You can also use unlist(), which is often useful for handling lists:
> mylist <- list(A = c(1:3), B = c(4:6), C = c(7:9))
> mylist
$A
[1] 1 2 3
$B
[1] 4 5 6
$C
[1] 7 8 9
> unlist(mylist)
A1 A2 A3 B1 B2 B3 C1 C2 C3
1 2 3 4 5 6 7 8 9
> length(unlist(mylist))
[1] 9
unlist() is a simple way of executing other functions on lists as well, such as:
> sum(mylist)
Error in sum(mylist) : invalid 'type' (list) of argument
> sum(unlist(mylist))
[1] 45
I spent ages trying to figure this out but it is simple! You can use length(·). length(mylist) will tell you the number of objects mylist contains.
... and just realised someone had already answered this- sorry!
Advice for R newcomers like me : beware, the following is a list of a single object :
> mylist <- list (1:10)
> length (mylist)
[1] 1
In such a case you are not looking for the length of the list, but of its first element :
> length (mylist[[1]])
[1] 10
This is a "true" list :
> mylist <- list(1:10, rnorm(25), letters[1:3])
> length (mylist)
[1] 3
Also, it seems that R considers a data.frame as a list :
> df <- data.frame (matrix(0, ncol = 30, nrow = 2))
> typeof (df)
[1] "list"
In such a case you may be interested in ncol() and nrow() rather than length() :
> ncol (df)
[1] 30
> nrow (df)
[1] 2
Though length() will also work (but it's a trick when your data.frame has only one column) :
> length (df)
[1] 30
> length (df[[1]])
[1] 2
Let's create an empty list (not required, but good to know):
> mylist <- vector(mode="list")
Let's put some stuff in it - 3 components/indexes/tags (whatever you want to call it) each with differing amounts of elements:
> mylist <- list(record1=c(1:10),record2=c(1:5),record3=c(1:2))
If you are interested in just the number of components in a list use:
> length(mylist)
[1] 3
If you are interested in the length of elements in a specific component of a list use: (both reference the same component here)
length(mylist[[1]])
[1] 10
length(mylist[["record1"]]
[1] 10
If you are interested in the length of all elements in all components of the list use:
> sum(sapply(mylist,length))
[1] 17
Source: Stackoverflow.com