Sort arrays of primitive types in descending order

Question

I ve got a large array of primitive types  double   How do I sort the elements in descending order   Unfortunately the Java API doesn t support sorting of primitive types with a Comparator   The first approach that probably comes to mind is to convert it to a list of objects  boxing    double   array   new double 1048576       Arrays stream array  boxed   sorted Collections reverseOrder         However  boxing each primitive in the array is too slow and causes a lot of GC pressure   Another approach would be to sort and then reverse   double   array   new double 1048576       Arrays sort array      reverse the array for  int i   0  i  lt  array length   2  i              swap the elements      double temp   array i        array i    array array length -  i   1         array array length -  i   1     temp      This approach is also slow - particularly if the array is already sorted quite well   What s a better alternative

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for small arrays this may work   int getOrder  double num  double   array       double   b   new double array length       for  int i   0  i  lt  array length  i             b i    array i             Arrays sort b       for  int i   0  i  lt  b length  i             if   num  lt  b i   return i            return b length      I was surprised that the initial loading of array b was necessary  double   b   array     makes b point to array  so beware

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You cannot use Comparators for sorting primitive arrays   Your best bet is to implement  or borrow an implementation  of a sorting algorithm that is appropriate  for your use case to sort the array  in reverse order in your case

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I am not aware of any primitive sorting facilities within the Java core API   From my experimentations with the D programming language  a sort of C on steroids   I ve found that the merge sort algorithm is arguably the fastest general-purpose sorting algorithm around  it s what the D language itself uses to implement its sort function     One implementation in Java Another implementation One more implementation

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double s  -1     double   n    111 5  111 2  110 5  101 3  101 9  102 1  115 2  112 1      for int i   n length-1 i gt  0 --i         int k   i-1        while k  gt   0             if n i  gt n k                  s   n k                 n k    n i                 n i    s                        k --                  System out println Arrays toString n     it gives time complexity O n 2  but i hope its work

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With numerical types  negating the elements before and after sort seems an option  Speed relative to a single reverse after sort depends on cache  and if reverse is not faster  any difference may well be lost in noise

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Guava has methods for converting primitive arrays to Lists of wrapper types  The nice part is that these lists are live views  so operations on them work on the underlying arrays as well  similar to Arrays asList    but for primitives    Anyway  each of these Lists can be passed to Collections reverse     int   intArr     1  2  3  4  5    float   floatArr     1 0f  2 0f  3 0f  4 0f  5 0f    double   doubleArr     1 0d  2 0d  3 0d  4 0d  5 0d    byte   byteArr     1  2  3  4  5    short   shortArr     1  2  3  4  5    Collections reverse Ints asList intArr    Collections reverse Floats asList floatArr    Collections reverse Doubles asList doubleArr    Collections reverse Bytes asList byteArr    Collections reverse Shorts asList shortArr    System out println Arrays toString intArr    System out println Arrays toString floatArr    System out println Arrays toString doubleArr    System out println Arrays toString byteArr    System out println Arrays toString shortArr      Output       5  4  3  2  1     5 0  4 0  3 0  2 0  1 0     5 0  4 0  3 0  2 0  1 0     5  4  3  2  1     5  4  3  2  1

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There s been some confusion about Arrays asList in the other answers   If you say  double   arr   new double   6 0  5 0  11 0  7 0   List xs   Arrays asList arr   System out println xs size         prints 1   then you ll have a List with 1 element   The resulting List has the double   array as its own element   What you want is to have a List lt Double gt  whose elements are the elements of the double     Unfortunately  no solution involving Comparators will work for a primitive array   Arrays sort only accepts a Comparator when being passed an Object     And for the reasons describe above  Arrays asList won t let you make a List out of the elements of your array   So despite my earlier answer which the comments below reference  there s no better way than manually reversing the array after sorting   Any other approach  such as copying the elements into a Double   and reverse-sorting and copying them back  would be more code and slower

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In Java 8  a better and more concise approach could be   double   arr    13 6  7 2  6 02  45 8  21 09  9 12  2 53  100 4    Double   boxedarr   Arrays stream  arr   boxed   toArray  Double    new    Arrays sort boxedarr  Collections reverseOrder     System out println Arrays toString boxedarr      This would give the reversed array and is more presentable   Input   13 6  7 2  6 02  45 8  21 09  9 12  2 53  100 4   Output   100 4  45 8  21 09  13 6  9 12  7 2  6 02  2 53

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I think the easiest solution is still    Getting the natural order of the array  Finding the maximum within that sorted array which is then the last item  Using a for-loop with decrement operator   As said by others before  using toList is additional effort  Arrays sort array Collections reverseOrder    doesn t work with primitives and using an extra framework seems too complicated when all you need is already inbuild and therefore probably faster as well     Sample code   import java util Arrays   public class SimpleDescending        public static void main String   args                unsorted array         int   integerList    55  44  33  88  99               Getting the natural  ascending  order of the array         Arrays sort integerList               Getting the last item of the now sorted array  which represents the maximum  in other words  highest number          int max   integerList length-1              reversing the order with a simple for-loop         System out println  Array in descending order             for int i max  i gt  0  i--                System out println integerList i                          You could make the code even shorter skipping the variable max and use             int i integerList length-1  instead of int  i max  in the parentheses of the for-loop

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Your algorithm is correct  But we can do optimization as follows  While reversing  You may try keeping another variable to reduce backward counter since computing of array length- i 1  may take time  And also move declaration of temp outside so that everytime it needs not to be allocated   double temp   for int i 0 j array length-1  i  lt   array length 2   i    j--             swap the elements      temp   array i        array i    array j        array j    temp

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Below is my solution  you can adapt it to your needs    How does it work  It takes an array of integers as arguments  After that it will create a new array which will contain the same values as the array from the arguments  The reason of doing this is to leave the original array intact   Once the new array contains the copied data  we sort it by swapping the values until the condition if newArr i   lt  newArr i 1   evaluates to false  That means the array is sorted in descending order   For a thorough explanation check my blog post here   public static int   sortDescending int   array        int   newArr   new int array length        for int i   0  i  lt  array length  i                  newArr i    array i              boolean flag   true      int tempValue       while flag                 flag   false           for int i   0  i  lt  newArr length - 1  i                           if newArr i   lt  newArr i 1                                 tempValue   newArr i                   newArr i    newArr i 1                   newArr i 1    tempValue                  flag   true                                     return newArr

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Below is my solution  you can adapt it to your needs    How does it work  It takes an array of integers as arguments  After that it will create a new array which will contain the same values as the array from the arguments  The reason of doing this is to leave the original array intact   Once the new array contains the copied data  we sort it by swapping the values until the condition if newArr i   lt  newArr i 1   evaluates to false  That means the array is sorted in descending order   For a thorough explanation check my blog post here   public static int   sortDescending int   array        int   newArr   new int array length        for int i   0  i  lt  array length  i                  newArr i    array i              boolean flag   true      int tempValue       while flag                 flag   false           for int i   0  i  lt  newArr length - 1  i                           if newArr i   lt  newArr i 1                                 tempValue   newArr i                   newArr i    newArr i 1                   newArr i 1    tempValue                  flag   true                                     return newArr

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Heres a one-liner  using streams in Java 8  int arr   new int   1 2 3 4 5   Arrays stream arr  boxed   sorted Collections reverseOrder    mapToInt Integer  intValue  toArray

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I am not aware of any primitive sorting facilities within the Java core API   From my experimentations with the D programming language  a sort of C on steroids   I ve found that the merge sort algorithm is arguably the fastest general-purpose sorting algorithm around  it s what the D language itself uses to implement its sort function     One implementation in Java Another implementation One more implementation

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Before sorting the given array multiply each element by -1    then use Arrays sort arr  then again multiply each element by -1  for int i 0 i lt arr length i        arr i  -arr i   Arrays sort arr   for int i 0 i lt arr length i        arr i  -arr i

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There s been some confusion about Arrays asList in the other answers   If you say  double   arr   new double   6 0  5 0  11 0  7 0   List xs   Arrays asList arr   System out println xs size         prints 1   then you ll have a List with 1 element   The resulting List has the double   array as its own element   What you want is to have a List lt Double gt  whose elements are the elements of the double     Unfortunately  no solution involving Comparators will work for a primitive array   Arrays sort only accepts a Comparator when being passed an Object     And for the reasons describe above  Arrays asList won t let you make a List out of the elements of your array   So despite my earlier answer which the comments below reference  there s no better way than manually reversing the array after sorting   Any other approach  such as copying the elements into a Double   and reverse-sorting and copying them back  would be more code and slower

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Double   d    5 5  1 3  8 8   Arrays sort d  Collections reverseOrder     System out println Arrays toString d      Collections reverseOrder   doesn t work on primitives  but Double  Integer etc works with Collections reverseOrder

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If performance is important  and the list usually already is sorted quite well   Bubble sort should be one of the slowest ways of sorting  but I have seen cases where the best performance was a simple bi-directional bubble sort   So this may be one of the few cases where you can benefit from coding it yourself  But you really need to do it right  make sure at least somebody else confirms your code  make a proof that it works etc    As somebody else pointed out  it may be even better to start with a sorted array  and keep it sorted while you change the contents  That may perform even better

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Your implementation  the one in the question  is faster than e g  wrapping with toList   and using a comparator-based method   Auto-boxing and running through comparator methods or wrapped Collections objects is far slower than just reversing   Of course you could write your own sort   That might not be the answer you re looking for  but note that if your comment about  if the array is already sorted quite well  happens frequently  you might do well to choose a sorting algorithm that handles that case well  e g  insertion  rather than use Arrays sort    which is mergesort  or insertion if the number of elements is small

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double   array   new double 1048576          By default order is ascending   To reverse the order   Arrays sort array Collections reverseOrder

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double s  -1     double   n    111 5  111 2  110 5  101 3  101 9  102 1  115 2  112 1      for int i   n length-1 i gt  0 --i         int k   i-1        while k  gt   0             if n i  gt n k                  s   n k                 n k    n i                 n i    s                        k --                  System out println Arrays toString n     it gives time complexity O n 2  but i hope its work

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Understand it s a very old post but I stumbled upon a similar problem trying to sort primitive int arrays  so posting my solution  Suggestions comments welcome -  int   arr    3 2 1 3   List lt Integer gt  list   new ArrayList lt  gt     Arrays stream arr  forEach i - gt  list add i    list stream   sorted Comparator reverseOrder    forEach System out  println

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for small arrays this may work   int getOrder  double num  double   array       double   b   new double array length       for  int i   0  i  lt  array length  i             b i    array i             Arrays sort b       for  int i   0  i  lt  b length  i             if   num  lt  b i   return i            return b length      I was surprised that the initial loading of array b was necessary  double   b   array     makes b point to array  so beware

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double   array   new double 1048576          By default order is ascending   To reverse the order   Arrays sort array Collections reverseOrder

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Your implementation  the one in the question  is faster than e g  wrapping with toList   and using a comparator-based method   Auto-boxing and running through comparator methods or wrapped Collections objects is far slower than just reversing   Of course you could write your own sort   That might not be the answer you re looking for  but note that if your comment about  if the array is already sorted quite well  happens frequently  you might do well to choose a sorting algorithm that handles that case well  e g  insertion  rather than use Arrays sort    which is mergesort  or insertion if the number of elements is small

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Your algorithm is correct  But we can do optimization as follows  While reversing  You may try keeping another variable to reduce backward counter since computing of array length- i 1  may take time  And also move declaration of temp outside so that everytime it needs not to be allocated   double temp   for int i 0 j array length-1  i  lt   array length 2   i    j--             swap the elements      temp   array i        array i    array j        array j    temp

User · Answer

I am not aware of any primitive sorting facilities within the Java core API   From my experimentations with the D programming language  a sort of C on steroids   I ve found that the merge sort algorithm is arguably the fastest general-purpose sorting algorithm around  it s what the D language itself uses to implement its sort function     One implementation in Java Another implementation One more implementation

User · Answer

With numerical types  negating the elements before and after sort seems an option  Speed relative to a single reverse after sort depends on cache  and if reverse is not faster  any difference may well be lost in noise

User · Answer

If performance is important  and the list usually already is sorted quite well   Bubble sort should be one of the slowest ways of sorting  but I have seen cases where the best performance was a simple bi-directional bubble sort   So this may be one of the few cases where you can benefit from coding it yourself  But you really need to do it right  make sure at least somebody else confirms your code  make a proof that it works etc    As somebody else pointed out  it may be even better to start with a sorted array  and keep it sorted while you change the contents  That may perform even better

User · Answer

Your implementation  the one in the question  is faster than e g  wrapping with toList   and using a comparator-based method   Auto-boxing and running through comparator methods or wrapped Collections objects is far slower than just reversing   Of course you could write your own sort   That might not be the answer you re looking for  but note that if your comment about  if the array is already sorted quite well  happens frequently  you might do well to choose a sorting algorithm that handles that case well  e g  insertion  rather than use Arrays sort    which is mergesort  or insertion if the number of elements is small

User · Answer

Understand it s a very old post but I stumbled upon a similar problem trying to sort primitive int arrays  so posting my solution  Suggestions comments welcome -  int   arr    3 2 1 3   List lt Integer gt  list   new ArrayList lt  gt     Arrays stream arr  forEach i - gt  list add i    list stream   sorted Comparator reverseOrder    forEach System out  println

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Your algorithm is correct  But we can do optimization as follows  While reversing  You may try keeping another variable to reduce backward counter since computing of array length- i 1  may take time  And also move declaration of temp outside so that everytime it needs not to be allocated   double temp   for int i 0 j array length-1  i  lt   array length 2   i    j--             swap the elements      temp   array i        array i    array j        array j    temp

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There s been some confusion about Arrays asList in the other answers   If you say  double   arr   new double   6 0  5 0  11 0  7 0   List xs   Arrays asList arr   System out println xs size         prints 1   then you ll have a List with 1 element   The resulting List has the double   array as its own element   What you want is to have a List lt Double gt  whose elements are the elements of the double     Unfortunately  no solution involving Comparators will work for a primitive array   Arrays sort only accepts a Comparator when being passed an Object     And for the reasons describe above  Arrays asList won t let you make a List out of the elements of your array   So despite my earlier answer which the comments below reference  there s no better way than manually reversing the array after sorting   Any other approach  such as copying the elements into a Double   and reverse-sorting and copying them back  would be more code and slower

User · Answer

If performance is important  and the list usually already is sorted quite well   Bubble sort should be one of the slowest ways of sorting  but I have seen cases where the best performance was a simple bi-directional bubble sort   So this may be one of the few cases where you can benefit from coding it yourself  But you really need to do it right  make sure at least somebody else confirms your code  make a proof that it works etc    As somebody else pointed out  it may be even better to start with a sorted array  and keep it sorted while you change the contents  That may perform even better

User · Answer

I am not aware of any primitive sorting facilities within the Java core API   From my experimentations with the D programming language  a sort of C on steroids   I ve found that the merge sort algorithm is arguably the fastest general-purpose sorting algorithm around  it s what the D language itself uses to implement its sort function     One implementation in Java Another implementation One more implementation

User · Answer

I think it would be best not to re-invent the wheel and use Arrays sort     Yes  I saw the  descending  part  The sorting is the hard part  and you want to benefit from the simplicity and speed of Java s library code  Once that s done  you simply reverse the array  which is a relatively cheap O n  operation  Here s some code I found to do this in as little as 4 lines   for  int left 0  right b length-1  left lt right  left    right--           exchange the first and last     int temp   b left   b left     b right   b right    temp

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Here s a full program that sorts objects based on a inner field  package Algorithms BranchAndBound   import java util Arrays  import java util Comparator   public class KnapSack01       private class ItemVals           double weight          double cost          double ratio           public ItemVals double weight  double cost                this weight   weight              this cost   cost              this ratio   weight cost                       public ItemVals   createSortedItemVals double   weight  double   cost            ItemVals   itemVals   new ItemVals weight length           for int i   0  i  lt  weight length  i                  ItemVals itemval   new ItemVals weight i   cost i                itemVals i    itemval                    Arrays sort itemVals  new Comparator lt ItemVals gt                   Override             public int compare ItemVals o1  ItemVals o2                    return Double compare o2 ratio  o1 ratio                                     return itemVals             public void printItemVals ItemVals   itemVals            for  int i   0  i  lt  itemVals length  i                  System out println itemVals i  ratio                        public static void main String   args            KnapSack01 knapSack01   new KnapSack01            double   weight    2  3 14  1 98  5  3           double   cost    40  50  100  95  30           ItemVals   itemVals   knapSack01 createSortedItemVals weight  cost           knapSack01 printItemVals itemVals

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Here s a full program that sorts objects based on a inner field  package Algorithms BranchAndBound   import java util Arrays  import java util Comparator   public class KnapSack01       private class ItemVals           double weight          double cost          double ratio           public ItemVals double weight  double cost                this weight   weight              this cost   cost              this ratio   weight cost                       public ItemVals   createSortedItemVals double   weight  double   cost            ItemVals   itemVals   new ItemVals weight length           for int i   0  i  lt  weight length  i                  ItemVals itemval   new ItemVals weight i   cost i                itemVals i    itemval                    Arrays sort itemVals  new Comparator lt ItemVals gt                   Override             public int compare ItemVals o1  ItemVals o2                    return Double compare o2 ratio  o1 ratio                                     return itemVals             public void printItemVals ItemVals   itemVals            for  int i   0  i  lt  itemVals length  i                  System out println itemVals i  ratio                        public static void main String   args            KnapSack01 knapSack01   new KnapSack01            double   weight    2  3 14  1 98  5  3           double   cost    40  50  100  95  30           ItemVals   itemVals   knapSack01 createSortedItemVals weight  cost           knapSack01 printItemVals itemVals

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I think it would be best not to re-invent the wheel and use Arrays sort     Yes  I saw the  descending  part  The sorting is the hard part  and you want to benefit from the simplicity and speed of Java s library code  Once that s done  you simply reverse the array  which is a relatively cheap O n  operation  Here s some code I found to do this in as little as 4 lines   for  int left 0  right b length-1  left lt right  left    right--           exchange the first and last     int temp   b left   b left     b right   b right    temp

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Java Primitive includes functionality for sorting primitive arrays based on a custom comparator  Using it  and Java 8  your sample could be written as   double   array   new double 1048576       Primitive sort array   d1  d2  - gt  Double compare d2  d1   false     If you re using Maven  you can include it with    lt dependency gt       lt groupId gt net mintern lt  groupId gt       lt artifactId gt primitive lt  artifactId gt       lt version gt 1 2 1 lt  version gt   lt  dependency gt    When you pass false as the third argument to sort  it uses an unstable sort  a simple edit of Java s built-in dual-pivot quicksort  This means that the speed should be close to that of built-in sorting   Full disclosure  I wrote the Java Primitive library

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If using java8  just convert array to stream  sort and convert back  All of the tasks can be done just in one line  so I feel this way is not too bad   double   nums   Arrays stream nums  boxed             sorted  i1  i2  - gt  Double compare i2  i1            mapToDouble Double  doubleValue           toArray

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double   array   new double 1048576          By default order is ascending   To reverse the order   Arrays sort array Collections reverseOrder

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You cannot use Comparators for sorting primitive arrays   Your best bet is to implement  or borrow an implementation  of a sorting algorithm that is appropriate  for your use case to sort the array  in reverse order in your case

User · Answer

Before sorting the given array multiply each element by -1    then use Arrays sort arr  then again multiply each element by -1  for int i 0 i lt arr length i        arr i  -arr i   Arrays sort arr   for int i 0 i lt arr length i        arr i  -arr i

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Double   d    5 5  1 3  8 8   Arrays sort d  Collections reverseOrder     System out println Arrays toString d      Collections reverseOrder   doesn t work on primitives  but Double  Integer etc works with Collections reverseOrder

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I think the easiest solution is still    Getting the natural order of the array  Finding the maximum within that sorted array which is then the last item  Using a for-loop with decrement operator   As said by others before  using toList is additional effort  Arrays sort array Collections reverseOrder    doesn t work with primitives and using an extra framework seems too complicated when all you need is already inbuild and therefore probably faster as well     Sample code   import java util Arrays   public class SimpleDescending        public static void main String   args                unsorted array         int   integerList    55  44  33  88  99               Getting the natural  ascending  order of the array         Arrays sort integerList               Getting the last item of the now sorted array  which represents the maximum  in other words  highest number          int max   integerList length-1              reversing the order with a simple for-loop         System out println  Array in descending order             for int i max  i gt  0  i--                System out println integerList i                          You could make the code even shorter skipping the variable max and use             int i integerList length-1  instead of int  i max  in the parentheses of the for-loop

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Heres a one-liner  using streams in Java 8  int arr   new int   1 2 3 4 5   Arrays stream arr  boxed   sorted Collections reverseOrder    mapToInt Integer  intValue  toArray

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Your implementation  the one in the question  is faster than e g  wrapping with toList   and using a comparator-based method   Auto-boxing and running through comparator methods or wrapped Collections objects is far slower than just reversing   Of course you could write your own sort   That might not be the answer you re looking for  but note that if your comment about  if the array is already sorted quite well  happens frequently  you might do well to choose a sorting algorithm that handles that case well  e g  insertion  rather than use Arrays sort    which is mergesort  or insertion if the number of elements is small

User · Answer

Guava has methods for converting primitive arrays to Lists of wrapper types  The nice part is that these lists are live views  so operations on them work on the underlying arrays as well  similar to Arrays asList    but for primitives    Anyway  each of these Lists can be passed to Collections reverse     int   intArr     1  2  3  4  5    float   floatArr     1 0f  2 0f  3 0f  4 0f  5 0f    double   doubleArr     1 0d  2 0d  3 0d  4 0d  5 0d    byte   byteArr     1  2  3  4  5    short   shortArr     1  2  3  4  5    Collections reverse Ints asList intArr    Collections reverse Floats asList floatArr    Collections reverse Doubles asList doubleArr    Collections reverse Bytes asList byteArr    Collections reverse Shorts asList shortArr    System out println Arrays toString intArr    System out println Arrays toString floatArr    System out println Arrays toString doubleArr    System out println Arrays toString byteArr    System out println Arrays toString shortArr      Output       5  4  3  2  1     5 0  4 0  3 0  2 0  1 0     5 0  4 0  3 0  2 0  1 0     5  4  3  2  1     5  4  3  2  1

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Your algorithm is correct  But we can do optimization as follows  While reversing  You may try keeping another variable to reduce backward counter since computing of array length- i 1  may take time  And also move declaration of temp outside so that everytime it needs not to be allocated   double temp   for int i 0 j array length-1  i  lt   array length 2   i    j--             swap the elements      temp   array i        array i    array j        array j    temp

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I think it would be best not to re-invent the wheel and use Arrays sort     Yes  I saw the  descending  part  The sorting is the hard part  and you want to benefit from the simplicity and speed of Java s library code  Once that s done  you simply reverse the array  which is a relatively cheap O n  operation  Here s some code I found to do this in as little as 4 lines   for  int left 0  right b length-1  left lt right  left    right--           exchange the first and last     int temp   b left   b left     b right   b right    temp

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double   array   new double 1048576          By default order is ascending   To reverse the order   Arrays sort array Collections reverseOrder

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In Java 8  a better and more concise approach could be   double   arr    13 6  7 2  6 02  45 8  21 09  9 12  2 53  100 4    Double   boxedarr   Arrays stream  arr   boxed   toArray  Double    new    Arrays sort boxedarr  Collections reverseOrder     System out println Arrays toString boxedarr      This would give the reversed array and is more presentable   Input   13 6  7 2  6 02  45 8  21 09  9 12  2 53  100 4   Output   100 4  45 8  21 09  13 6  9 12  7 2  6 02  2 53

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You cannot use Comparators for sorting primitive arrays   Your best bet is to implement  or borrow an implementation  of a sorting algorithm that is appropriate  for your use case to sort the array  in reverse order in your case

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There s been some confusion about Arrays asList in the other answers   If you say  double   arr   new double   6 0  5 0  11 0  7 0   List xs   Arrays asList arr   System out println xs size         prints 1   then you ll have a List with 1 element   The resulting List has the double   array as its own element   What you want is to have a List lt Double gt  whose elements are the elements of the double     Unfortunately  no solution involving Comparators will work for a primitive array   Arrays sort only accepts a Comparator when being passed an Object     And for the reasons describe above  Arrays asList won t let you make a List out of the elements of your array   So despite my earlier answer which the comments below reference  there s no better way than manually reversing the array after sorting   Any other approach  such as copying the elements into a Double   and reverse-sorting and copying them back  would be more code and slower

User · Answer

Java Primitive includes functionality for sorting primitive arrays based on a custom comparator  Using it  and Java 8  your sample could be written as   double   array   new double 1048576       Primitive sort array   d1  d2  - gt  Double compare d2  d1   false     If you re using Maven  you can include it with    lt dependency gt       lt groupId gt net mintern lt  groupId gt       lt artifactId gt primitive lt  artifactId gt       lt version gt 1 2 1 lt  version gt   lt  dependency gt    When you pass false as the third argument to sort  it uses an unstable sort  a simple edit of Java s built-in dual-pivot quicksort  This means that the speed should be close to that of built-in sorting   Full disclosure  I wrote the Java Primitive library

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I think it would be best not to re-invent the wheel and use Arrays sort     Yes  I saw the  descending  part  The sorting is the hard part  and you want to benefit from the simplicity and speed of Java s library code  Once that s done  you simply reverse the array  which is a relatively cheap O n  operation  Here s some code I found to do this in as little as 4 lines   for  int left 0  right b length-1  left lt right  left    right--           exchange the first and last     int temp   b left   b left     b right   b right    temp

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If using java8  just convert array to stream  sort and convert back  All of the tasks can be done just in one line  so I feel this way is not too bad   double   nums   Arrays stream nums  boxed             sorted  i1  i2  - gt  Double compare i2  i1            mapToDouble Double  doubleValue           toArray

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If performance is important  and the list usually already is sorted quite well   Bubble sort should be one of the slowest ways of sorting  but I have seen cases where the best performance was a simple bi-directional bubble sort   So this may be one of the few cases where you can benefit from coding it yourself  But you really need to do it right  make sure at least somebody else confirms your code  make a proof that it works etc    As somebody else pointed out  it may be even better to start with a sorted array  and keep it sorted while you change the contents  That may perform even better

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You cannot use Comparators for sorting primitive arrays   Your best bet is to implement  or borrow an implementation  of a sorting algorithm that is appropriate  for your use case to sort the array  in reverse order in your case

[java] Sort arrays of primitive types in descending order

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Examples related to sorting