How do I round to the nearest 0 5

Question

I have to display ratings and for that i need increments as follows   If the number is 1 0 it should be equal to 1  If the number is 1 1 should be equal to 1  If the number is 1 2 should be equal to 1  If the number is 1 3 should be equal to 1 5  If the number is 1 4 should be equal to 1 5  If the number is 1 5 should be equal to 1 5  If the number is 1 6 should be equal to 1 5  If the number is 1 7 should be equal to 1 5  If the number is 1 8 should be equal to 2 0  If the number is 1 9 should be equal to 2 0  If the number is 2 0 should be equal to 2 0  If the number is 2 1 should be equal to 2 0  and so on     Is there a simple way to compute the required values

User · Answer

I had difficulty with this problem as well. I code mainly in Actionscript 3.0 which is base coding for the Adobe Flash Platform, but there are simularities in the Languages:

The solution I came up with is the following:

//Code for Rounding to the nearest 0.05
var r:Number = Math.random() * 10;  // NUMBER - Input Your Number here
var n:int = r * 10;   // INTEGER - Shift Decimal 2 places to right
var f:int = Math.round(r * 10 - n) * 5;// INTEGER - Test 1 or 0 then convert to 5
var d:Number = (n + (f / 10)) / 10; //  NUMBER - Re-assemble the number

trace("ORG No: " + r);
trace("NEW No: " + d);

Thats pretty much it. Note the use of 'Numbers' and 'Integers' and the way they are processed.

Good Luck!

User · Answer

There are several options   If performance is a concern  test them to see which works fastest in a large loop   double Adjust double input        double whole   Math Truncate input       double remainder   input - whole      if  remainder  lt  0 3                remainder   0            else if  remainder  lt  0 8                remainder   0 5            else               remainder   1            return whole   remainder

User · Answer

Multiply by 2  round  then divide by 2  if you want nearest quarter  multiply by 4  divide by 4  etc

User · Answer

This answer is taken from Rosdi Kasim s comment in the answer that John Rasch provided  John s answer works but does have an overflow possibility  Here is my version of Rosdi s code  I also put it in an extension to make it easy to use   The extension is not necessary and could be used as a function without issue   lt Extension gt  Public Function ToHalf value As Decimal  As Decimal     Dim integerPart   Decimal Truncate value      Dim fractionPart   value - Decimal Truncate integerPart      Dim roundedFractionPart   Math Round fractionPart   2  MidpointRounding AwayFromZero    2     Dim newValue   integerPart   roundedFractionPart     Return newValue End Function  The usage would then be  Dim newValue   CDec 1 26  ToHalf  This would return 1 5

User · Answer

Sounds like you need to round to the nearest 0 5   I see no version of round in the C  API that does this  one version takes a number of decimal digits to round to  which isn t the same thing    Assuming you only have to deal with integer numbers of tenths  it s sufficient to calculate round  num   2    2   If you re using arbitrarily precise decimals  it gets trickier   Let s hope you don t

User · Answer

The Correct way to do this is     public static Decimal GetPrice Decimal price                                var DecPrice   price   50                  var roundedPrice   Math Round DecPrice  MidpointRounding AwayFromZero                   var finalPrice   roundedPrice   50                   return finalPrice

User · Answer

Public Function Round ByVal text As TextBox  As Integer     Dim r As String   Nothing     If text TextLength  gt  3 Then         Dim Last3 As String    text Text Substring text Text Length - 3           If Last3 Substring 0  1        Then             Dim dimcalvalue As String   Last3 Substring Last3 Length - 2              If Val dimcalvalue   gt   50 Then                 text Text   Val text Text  - Val Last3                  text Text   Val text Text    1             ElseIf Val dimcalvalue   lt  50 Then                 text Text   Val text Text  - Val Last3              End If         End If     End If     Return r End Function

User · Answer

Here are a couple of methods I wrote that will always round up or down to any value   public static Double RoundUpToNearest Double passednumber  Double roundto           105 5 up to nearest 1   106        105 5 up to nearest 10   110        105 5 up to nearest 7   112        105 5 up to nearest 100   200        105 5 up to nearest 0 2   105 6        105 5 up to nearest 0 3   105 6        if no rounto then just pass original number back     if  roundto    0                return passednumber            else               return Math Ceiling passednumber   roundto    roundto           public static Double RoundDownToNearest Double passednumber  Double roundto           105 5 down to nearest 1   105        105 5 down to nearest 10   100        105 5 down to nearest 7   105        105 5 down to nearest 100   100        105 5 down to nearest 0 2   105 4        105 5 down to nearest 0 3   105 3        if no rounto then just pass original number back     if  roundto    0                return passednumber            else               return Math Floor passednumber   roundto    roundto

User · Answer

decimal d      your number    decimal t   d - Math Floor d   if t  gt   0 3d  amp  amp  t  lt   0 7d        return Math Floor d    0 5d    else if t gt 0 7d      return Math Ceil d   return Math Floor d

User · Answer

Multiply your rating by 2  then round using Math Round rating  MidpointRounding AwayFromZero   then divide that value by 2   Math Round value   2  MidpointRounding AwayFromZero    2

[c#] How do I round to the nearest 0.5?

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