How can I launch an application using C#?
Requirements: Must work on Windows XP and Windows Vista.
I have seen a sample from DinnerNow.net sampler that only works in Windows Vista.
This question is related to
c#
.net
windows-vista
windows-xp
Use System.Diagnostics.Process.Start() method.
Check out this article on how to use it.
Process.Start("notepad", "readme.txt");
string winpath = Environment.GetEnvironmentVariable("windir");
string path = System.IO.Path.GetDirectoryName(
System.Windows.Forms.Application.ExecutablePath);
Process.Start(winpath + @"\Microsoft.NET\Framework\v1.0.3705\Installutil.exe",
path + "\\MyService.exe");
Additionally you will want to use the Environment Variables for your paths if at all possible: http://en.wikipedia.org/wiki/Environment_variable#Default_Values_on_Microsoft_Windows
E.G.
There are many more check out the link for a longer list.
Here's a snippet of helpful code:
using System.Diagnostics;
// Prepare the process to run
ProcessStartInfo start = new ProcessStartInfo();
// Enter in the command line arguments, everything you would enter after the executable name itself
start.Arguments = arguments;
// Enter the executable to run, including the complete path
start.FileName = ExeName;
// Do you want to show a console window?
start.WindowStyle = ProcessWindowStyle.Hidden;
start.CreateNoWindow = true;
int exitCode;
// Run the external process & wait for it to finish
using (Process proc = Process.Start(start))
{
proc.WaitForExit();
// Retrieve the app's exit code
exitCode = proc.ExitCode;
}
There is much more you can do with these objects, you should read the documentation: ProcessStartInfo, Process.
System.Diagnostics.Process.Start( @"C:\Windows\System32\Notepad.exe" );
Try this:
Process.Start("Location Of File.exe");
(Make sure you use the System.Diagnostics library)
Here's a snippet of helpful code:
using System.Diagnostics;
// Prepare the process to run
ProcessStartInfo start = new ProcessStartInfo();
// Enter in the command line arguments, everything you would enter after the executable name itself
start.Arguments = arguments;
// Enter the executable to run, including the complete path
start.FileName = ExeName;
// Do you want to show a console window?
start.WindowStyle = ProcessWindowStyle.Hidden;
start.CreateNoWindow = true;
int exitCode;
// Run the external process & wait for it to finish
using (Process proc = Process.Start(start))
{
proc.WaitForExit();
// Retrieve the app's exit code
exitCode = proc.ExitCode;
}
There is much more you can do with these objects, you should read the documentation: ProcessStartInfo, Process.
System.Diagnostics.Process.Start("PathToExe.exe");
System.Diagnostics.Process.Start( @"C:\Windows\System32\Notepad.exe" );
Just put your file.exe in the \bin\Debug folder and use:
Process.Start("File.exe");
Use Process.Start to start a process.
using System.Diagnostics;
class Program
{
static void Main()
{
//
// your code
//
Process.Start("C:\\process.exe");
}
}
If you have problems using System.Diagnostics like I had, use the following simple code that will work without it:
using System.Diagnostics;
Process notePad = new Process();
notePad.StartInfo.FileName = "notepad.exe";
notePad.StartInfo.Arguments = "mytextfile.txt";
notePad.Start();
Use Process.Start to start a process.
using System.Diagnostics;
class Program
{
static void Main()
{
//
// your code
//
Process.Start("C:\\process.exe");
}
}
Just put your file.exe in the \bin\Debug folder and use:
Process.Start("File.exe");
System.Diagnostics.Process.Start("PathToExe.exe");
Here's a snippet of helpful code:
using System.Diagnostics;
// Prepare the process to run
ProcessStartInfo start = new ProcessStartInfo();
// Enter in the command line arguments, everything you would enter after the executable name itself
start.Arguments = arguments;
// Enter the executable to run, including the complete path
start.FileName = ExeName;
// Do you want to show a console window?
start.WindowStyle = ProcessWindowStyle.Hidden;
start.CreateNoWindow = true;
int exitCode;
// Run the external process & wait for it to finish
using (Process proc = Process.Start(start))
{
proc.WaitForExit();
// Retrieve the app's exit code
exitCode = proc.ExitCode;
}
There is much more you can do with these objects, you should read the documentation: ProcessStartInfo, Process.
System.Diagnostics.Process.Start("PathToExe.exe");
Here's a snippet of helpful code:
using System.Diagnostics;
// Prepare the process to run
ProcessStartInfo start = new ProcessStartInfo();
// Enter in the command line arguments, everything you would enter after the executable name itself
start.Arguments = arguments;
// Enter the executable to run, including the complete path
start.FileName = ExeName;
// Do you want to show a console window?
start.WindowStyle = ProcessWindowStyle.Hidden;
start.CreateNoWindow = true;
int exitCode;
// Run the external process & wait for it to finish
using (Process proc = Process.Start(start))
{
proc.WaitForExit();
// Retrieve the app's exit code
exitCode = proc.ExitCode;
}
There is much more you can do with these objects, you should read the documentation: ProcessStartInfo, Process.
If you have problems using System.Diagnostics like I had, use the following simple code that will work without it:
using System.Diagnostics;
Process notePad = new Process();
notePad.StartInfo.FileName = "notepad.exe";
notePad.StartInfo.Arguments = "mytextfile.txt";
notePad.Start();
Additionally you will want to use the Environment Variables for your paths if at all possible: http://en.wikipedia.org/wiki/Environment_variable#Default_Values_on_Microsoft_Windows
E.G.
There are many more check out the link for a longer list.
System.Diagnostics.Process.Start("PathToExe.exe");
Additionally you will want to use the Environment Variables for your paths if at all possible: http://en.wikipedia.org/wiki/Environment_variable#Default_Values_on_Microsoft_Windows
E.G.
There are many more check out the link for a longer list.
Source: Stackoverflow.com