swift How to remove optional String Character

Question

How do I remove Optional Character    let color   colorChoiceSegmentedControl titleForSegmentAtIndex colorChoiceSegmentedControl selectedSegmentIndex   println color     Optional  Red    let imageURLString    http   hahaha com ha php color   color   println imageURLString    http   hahaha com ha php color Optional  Red       I just want output  http   hahaha com ha php color Red   How can I do   hmm

User · Answer

print  imageURLString       imageURLString    just use

User · Answer

Hello i have got the same issue i was getting Optional 3  So  i have tried this below code cell lbl Quantity text     quot  data  quantity   quot     quot Optional 3  quot  let quantity   data  quantity cell lbl Quantity text    quot  quantity   quot     quot 3 quot

User · Answer

You need to unwrap the optional before you try to use it via string interpolation  The safest way to do that is via optional binding   if let color   colorChoiceSegmentedControl titleForSegmentAtIndex colorChoiceSegmentedControl selectedSegmentIndex        println color      Red       let imageURLString    http   hahaha com ha php color   color       println imageURLString     http   hahaha com ha php color Red

User · Answer

Actually when you define any variable as a optional then you need to unwrap that optional value  To fix this problem either you have to declare variable as non option or put   exclamation  mark behind the variable to unwrap the option value    var temp   String     This is an optional  temp    I am a programer                  print temp     Optional  I am a programer    var temp1   String     This is not optional  temp1    I am a programer  print temp1      I am a programer

User · Answer

Check for nil and unwrap using       let color   colorChoiceSegmentedControl titleForSegmentAtIndex colorChoiceSegmentedControl selectedSegmentIndex   println color     Optional  Red    if color    nil       println color       Red      let imageURLString    http   hahaha com ha php color   color        println imageURLString         http   hahaha com ha php color Red

User · Answer

import UIKit  let characters     quot A quot    quot B quot    quot C quot    quot D quot    quot E quot    quot F quot    quot G quot    quot H quot    quot I quot    quot J quot    quot K quot    quot L quot    quot M quot    quot N quot    quot O quot    quot P quot    quot Q quot    quot R quot    quot S quot    quot T quot    quot U quot    quot V quot    quot W quot    quot X quot    quot Y quot    quot Z quot    var a  String   characters randomElement    var b  String   characters randomElement    var c  String   characters randomElement    var d  String   characters randomElement    var e  String   characters randomElement    var f  String   characters randomElement    var password     quot   a  quot     quot   b  quot     quot   c  quot     quot   d  quot     quot   e  quot     quot   f  quot        print   password

User · Answer

I looked over this again and i m simplifying my answer  I think most the answers here are missing the point  You usually want to print whether or not your variable has a value and you also want your program not to crash if it doesn t  so don t use     Here just do this      print  color    color            This will give you blank or the value

User · Answer

Besides the solutions mentioned in other answers  if you want to always avoid that Optional text for your whole project  you can add this pod   pod  NoOptionalInterpolation     https   github com T-Pham NoOptionalInterpolation   The pod adds an extension to override the string interpolation init method to get rid of the Optional text once for all  It also provides a custom operator   to bring the default behaviour back   So   import NoOptionalInterpolation let a  String     string     a       string    a       Optional  string     Please see this answer https   stackoverflow com a 37481627 6390582 for more details

User · Answer

Simple convert   to   fixed my issue   usernameLabel text      userInfo  userName     To   usernameLabel text      userInfo  userName

User · Answer

Try this   var check String   optional String  print check     optional string  This will result in nil while unwrapping an optional value if value is not initialized or if initialized to nil  print check    Optional  optional string     nil values are handled in this statement   Go with first if you are confident to have no nil in your variable  Also  you can use if let or Guard let statement to unwrap optionals without any crash    if let unwrapperStr   check        print unwrapperStr    optional String      Guard let    guard let gUnwrap   check else          handle failed unwrap case here     print gUnwrap    optional String

User · Answer

Although we might have different contexts  the below worked for me   I wrapped every part of my variable in brackets and then added an exclamation mark outside the right closing bracket   For example  print documentData  mileage    is changed to   print  documentData  mileage

User · Answer

when you define any variable as a optional then you need to unwrap that optional value Convert   to

User · Answer

In swift3 you can easily remove optional   if let value   optionalvariable     in value you will get non optional value

User · Answer

You can just put   and it will work   print var1     optional  something    print var1       something

[string] swift How to remove optional String Character

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