I'd like to do it in python. What I'd like to do in this example in c:
In C:
#include <stdio.h>
int main() {
int i;
for (i=0; i<10; i++) printf(".");
return 0;
}
Output:
..........
In Python:
>>> for i in range(10): print('.')
.
.
.
.
.
.
.
.
.
.
>>> print('.', '.', '.', '.', '.', '.', '.', '.', '.', '.')
. . . . . . . . . .
In Python print
will add a \n
or space, how can I avoid that? Now, it's just an example, don't tell me I can first build a string then print it. I'd like to know how to "append" strings to stdout
.
you want to print something in for loop right;but you don't want it print in new line every time.. for example:
for i in range (0,5):
print "hi"
OUTPUT:
hi
hi
hi
hi
hi
but you want it to print like this: hi hi hi hi hi hi right???? just add a comma after print "hi"
Example:
for i in range (0,5):
print "hi",
OUTPUT:
hi hi hi hi hi
for i in xrange(0,10): print '\b.',
This worked in both 2.7.8 & 2.5.2 (Canopy and OSX terminal, respectively) -- no module imports or time travel required.
The new (as of Python 3.x) print
function has an optional end
parameter that lets you modify the ending character:
print("HELLO", end="")
print("HELLO")
Output:
HELLOHELLO
There's also sep
for separator:
print("HELLO", "HELLO", "HELLO", sep="")
Output:
HELLOHELLOHELLO
If you wanted to use this in Python 2.x just add this at the start of your file:
from __future__ import print_function
i recently had the same problem..
i solved it by doing:
import sys, os
# reopen stdout with "newline=None".
# in this mode,
# input: accepts any newline character, outputs as '\n'
# output: '\n' converts to os.linesep
sys.stdout = os.fdopen(sys.stdout.fileno(), "w", newline=None)
for i in range(1,10):
print(i)
this works on both unix and windows ... have not tested it on macosx ...
hth
for i in xrange(0,10): print '\b.',
This worked in both 2.7.8 & 2.5.2 (Canopy and OSX terminal, respectively) -- no module imports or time travel required.
You can just add ,
in the end of print
function so it won't print on new line.
You can do the same in python3 as follows :
#!usr/bin/python
i = 0
while i<10 :
print('.',end='')
i = i+1
and execute it with python filename.py
or python3 filename.py
You will notice that all the above answers are correct. But I wanted to make a shortcut to always writing the " end='' " parameter in the end.
You could define a function like
def Print(*args,sep='',end='',file=None,flush=False):
print(*args,sep=sep,end=end,file=file,flush=flush)
It would accept all the number of parameters. Even it will accept all the other parameters like file, flush ,etc and with the same name.
you want to print something in for loop right;but you don't want it print in new line every time.. for example:
for i in range (0,5):
print "hi"
OUTPUT:
hi
hi
hi
hi
hi
but you want it to print like this: hi hi hi hi hi hi right???? just add a comma after print "hi"
Example:
for i in range (0,5):
print "hi",
OUTPUT:
hi hi hi hi hi
...you do not need to import any library. Just use the delete character:
BS=u'\0008' # the unicode for "delete" character
for i in range(10):print(BS+"."),
this removes the newline and the space (^_^)*
python 2.6+:
from __future__ import print_function # needs to be first statement in file
print('.', end='')
python 3:
print('.', end='')
python <= 2.5:
import sys
sys.stdout.write('.')
if extra space is OK after each print, in python 2
print '.',
misleading in python 2 - avoid:
print('.'), # avoid this if you want to remain sane
# this makes it look like print is a function but it is not
# this is the `,` creating a tuple and the parentheses enclose an expression
# to see the problem, try:
print('.', 'x'), # this will print `('.', 'x') `
Or have a function like:
def Print(s):
return sys.stdout.write(str(s))
Then now:
for i in range(10): # or `xrange` for python 2 version
Print(i)
Outputs:
0123456789
In Python 3+, print
is a function. When you call
print('hello world')
Python translates it to
print('hello world', end='\n')
You can change end
to whatever you want.
print('hello world', end='')
print('hello world', end=' ')
i recently had the same problem..
i solved it by doing:
import sys, os
# reopen stdout with "newline=None".
# in this mode,
# input: accepts any newline character, outputs as '\n'
# output: '\n' converts to os.linesep
sys.stdout = os.fdopen(sys.stdout.fileno(), "w", newline=None)
for i in range(1,10):
print(i)
this works on both unix and windows ... have not tested it on macosx ...
hth
Using functools.partial to create a new function called printf
>>> import functools
>>> printf = functools.partial(print, end="")
>>> printf("Hello world\n")
Hello world
Easy way to wrap a function with default parameters.
for i in range(0, 5): #setting the value of (i) in the range 0 to 5
print(i)
The above code gives the following output:
0
1
2
3
4
But if you want to print all these output in a straight line then all you should do is add an attribute called end() to print.
for i in range(0, 5): #setting the value of (i) in the range 0 to 5
print(i, end=" ")
Output:
0 1 2 3 4
And not just a space, you can also add other endings for your output. For example,
for i in range(0, 5): #setting the value of (i) in the range 0 to 5
print(i, end=", ")
Output:
0, 1, 2, 3, 4,
Remember:
Note: The [for variable in range(int_1, int_2):] always prints till the variable is 1
less than it's limit. (1 less than int_2)
The new (as of Python 3.x) print
function has an optional end
parameter that lets you modify the ending character:
print("HELLO", end="")
print("HELLO")
Output:
HELLOHELLO
There's also sep
for separator:
print("HELLO", "HELLO", "HELLO", sep="")
Output:
HELLOHELLOHELLO
If you wanted to use this in Python 2.x just add this at the start of your file:
from __future__ import print_function
In Python 3+, print
is a function. When you call
print('hello world')
Python translates it to
print('hello world', end='\n')
You can change end
to whatever you want.
print('hello world', end='')
print('hello world', end=' ')
for i in range(0, 5): #setting the value of (i) in the range 0 to 5
print(i)
The above code gives the following output:
0
1
2
3
4
But if you want to print all these output in a straight line then all you should do is add an attribute called end() to print.
for i in range(0, 5): #setting the value of (i) in the range 0 to 5
print(i, end=" ")
Output:
0 1 2 3 4
And not just a space, you can also add other endings for your output. For example,
for i in range(0, 5): #setting the value of (i) in the range 0 to 5
print(i, end=", ")
Output:
0, 1, 2, 3, 4,
Remember:
Note: The [for variable in range(int_1, int_2):] always prints till the variable is 1
less than it's limit. (1 less than int_2)
Use the python3-style print function for python2.6+ (will also break any existing keyworded print statements in the same file.)
# for python2 to use the print() function, removing the print keyword
from __future__ import print_function
for x in xrange(10):
print('.', end='')
To not ruin all your python2 print keywords, create a separate printf.py
file
# printf.py
from __future__ import print_function
def printf(str, *args):
print(str % args, end='')
Then, use it in your file
from printf import printf
for x in xrange(10):
printf('.')
print 'done'
#..........done
More examples showing printf style
printf('hello %s', 'world')
printf('%i %f', 10, 3.14)
#hello world10 3.140000
There are general two ways to do this:
Print without newline in Python 3.x
Append nothing after the print statement and remove '\n' by using end=''
as:
>>> print('hello')
hello # appending '\n' automatically
>>> print('world')
world # with previous '\n' world comes down
# solution is:
>>> print('hello', end='');print(' world'); # end with anything like end='-' or end=" " but not '\n'
hello world # it seem correct output
Another Example in Loop:
for i in range(1,10):
print(i, end='.')
Print without newline in Python 2.x
Adding a trailing comma says that after print ignore \n
.
>>> print "hello",; print" world"
hello world
Another Example in Loop:
for i in range(1,10):
print "{} .".format(i),
Hope this will help you. You can visit this link .
You can just add ,
in the end of print
function so it won't print on new line.
Note: The title of this question used to be something like "How to printf in python?"
Since people may come here looking for it based on the title, Python also supports printf-style substitution:
>>> strings = [ "one", "two", "three" ]
>>>
>>> for i in xrange(3):
... print "Item %d: %s" % (i, strings[i])
...
Item 0: one
Item 1: two
Item 2: three
And, you can handily multiply string values:
>>> print "." * 10
..........
...you do not need to import any library. Just use the delete character:
BS=u'\0008' # the unicode for "delete" character
for i in range(10):print(BS+"."),
this removes the newline and the space (^_^)*
Many of these answers seem a little complicated. In Python 3.x you simply do this:
print(<expr>, <expr>, ..., <expr>, end=" ")
The default value of end is "\n"
. We are simply changing it to a space or you can also use end=""
(no space) to do what printf
normally does.
Note: The title of this question used to be something like "How to printf in python?"
Since people may come here looking for it based on the title, Python also supports printf-style substitution:
>>> strings = [ "one", "two", "three" ]
>>>
>>> for i in xrange(3):
... print "Item %d: %s" % (i, strings[i])
...
Item 0: one
Item 1: two
Item 2: three
And, you can handily multiply string values:
>>> print "." * 10
..........
It should be as simple as described at this link by Guido Van Rossum:
Re: How does one print without a c/r ?
http://legacy.python.org/search/hypermail/python-1992/0115.html
Is it possible to print something but not automatically have a carriage return appended to it ?
Yes, append a comma after the last argument to print. For instance, this loop prints the numbers 0..9 on a line separated by spaces. Note the parameterless "print" that adds the final newline:
>>> for i in range(10):
... print i,
... else:
... print
...
0 1 2 3 4 5 6 7 8 9
>>>
You can try:
import sys
import time
# Keeps the initial message in buffer.
sys.stdout.write("\rfoobar bar black sheep")
sys.stdout.flush()
# Wait 2 seconds
time.sleep(2)
# Replace the message with a new one.
sys.stdout.write("\r"+'hahahahaaa ')
sys.stdout.flush()
# Finalize the new message by printing a return carriage.
sys.stdout.write('\n')
There are general two ways to do this:
Print without newline in Python 3.x
Append nothing after the print statement and remove '\n' by using end=''
as:
>>> print('hello')
hello # appending '\n' automatically
>>> print('world')
world # with previous '\n' world comes down
# solution is:
>>> print('hello', end='');print(' world'); # end with anything like end='-' or end=" " but not '\n'
hello world # it seem correct output
Another Example in Loop:
for i in range(1,10):
print(i, end='.')
Print without newline in Python 2.x
Adding a trailing comma says that after print ignore \n
.
>>> print "hello",; print" world"
hello world
Another Example in Loop:
for i in range(1,10):
print "{} .".format(i),
Hope this will help you. You can visit this link .
Many of these answers seem a little complicated. In Python 3.x you simply do this:
print(<expr>, <expr>, ..., <expr>, end=" ")
The default value of end is "\n"
. We are simply changing it to a space or you can also use end=""
(no space) to do what printf
normally does.
Note: The title of this question used to be something like "How to printf in python?"
Since people may come here looking for it based on the title, Python also supports printf-style substitution:
>>> strings = [ "one", "two", "three" ]
>>>
>>> for i in xrange(3):
... print "Item %d: %s" % (i, strings[i])
...
Item 0: one
Item 1: two
Item 2: three
And, you can handily multiply string values:
>>> print "." * 10
..........
The new (as of Python 3.x) print
function has an optional end
parameter that lets you modify the ending character:
print("HELLO", end="")
print("HELLO")
Output:
HELLOHELLO
There's also sep
for separator:
print("HELLO", "HELLO", "HELLO", sep="")
Output:
HELLOHELLOHELLO
If you wanted to use this in Python 2.x just add this at the start of your file:
from __future__ import print_function
You will notice that all the above answers are correct. But I wanted to make a shortcut to always writing the " end='' " parameter in the end.
You could define a function like
def Print(*args,sep='',end='',file=None,flush=False):
print(*args,sep=sep,end=end,file=file,flush=flush)
It would accept all the number of parameters. Even it will accept all the other parameters like file, flush ,etc and with the same name.
It should be as simple as described at this link by Guido Van Rossum:
Re: How does one print without a c/r ?
http://legacy.python.org/search/hypermail/python-1992/0115.html
Is it possible to print something but not automatically have a carriage return appended to it ?
Yes, append a comma after the last argument to print. For instance, this loop prints the numbers 0..9 on a line separated by spaces. Note the parameterless "print" that adds the final newline:
>>> for i in range(10):
... print i,
... else:
... print
...
0 1 2 3 4 5 6 7 8 9
>>>
You can do the same in python3 as follows :
#!usr/bin/python
i = 0
while i<10 :
print('.',end='')
i = i+1
and execute it with python filename.py
or python3 filename.py
You can try:
import sys
import time
# Keeps the initial message in buffer.
sys.stdout.write("\rfoobar bar black sheep")
sys.stdout.flush()
# Wait 2 seconds
time.sleep(2)
# Replace the message with a new one.
sys.stdout.write("\r"+'hahahahaaa ')
sys.stdout.flush()
# Finalize the new message by printing a return carriage.
sys.stdout.write('\n')
The new (as of Python 3.x) print
function has an optional end
parameter that lets you modify the ending character:
print("HELLO", end="")
print("HELLO")
Output:
HELLOHELLO
There's also sep
for separator:
print("HELLO", "HELLO", "HELLO", sep="")
Output:
HELLOHELLOHELLO
If you wanted to use this in Python 2.x just add this at the start of your file:
from __future__ import print_function
@lenooh satisfied my query. I discovered this article while searching for 'python suppress newline'. I'm using IDLE3 on Raspberry Pi to develop Python 3.2 for PuTTY. I wanted to create a progress bar on the PuTTY command line. I didn't want the page scrolling away. I wanted a horizontal line to re-assure the user from freaking out that the program hasn't cruncxed to a halt nor been sent to lunch on a merry infinite loop - as a plea to 'leave me be, I'm doing fine, but this may take some time.' interactive message - like a progress bar in text.
The print('Skimming for', search_string, '\b! .001', end='')
initializes the message by preparing for the next screen-write, which will print three backspaces as ??? rubout and then a period, wiping off '001' and extending the line of periods. After search_string
parrots user input, the \b!
trims the exclamation point of my search_string
text to back over the space which print()
otherwise forces, properly placing the punctuation. That's followed by a space and the first 'dot' of the 'progress bar' which I'm simulating. Unnecessarily, the message is also then primed with the page number (formatted to a length of three with leading zeros) to take notice from the user that progress is being processed and which will also reflect the count of periods we will later build out to the right.
import sys
page=1
search_string=input('Search for?',)
print('Skimming for', search_string, '\b! .001', end='')
sys.stdout.flush() # the print function with an end='' won't print unless forced
while page:
# some stuff…
# search, scrub, and build bulk output list[], count items,
# set done flag True
page=page+1 #done flag set in 'some_stuff'
sys.stdout.write('\b\b\b.'+format(page, '03')) #<-- here's the progress bar meat
sys.stdout.flush()
if done: #( flag alternative to break, exit or quit)
print('\nSorting', item_count, 'items')
page=0 # exits the 'while page' loop
list.sort()
for item_count in range(0, items)
print(list[item_count])
#print footers here
if not (len(list)==items):
print('#error_handler')
The progress bar meat is in the sys.stdout.write('\b\b\b.'+format(page, '03'))
line. First, to erase to the left, it backs up the cursor over the three numeric characters with the '\b\b\b' as ??? rubout and drops a new period to add to the progress bar length. Then it writes three digits of the page it has progressed to so far. Because sys.stdout.write()
waits for a full buffer or the output channel to close, the sys.stdout.flush()
forces the immediate write. sys.stdout.flush()
is built into the end of print()
which is bypassed with print(txt, end='' )
. Then the code loops through its mundane time intensive operations while it prints nothing more until it returns here to wipe three digits back, add a period and write three digits again, incremented.
The three digits wiped and rewritten is by no means necessary - it's just a flourish which exemplifies sys.stdout.write()
versus print()
. You could just as easily prime with a period and forget the three fancy backslash-b ? backspaces (of course not writing formatted page counts as well) by just printing the period bar longer by one each time through - without spaces or newlines using just the sys.stdout.write('.'); sys.stdout.flush()
pair.
Please note that the Raspberry Pi IDLE3 Python shell does not honor the backspace as ? rubout but instead prints a space, creating an apparent list of fractions instead.
—(o=8> wiz
Note: The title of this question used to be something like "How to printf in python?"
Since people may come here looking for it based on the title, Python also supports printf-style substitution:
>>> strings = [ "one", "two", "three" ]
>>>
>>> for i in xrange(3):
... print "Item %d: %s" % (i, strings[i])
...
Item 0: one
Item 1: two
Item 2: three
And, you can handily multiply string values:
>>> print "." * 10
..........
@lenooh satisfied my query. I discovered this article while searching for 'python suppress newline'. I'm using IDLE3 on Raspberry Pi to develop Python 3.2 for PuTTY. I wanted to create a progress bar on the PuTTY command line. I didn't want the page scrolling away. I wanted a horizontal line to re-assure the user from freaking out that the program hasn't cruncxed to a halt nor been sent to lunch on a merry infinite loop - as a plea to 'leave me be, I'm doing fine, but this may take some time.' interactive message - like a progress bar in text.
The print('Skimming for', search_string, '\b! .001', end='')
initializes the message by preparing for the next screen-write, which will print three backspaces as ??? rubout and then a period, wiping off '001' and extending the line of periods. After search_string
parrots user input, the \b!
trims the exclamation point of my search_string
text to back over the space which print()
otherwise forces, properly placing the punctuation. That's followed by a space and the first 'dot' of the 'progress bar' which I'm simulating. Unnecessarily, the message is also then primed with the page number (formatted to a length of three with leading zeros) to take notice from the user that progress is being processed and which will also reflect the count of periods we will later build out to the right.
import sys
page=1
search_string=input('Search for?',)
print('Skimming for', search_string, '\b! .001', end='')
sys.stdout.flush() # the print function with an end='' won't print unless forced
while page:
# some stuff…
# search, scrub, and build bulk output list[], count items,
# set done flag True
page=page+1 #done flag set in 'some_stuff'
sys.stdout.write('\b\b\b.'+format(page, '03')) #<-- here's the progress bar meat
sys.stdout.flush()
if done: #( flag alternative to break, exit or quit)
print('\nSorting', item_count, 'items')
page=0 # exits the 'while page' loop
list.sort()
for item_count in range(0, items)
print(list[item_count])
#print footers here
if not (len(list)==items):
print('#error_handler')
The progress bar meat is in the sys.stdout.write('\b\b\b.'+format(page, '03'))
line. First, to erase to the left, it backs up the cursor over the three numeric characters with the '\b\b\b' as ??? rubout and drops a new period to add to the progress bar length. Then it writes three digits of the page it has progressed to so far. Because sys.stdout.write()
waits for a full buffer or the output channel to close, the sys.stdout.flush()
forces the immediate write. sys.stdout.flush()
is built into the end of print()
which is bypassed with print(txt, end='' )
. Then the code loops through its mundane time intensive operations while it prints nothing more until it returns here to wipe three digits back, add a period and write three digits again, incremented.
The three digits wiped and rewritten is by no means necessary - it's just a flourish which exemplifies sys.stdout.write()
versus print()
. You could just as easily prime with a period and forget the three fancy backslash-b ? backspaces (of course not writing formatted page counts as well) by just printing the period bar longer by one each time through - without spaces or newlines using just the sys.stdout.write('.'); sys.stdout.flush()
pair.
Please note that the Raspberry Pi IDLE3 Python shell does not honor the backspace as ? rubout but instead prints a space, creating an apparent list of fractions instead.
—(o=8> wiz
python 2.6+:
from __future__ import print_function # needs to be first statement in file
print('.', end='')
python 3:
print('.', end='')
python <= 2.5:
import sys
sys.stdout.write('.')
if extra space is OK after each print, in python 2
print '.',
misleading in python 2 - avoid:
print('.'), # avoid this if you want to remain sane
# this makes it look like print is a function but it is not
# this is the `,` creating a tuple and the parentheses enclose an expression
# to see the problem, try:
print('.', 'x'), # this will print `('.', 'x') `
How to print on the same line:
import sys
for i in xrange(0,10):
sys.stdout.write(".")
sys.stdout.flush()
Using functools.partial to create a new function called printf
>>> import functools
>>> printf = functools.partial(print, end="")
>>> printf("Hello world\n")
Hello world
Easy way to wrap a function with default parameters.
How to print on the same line:
import sys
for i in xrange(0,10):
sys.stdout.write(".")
sys.stdout.flush()
Source: Stackoverflow.com