I'm trying to use the POST method in jQuery to make a data request. So this is the code in the html page:
<form>
Title : <input type="text" size="40" name="title"/>
<input type="button" onclick="headingSearch(this.form)" value="Submit"/><br /><br />
</form>
<script type="text/javascript">
function headingSearch(f)
{
var title=f.title.value;
$.ajax({
type: "POST",
url: "edit.php",
data: {title:title} ,
success: function(data) {
$('.center').html(data);
}
});
}
</script>
And this is the php code on the server :
<?php
$title = $_POST['title'];
if($title != "")
{
echo $title;
}
?>
The POST request is not made at all and I have no idea why. The files are in the same folder in the wamp www folder so at least the url isn't wrong.
This question is related to
php
javascript
jquery
ajax
post
You need to use data: {title: title}
to POST it correctly.
In the PHP code you need to echo
the value instead of return
ing it.
Check whether title has any value or not. If not, then retrive the value using Id.
<form>
Title : <input type="text" id="title" size="40" name="title" value = ''/>
<input type="button" onclick="headingSearch(this.form)" value="Submit"/><br /><br />
</form>
<script type="text/javascript">
function headingSearch(f)
{
var title=jQuery('#title').val();
$.ajax({
type: "POST",
url: "edit.php",
data: {title:title} ,
success: function(data) {
$('.center').html(data);
}
});
}
</script>
Try this code.
In php code, use echo instead of return. Only then, javascript data will have its value.
try this
$(document).on("submit", "#form-data", function(e){
e.preventDefault()
$.ajax({
url: "edit.php",
method: "POST",
data: new FormData(this),
contentType: false,
processData: false,
success: function(data){
$('.center').html(data);
}
})
})
in the form the button needs to be type="submit"
contentType: 'application/x-www-form-urlencoded'
Id advice you to use a bit simplier method -
$.post('edit.php', {title: $('input[name="title"]').val() }, function(resp){
alert(resp);
});
try this one, I just feels its syntax is simplier than the $.ajax's one...
Source: Stackoverflow.com