want  quot BigInterger quot  Example  value is a string - 7515904334 We need to represent it as a numerical in a Json message         quot contact phone quot   quot 800220-3333 quot        quot servicer id quot  7515904334       quot servicer name quot   quot SOME CORPORATION quot     We can t print it or we ll get this         quot contact phone quot   quot 800220-3333 quot        quot servicer id quot   quot 7515904334 quot        quot servicer name quot   quot SOME CORPORATION quot     Adding the value to the node like this produces the desired outcome  BigInteger valueOf Long parseLong value  10    I m not sure this is really on-topic  but since this question was my top hit when I searched for my solution  I thought I would share here for the benefit of others  lie me  who search poorly   D

User · Answer

Java prevent E notation in a double   Five different ways to convert a double to a normal number   import java math BigDecimal  import java text DecimalFormat   public class Runner       public static void main String   args            double myvalue   0 00000021d             Option 1 Print bare double          System out println myvalue              Option2  use decimalFormat          DecimalFormat df   new DecimalFormat               df setMaximumFractionDigits 8           System out println df format myvalue               Option 3  use printf          System out printf    9f   myvalue           System out println               Option 4  convert toBigDecimal and ask for toPlainString            System out print new BigDecimal myvalue  toPlainString             System out println               Option 5  String format          System out println String format    12f   myvalue              This program prints   2 1E-7  00000021 0 000000210 0 000000210000000000000001085015324114868562332958390470594167709350585 0 000000210000   Which are all the same value   Protip  If you are confused as to why those random digits appear beyond a certain threshold in the double value  this video explains  computerphile why does 0 1 0 2 equal 0 30000000000001   http   youtube com watch v PZRI1IfStY0

User · Answer

I needed to convert some double to currency values and found that most of the solutions were OK  but not for me   The DecimalFormat was eventually the way for me  so here is what I ve done      public String foo double value    Got here 6 743240136E7 or something                 DecimalFormat formatter           if value -  int value  gt  0 0              formatter   new DecimalFormat  0 00       Here you can also deal with rounding if you wish           else             formatter   new DecimalFormat  0             return formatter format value           As you can see  if the number is natural I get - say - 20000000 instead of 2E7  etc   - without any decimal point   And if it s decimal  I get only two decimal digits

User · Answer

Java Kotlin compiler converts any value greater than 9999999  greater than or equal to 10 million  to scientific notation ie  Epsilion notation    Ex  12345678 is converted to 1 2345678E7  Use this code to avoid automatic conversion to scientific notation   fun setTotalSalesValue String total            var valueWithoutEpsilon   total toBigDecimal              Set the converted value to your android text view using setText   function            salesTextView setText  valueWithoutEpsilon toPlainString

[java] How do I print a double value without scientific notation using Java?

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