Saving awk output to variable

Question

Can anyone help me out with this problem   I m trying to save the awk output into a variable   variable    ps -ef   grep  port 10 -    grep -v  grep port 10 -   awk   printf   s    12    printf   variable    EDIT   12 corresponds to a parameter running on that process   Thanks

User · Answer

variable   ps -ef   awk    p ort 10   print  12      The  p  is a neat trick to remove the search from showing from ps   Jeremy If you post the output of ps -ef   grep  port 10   and what you need from the line  it would be more easy to help you getting correct syntax

User · Answer

bin bash  variable  ps -ef   grep  port 10 -    grep -v  grep port 10 -    awk   printf  12    echo  variable   Notice that there s no space after the equal sign   You can also use     which allows nesting and is readable

User · Answer

as noted earlier  setting bash variables does not allow whitespace between the variable name on the LHS  and the variable value on the RHS  of the     sign   awk can do everything and avoid the  awk ward extra  grep   The use of awk s printf is to not add an unnecessary   n  in the string which would give perl-ish matcher programs conniptions  The variable parameter expansion for your case in bash doesn t have that issue  so either of these work   variable   ps -ef   awk   port 10  -   print  12     variable  ps -ef   awk   port 10  -   print  12      The  -  int the awk record matching pattern removes the need to remove awk itself from the search results

User · Answer

I think the     syntax is easier to read     variable   ps -ef   grep  port 10 -    grep -v  grep port 10 -   awk   printf   s    12      But the real issue is probably that  12 should not be qouted with     Edited since the question was changed  This returns valid data  but it is not clear what the expected output of ps -ef is and what is expected in variable

[linux] Saving awk output to variable

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