[php] PHP, Get tomorrows date from date

I have a PHP date in the form of 2013-01-22 and I want to get tomorrows date in the same format, so for example 2013-01-23.

How is this possible with PHP?

here's working function

function plus_one_day($date){
 $date2 = formatDate4db($date);
 $date1 = str_replace('-', '/', $date2);
 $tomorrow = date('Y-m-d',strtotime($date1 . "+1 days"));
 return $tomorrow; }

/**
 * get tomorrow's date in the format requested, default to Y-m-d for MySQL (e.g. 2013-01-04)
 *
 * @param string
 *
 * @return string
 */
public static function getTomorrowsDate($format = 'Y-m-d')
{
    $date = new DateTime();
    $date->add(DateInterval::createFromDateString('tomorrow'));

    return $date->format($format);
}

By strange it can seem it works perfectly fine: date_create( '2016-02-01 + 1 day' );

echo date_create( $your_date . ' + 1 day' )->format( 'Y-m-d' );

Should do it

<? php 

//1 Day = 24*60*60 = 86400

echo date("d-m-Y", time()+86400); 

?>

Since you tagged this with strtotime, you can use it with the +1 day modifier like so:

$tomorrow_timestamp = strtotime('+1 day', strtotime('2013-01-22'));

That said, it's a much better solution to use DateTime.

First, coming up with correct abstractions is always a key. key to readability, maintainability, and extendability.

Here, quite obvious candidate is an ISO8601DateTime. There are at least two implementations: first one is a parsed datetime from a string, and the second one is tomorrow. Hence, there are two classes that can be used, and their combination results in (almost) desired outcome:

new Tomorrow(new FromISO8601('2013-01-22'));

Both objects are an ISO8601 datetime, so their textual representation is not exactly what you need. So the final stroke is to make them take a date-form:

new Date(
    new Tomorrow(
        new FromISO8601('2013-01-22')
    )
);

Since you need a textual representation, not just an object, you invoke a value() method.

For more about this approach, take a look at this post.

$date = '2013-01-22';
$time = strtotime($date) + 86400;
echo date('Y-m-d', $time);

Where 86400 is the # of seconds in a day.

echo date ('Y-m-d',strtotime('+1 day', strtotime($your_date)));

 $tomorrow = date("Y-m-d", strtotime('tomorrow'));

or

  $tomorrow = date("Y-m-d", strtotime("+1 day"));

Help Link: STRTOTIME()

Use DateTime:

To get tomorrow from now :

$d = new DateTime('+1day');
$tomorrow = $d->format('d/m/Y h.i.s');
echo $tomorrow;

Results : 28/06/2017 08.13.20

To get tomorrow from a date :

$d = new DateTime('2017/06/10 08.16.35 +1day')
$tomorrow = $d->format('d/m/Y h.i.s');
echo $tomorrow;

Results : 11/06/2017 08.16.35

Hope it helps!