How do I convert a decimal to an int in C

Question

How do I convert a decimal to an int

User · Answer

A neat trick for fast rounding is to add .5 before you cast your decimal to an int.

decimal d = 10.1m;
d += .5m;
int i = (int)d;

Still leaves i=10, but

decimal d = 10.5m;
d += .5m;
int i = (int)d;

Would round up so that i=11.

User · Answer

System Decimal implements the IConvertable interface  which has a ToInt32   member    Does calling System Decimal ToInt32   work for you

User · Answer

decimal d   2  int i    int  d    This should work just fine

User · Answer

I prefer using Math Round  Math Floor  Math Ceiling or Math Truncate to explicitly set the rounding mode as appropriate    Note that they all return Decimal as well - since Decimal has a larger range of values than an Int32  so you ll still need to cast  and check for overflow underflow     checked      int i    int Math Floor d

User · Answer

Use Convert ToInt32 from mscorlib as in  decimal value   3 14m  int n   Convert ToInt32 value     See MSDN  You can also use Decimal ToInt32  Again  see MSDN  Finally  you can do a direct cast as in  decimal value   3 14m  int n    int  value    which uses the explicit cast operator  See MSDN

User · Answer

You can t   Well  of course you could  however an int  System Int32  is not big enough to hold every possible decimal value     That means if you cast a decimal that s larger than int MaxValue you will overflow  and if the decimal is smaller than int MinValue  it will underflow     What happens when you under overflow   One of two things   If your build is unchecked  i e   the CLR doesn t care if you do   your application will continue after the value over underflows  but the value in the int will not be what you expected   This can lead to intermittent bugs and may be hard to fix   You ll end up your application in an unknown state which may result in your application corrupting whatever important data its working on   Not good   If your assembly is checked  properties- build- advanced- check for arithmetic overflow underflow or the  checked compiler option   your code will throw an exception when an under overflow occurs   This is probably better than not  however the default for assemblies is not to check for over underflow   The real question is  what are you trying to do    Without knowing your requirements  nobody can tell you what you should do in this case  other than the obvious   DON T DO IT     If you specifically do NOT care  the answers here are valid   However  you should communicate your understanding that an overflow may occur and that it doesn t matter by wrapping your cast code in an unchecked block  unchecked        do your conversions that may underflow overflow here     That way people coming behind you understand you don t care  and if in the future someone changes your builds to  checked  your code won t break unexpectedly   If all you want to do is drop the fractional portion of the number  leaving the integral part  you can use Math Truncate   decimal actual   10 5M  decimal expected   10M  Assert AreEqual expected  Math Truncate actual

User · Answer

I find that the casting operator does not work if you have a boxed decimal  i e  a decimal value inside an object type    Convert ToInt32 decimal as object  works fine in this case   This situation comes up when retrieving IDENTITY AUTONUMBER values from the database   SqlCommand foo   new SqlCommand  INSERT INTO     SELECT SCOPE IDENTITY     conn   int ID   Convert ToInt32 foo ExecuteScalar         works int ID    int foo ExecuteScalar                    throws InvalidCastException   See 4 3 2 Unboxing conversions

User · Answer

No answer seems to deal with the OverflowException UnderflowException that comes from trying to convert a decimal that is outside the range of int   int intValue    int Math Max int MinValue  Math Min int MaxValue  decimalValue      This solution will return the maximum or minimum int value possible if the decimal value is outside the int range  You might want to add some rounding with Math Round  Math Ceiling or Math Floor for when the value is inside the int range

User · Answer

I prefer using Math Round  Math Floor  Math Ceiling or Math Truncate to explicitly set the rounding mode as appropriate    Note that they all return Decimal as well - since Decimal has a larger range of values than an Int32  so you ll still need to cast  and check for overflow underflow     checked      int i    int Math Floor d

User · Answer

decimal d   5 5   int i   decimal ToInt32 d     you will get i   5   ref  link text

User · Answer

You can t   Well  of course you could  however an int  System Int32  is not big enough to hold every possible decimal value     That means if you cast a decimal that s larger than int MaxValue you will overflow  and if the decimal is smaller than int MinValue  it will underflow     What happens when you under overflow   One of two things   If your build is unchecked  i e   the CLR doesn t care if you do   your application will continue after the value over underflows  but the value in the int will not be what you expected   This can lead to intermittent bugs and may be hard to fix   You ll end up your application in an unknown state which may result in your application corrupting whatever important data its working on   Not good   If your assembly is checked  properties- build- advanced- check for arithmetic overflow underflow or the  checked compiler option   your code will throw an exception when an under overflow occurs   This is probably better than not  however the default for assemblies is not to check for over underflow   The real question is  what are you trying to do    Without knowing your requirements  nobody can tell you what you should do in this case  other than the obvious   DON T DO IT     If you specifically do NOT care  the answers here are valid   However  you should communicate your understanding that an overflow may occur and that it doesn t matter by wrapping your cast code in an unchecked block  unchecked        do your conversions that may underflow overflow here     That way people coming behind you understand you don t care  and if in the future someone changes your builds to  checked  your code won t break unexpectedly   If all you want to do is drop the fractional portion of the number  leaving the integral part  you can use Math Truncate   decimal actual   10 5M  decimal expected   10M  Assert AreEqual expected  Math Truncate actual

User · Answer

int i    int d    will give you the number rounded down   If you want to round to the nearest even number  i e    5 will round up  you can use  int i    int Math Round d  MidpointRounding ToEven     In general you can cast between all the numerical types in C   If there is no information that will be lost during the cast you can do it implicitly   int i   10  decimal d   i    though you can still do it explicitly if you wish   int i   10  decimal d    decimal i    However  if you are going to be losing information through the cast you must do it explicitly  to show you are aware you may be losing information    decimal d   10 5M  int i    int d    Here you are losing the   5   This may be fine  but you must be explicit about it and make an explicit cast to show you know you may be losing the information

User · Answer

decimal d   2  int i    int  d    This should work just fine

User · Answer

System Decimal implements the IConvertable interface  which has a ToInt32   member    Does calling System Decimal ToInt32   work for you

User · Answer

int i    int d    will give you the number rounded down   If you want to round to the nearest even number  i e    5 will round up  you can use  int i    int Math Round d  MidpointRounding ToEven     In general you can cast between all the numerical types in C   If there is no information that will be lost during the cast you can do it implicitly   int i   10  decimal d   i    though you can still do it explicitly if you wish   int i   10  decimal d    decimal i    However  if you are going to be losing information through the cast you must do it explicitly  to show you are aware you may be losing information    decimal d   10 5M  int i    int d    Here you are losing the   5   This may be fine  but you must be explicit about it and make an explicit cast to show you know you may be losing the information

User · Answer

System Decimal implements the IConvertable interface  which has a ToInt32   member    Does calling System Decimal ToInt32   work for you

User · Answer

decimal vIn   0 0M  int vOut   Convert ToInt32 vIn     Here is a very handy convert data type webpage for those of others  http   www convertdatatypes com Convert-decimal-to-int-in-CSharp html

User · Answer

I prefer using Math Round  Math Floor  Math Ceiling or Math Truncate to explicitly set the rounding mode as appropriate    Note that they all return Decimal as well - since Decimal has a larger range of values than an Int32  so you ll still need to cast  and check for overflow underflow     checked      int i    int Math Floor d

User · Answer

decimal vIn   0 0M  int vOut   Convert ToInt32 vIn     Here is a very handy convert data type webpage for those of others  http   www convertdatatypes com Convert-decimal-to-int-in-CSharp html

User · Answer

System Decimal implements the IConvertable interface  which has a ToInt32   member    Does calling System Decimal ToInt32   work for you

User · Answer

A neat trick for fast rounding is to add .5 before you cast your decimal to an int.

decimal d = 10.1m;
d += .5m;
int i = (int)d;

Still leaves i=10, but

decimal d = 10.5m;
d += .5m;
int i = (int)d;

Would round up so that i=11.

User · Answer

decimal d   5 5   int i   decimal ToInt32 d     you will get i   5   ref  link text

User · Answer

Rounding a decimal to the nearest integer  decimal a   int b    int  a   0 5m     when a   49 9  then b   50  when a   49 5  then b   50  when a   49 4  then b   49 etc

User · Answer

A neat trick for fast rounding is to add .5 before you cast your decimal to an int.

decimal d = 10.1m;
d += .5m;
int i = (int)d;

Still leaves i=10, but

decimal d = 10.5m;
d += .5m;
int i = (int)d;

Would round up so that i=11.

User · Answer

decimal d   2  int i    int  d    This should work just fine

User · Answer

decimal d   2  int i    int  d    This should work just fine

User · Answer

Rounding a decimal to the nearest integer  decimal a   int b    int  a   0 5m     when a   49 9  then b   50  when a   49 5  then b   50  when a   49 4  then b   49 etc

User · Answer

No answer seems to deal with the OverflowException UnderflowException that comes from trying to convert a decimal that is outside the range of int   int intValue    int Math Max int MinValue  Math Min int MaxValue  decimalValue      This solution will return the maximum or minimum int value possible if the decimal value is outside the int range  You might want to add some rounding with Math Round  Math Ceiling or Math Floor for when the value is inside the int range

User · Answer

You can t   Well  of course you could  however an int  System Int32  is not big enough to hold every possible decimal value     That means if you cast a decimal that s larger than int MaxValue you will overflow  and if the decimal is smaller than int MinValue  it will underflow     What happens when you under overflow   One of two things   If your build is unchecked  i e   the CLR doesn t care if you do   your application will continue after the value over underflows  but the value in the int will not be what you expected   This can lead to intermittent bugs and may be hard to fix   You ll end up your application in an unknown state which may result in your application corrupting whatever important data its working on   Not good   If your assembly is checked  properties- build- advanced- check for arithmetic overflow underflow or the  checked compiler option   your code will throw an exception when an under overflow occurs   This is probably better than not  however the default for assemblies is not to check for over underflow   The real question is  what are you trying to do    Without knowing your requirements  nobody can tell you what you should do in this case  other than the obvious   DON T DO IT     If you specifically do NOT care  the answers here are valid   However  you should communicate your understanding that an overflow may occur and that it doesn t matter by wrapping your cast code in an unchecked block  unchecked        do your conversions that may underflow overflow here     That way people coming behind you understand you don t care  and if in the future someone changes your builds to  checked  your code won t break unexpectedly   If all you want to do is drop the fractional portion of the number  leaving the integral part  you can use Math Truncate   decimal actual   10 5M  decimal expected   10M  Assert AreEqual expected  Math Truncate actual

User · Answer

Use Convert ToInt32 from mscorlib as in  decimal value   3 14m  int n   Convert ToInt32 value     See MSDN  You can also use Decimal ToInt32  Again  see MSDN  Finally  you can do a direct cast as in  decimal value   3 14m  int n    int  value    which uses the explicit cast operator  See MSDN

User · Answer

Use Convert ToInt32 from mscorlib as in  decimal value   3 14m  int n   Convert ToInt32 value     See MSDN  You can also use Decimal ToInt32  Again  see MSDN  Finally  you can do a direct cast as in  decimal value   3 14m  int n    int  value    which uses the explicit cast operator  See MSDN

User · Answer

I find that the casting operator does not work if you have a boxed decimal  i e  a decimal value inside an object type    Convert ToInt32 decimal as object  works fine in this case   This situation comes up when retrieving IDENTITY AUTONUMBER values from the database   SqlCommand foo   new SqlCommand  INSERT INTO     SELECT SCOPE IDENTITY     conn   int ID   Convert ToInt32 foo ExecuteScalar         works int ID    int foo ExecuteScalar                    throws InvalidCastException   See 4 3 2 Unboxing conversions

User · Answer

int i    int d    will give you the number rounded down   If you want to round to the nearest even number  i e    5 will round up  you can use  int i    int Math Round d  MidpointRounding ToEven     In general you can cast between all the numerical types in C   If there is no information that will be lost during the cast you can do it implicitly   int i   10  decimal d   i    though you can still do it explicitly if you wish   int i   10  decimal d    decimal i    However  if you are going to be losing information through the cast you must do it explicitly  to show you are aware you may be losing information    decimal d   10 5M  int i    int d    Here you are losing the   5   This may be fine  but you must be explicit about it and make an explicit cast to show you know you may be losing the information

User · Answer

A neat trick for fast rounding is to add .5 before you cast your decimal to an int.

decimal d = 10.1m;
d += .5m;
int i = (int)d;

Still leaves i=10, but

decimal d = 10.5m;
d += .5m;
int i = (int)d;

Would round up so that i=11.

User · Answer

I prefer using Math Round  Math Floor  Math Ceiling or Math Truncate to explicitly set the rounding mode as appropriate    Note that they all return Decimal as well - since Decimal has a larger range of values than an Int32  so you ll still need to cast  and check for overflow underflow     checked      int i    int Math Floor d

User · Answer

You can t   Well  of course you could  however an int  System Int32  is not big enough to hold every possible decimal value     That means if you cast a decimal that s larger than int MaxValue you will overflow  and if the decimal is smaller than int MinValue  it will underflow     What happens when you under overflow   One of two things   If your build is unchecked  i e   the CLR doesn t care if you do   your application will continue after the value over underflows  but the value in the int will not be what you expected   This can lead to intermittent bugs and may be hard to fix   You ll end up your application in an unknown state which may result in your application corrupting whatever important data its working on   Not good   If your assembly is checked  properties- build- advanced- check for arithmetic overflow underflow or the  checked compiler option   your code will throw an exception when an under overflow occurs   This is probably better than not  however the default for assemblies is not to check for over underflow   The real question is  what are you trying to do    Without knowing your requirements  nobody can tell you what you should do in this case  other than the obvious   DON T DO IT     If you specifically do NOT care  the answers here are valid   However  you should communicate your understanding that an overflow may occur and that it doesn t matter by wrapping your cast code in an unchecked block  unchecked        do your conversions that may underflow overflow here     That way people coming behind you understand you don t care  and if in the future someone changes your builds to  checked  your code won t break unexpectedly   If all you want to do is drop the fractional portion of the number  leaving the integral part  you can use Math Truncate   decimal actual   10 5M  decimal expected   10M  Assert AreEqual expected  Math Truncate actual

User · Answer

Use Convert ToInt32 from mscorlib as in  decimal value   3 14m  int n   Convert ToInt32 value     See MSDN  You can also use Decimal ToInt32  Again  see MSDN  Finally  you can do a direct cast as in  decimal value   3 14m  int n    int  value    which uses the explicit cast operator  See MSDN

User · Answer

int i    int d    will give you the number rounded down   If you want to round to the nearest even number  i e    5 will round up  you can use  int i    int Math Round d  MidpointRounding ToEven     In general you can cast between all the numerical types in C   If there is no information that will be lost during the cast you can do it implicitly   int i   10  decimal d   i    though you can still do it explicitly if you wish   int i   10  decimal d    decimal i    However  if you are going to be losing information through the cast you must do it explicitly  to show you are aware you may be losing information    decimal d   10 5M  int i    int d    Here you are losing the   5   This may be fine  but you must be explicit about it and make an explicit cast to show you know you may be losing the information

[c#] How do I convert a decimal to an int in C#?

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