Get last dirname filename in a file path argument in Bash

Question

I m trying to write a post-commit hook for SVN  which is hosted on our development server   My goal is to try to automatically checkout a copy of the committed project to the directory where it is hosted on the server   However I need to be able to read only the last directory in the directory string passed to the script in order to checkout to the same sub-directory where our projects are hosted   For example if I make an SVN commit to the project  example   my script gets   usr local svn repos example  as its first argument   I need to get just  example  off the end of the string and then concat it with another string so I can checkout to   server root example  and see the changes live immediately

User · Answer

The following approach can be used to get any path of a pathname:

some_path=a/b/c
echo $(basename $some_path)
echo $(basename $(dirname $some_path))
echo $(basename $(dirname $(dirname $some_path)))

Output:

c
b
a

User · Answer

basename does remove the directory prefix of a path     basename  usr local svn repos example example   echo   server root   basename  usr local svn repos example    server root example

User · Answer

Bash can get the last part of a path without having to call the external basename   subdir   path to whatever   1

[linux] Get last dirname/filename in a file path argument in Bash

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