[php] Output an Image in PHP

(Expanding on the accepted answer...)

I needed to:

  1. log views of a jpg image and an animated gif, and,
  2. ensure that the images are never cached (so every view is logged), and,
  3. also retain the original file extensions.

I accomplished this by creating a "secondary" .htaccess file in the sub-folder where the images are located.
The file contains only one line:

AddHandler application/x-httpd-lsphp .jpg .jpeg .gif

In the same folder, I placed the two 'original' image files (we'll call them orig.jpg and orig.gif), as well as two variations of the [simplified] script below (saved as myimage.jpg and myimage.gif)...

<?php 
  error_reporting(0); //hide errors (displaying one would break the image)

  //get user IP and the pseudo-image's URL
  if(isset($_SERVER['REMOTE_ADDR'])) {$ip =$_SERVER['REMOTE_ADDR'];}else{$ip= '(unknown)';}
  if(isset($_SERVER['REQUEST_URI'])) {$url=$_SERVER['REQUEST_URI'];}else{$url='(unknown)';}

  //log the visit
  require_once('connect.php');            //file with db connection info
  $conn = new mysqli($servername, $username, $password, $dbname);
  if (!$conn->connect_error) {         //if connected then save mySQL record
   $conn->query("INSERT INTO imageclicks (image, ip) VALUES ('$url', '$ip');");
     $conn->close();  //(datetime is auto-added to table with default of 'now')
  } 

  //display the image
  $imgfile='orig.jpg';                             // or 'orig.gif'
  header('Content-Type: image/jpeg');              // or 'image/gif'
  header('Content-Length: '.filesize($imgfile));
  header('Cache-Control: no-cache');
  readfile($imgfile);
?>

The images render (or animate) normally and can be called in any of the normal ways for images (like an <img> tag), and will save a record of the visiting IP, while invisible to the user.