[c] How to display hexadecimal numbers in C?

I have a list of numbers as below:

0, 16, 32, 48 ...

I need to output those numbers in hexadecimal as:

0000,0010,0020,0030,0040 ...

I have tried solution such as:

printf("%.4x",a); // where a is an integer

but the result that I got is:

0000, 0001, 0002, 0003, 0004 ...

I think I'm close there. Can anybody help as I'm not so good at printf in C.

Thanks.

i use it like this:

printf("my number is 0x%02X\n",number);
// output: my number is 0x4A

Just change number "2" to any number of chars You want to print ;)

You can use the following snippet code:

#include<stdio.h>
int main(int argc, char *argv[]){
    unsigned int i;
    printf("decimal  hexadecimal\n");
    for (i = 0; i <= 256; i+=16)
        printf("%04d     0x%04X\n", i, i);
    return 0;
}

It prints both decimal and hexadecimal numbers in 4 places with zero padding.

Your code has no problem. It does print the way you want. Alternatively, you can do this:

printf("%04x",a);