Get file name from URL

Question

In Java  given a java net URL or a String in the form of http   www example com some path to a file xml   what is the easiest way to get the file name  minus the extension  So  in this example  I m looking for something that returns  file     I can think of several ways to do this  but I m looking for something that s easy to read and short

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How about this   String filenameWithoutExtension   null  String fullname   new File      new URI  http   www xyz com some deep path to abc png   getPath    getName     int lastIndexOfDot   fullname lastIndexOf       filenameWithoutExtension   fullname substring 0       lastIndexOfDot    -1   fullname length     lastIndexOfDot

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return new File Uri parse url  getPath    getName

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This should about cut it  i ll leave the error handling to you    int slashIndex   url lastIndexOf       int dotIndex   url lastIndexOf      slashIndex   String filenameWithoutExtension  if  dotIndex    -1      filenameWithoutExtension   url substring slashIndex   1     else     filenameWithoutExtension   url substring slashIndex   1  dotIndex

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I ve found that some urls when passed directly to FilenameUtils getName return unwanted results and this needs to be wrapped up to avoid exploits  For example  System out println FilenameUtils getName  quot http   www google com    quot      returns      which I doubt anyone wants to allow  The following function seems to work fine  and shows some of these test cases  and it returns null when the filename can t be determined  public static String getFilenameFromUrl String url        if  url    null          return null           try                  Add a protocol if none found         if    url contains  quot    quot                url    quot http    quot    url           URL uri   new URL url           String result   FilenameUtils getName uri getPath              if  result    null    result isEmpty                return null           if  result contains  quot    quot                return null           return result            catch  MalformedURLException e                return null           This is wrapped up with some simple tests cases in the following example  import java util Objects  import java net URL  import org apache commons io FilenameUtils   class Main      public static void main String   args        validateFilename null  null       validateFilename  quot  quot   null       validateFilename  quot www google com    me you trex 5 sdf quot    quot you quot        validateFilename  quot www google com    me you trex 5 is the num sdf quot    quot you quot        validateFilename  quot http   www google com test png test quot    quot test png quot        validateFilename  quot http   www google com quot   null       validateFilename  quot http   www google com test quot   null       validateFilename  quot http   www google com     quot   null       validateFilename  quot www google com    quot   null       validateFilename  quot http   www google com    quot   null       validateFilename  quot http   www google com test quot    quot test quot        validateFilename  quot https   www google com       test png quot    quot test png quot        validateFilename  quot file   www google com test png quot    quot test png quot        validateFilename  quot file   www google com    me you trex 5 quot    quot you quot        validateFilename  quot file   www google com    me you trex quot    quot you quot           private static void validateFilename String url  String expectedFilename       String actualFilename   getFilenameFromUrl url        System out println  quot  quot        System out println  quot url  quot    url       System out println  quot filename  quot    expectedFilename        if    Objects equals actualFilename  expectedFilename         throw new RuntimeException  quot Problem  actual  quot    actualFilename    quot  and expected  quot    expectedFilename    quot  are not equal quot           public static String getFilenameFromUrl String url          if  url    null        return null       try                Add a protocol if none found       if    url contains  quot    quot            url    quot http    quot    url         URL uri   new URL url         String result   FilenameUtils getName uri getPath            if  result    null    result isEmpty            return null         if  result contains  quot    quot            return null         return result            catch  MalformedURLException e              return null

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andy s answer redone using split     Url u       String   pathparts  u getPath   split         String filename  pathparts pathparts length-1  split        1  0

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The Url object in urllib allows you to access the path s unescaped filename  Here are some examples   String raw    http   www example com some path to a file xml   assertEquals  file xml   Url parse raw  path   filename      raw    http   www example com files r C3 A9sum C3 A9 pdf   assertEquals  r  sum   pdf   Url parse raw  path   filename

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Get File Name with Extension  without Extension  only Extension with just 3 line   String urlStr    http   www example com yourpath foler test png    String fileName   urlStr substring urlStr lastIndexOf      1  urlStr length     String fileNameWithoutExtension   fileName substring 0  fileName lastIndexOf        String fileExtension   urlStr substring urlStr lastIndexOf         Log i  File Name   fileName   Log i  File Name Without Extension   fileNameWithoutExtension   Log i  File Extension   fileExtension     Log Result   File Name 13656   test png File Name Without Extension 13656   test File Extension 13656    png   Hope it will help you

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Keep it simple           This function will take an URL as input and return the file name      lt p gt Examples   lt  p gt      lt ul gt      lt li gt http   example com a b c test txt - gt  test txt lt  li gt      lt li gt http   example com  - gt  an empty string  lt  li gt      lt li gt http   example com test txt param value - gt  test txt lt  li gt      lt li gt http   example com test txt anchor - gt  test txt lt  li gt      lt  ul gt          param url The input URL     return The URL file name     public static String getFileNameFromUrl URL url         String urlString   url getFile         return urlString substring urlString lastIndexOf        1  split        0  split      0

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One liner   new File uri getPath  getName   Complete code  in a scala REPL    import java io File import java net URI  val uri   new URI  http   example org file txt whatever    new File uri getPath  getName res18  String   file txt   Note  URI gePath is already intelligent enough to strip off query parameters and the protocol s scheme  Examples   new URI  http   example org hey file txt whatever   getPath res20  String    hey file txt  new URI  hdfs    hey file txt   getPath res21  String    hey file txt  new URI  file    hey file txt   getPath res22  String    hey file txt

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There are some ways   Java 7 File I O   String fileName   Paths get strUrl  getFileName   toString      Apache Commons   String fileName   FilenameUtils getName strUrl     Using Jersey   UriBuilder buildURI   UriBuilder fromUri strUrl   URI uri   buildURI build    String fileName   Paths get uri getPath    getFileName      Substring   String fileName   strUrl substring strUrl lastIndexOf        1

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Beyond the all advanced methods  my simple trick is StringTokenizer   import java util ArrayList  import java util StringTokenizer   public class URLName       public static void main String args             String url    http   www example com some path to a file xml           StringTokenizer tokens   new StringTokenizer url                 ArrayList lt String gt  parts   new ArrayList lt  gt              while tokens hasMoreTokens                 parts add tokens nextToken                       String file   parts get parts size   -1           int dot   file indexOf               String fileName   file substring 0  dot           System out println fileName

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Here is the simplest way to do it in Android  I know it will not work in Java but It may help Android application developer   import android webkit URLUtil   public String getFileNameFromURL String url        String fileNameWithExtension   null      String fileNameWithoutExtension   null      if  URLUtil isValidUrl url             fileNameWithExtension   URLUtil guessFileName url  null  null           if  fileNameWithExtension    null  amp  amp   fileNameWithExtension isEmpty                  String   f   fileNameWithExtension split                   if  f    null  amp  f length  gt  1                    fileNameWithoutExtension   f 0                                     return fileNameWithoutExtension

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If you are using Spring  there is a helper to handle URIs  Here is the solution   List lt String gt  pathSegments   UriComponentsBuilder fromUriString url  build   getPathSegments    String filename   pathSegments get pathSegments size  -1

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Urls can have parameters in the end  this          Getting file name from url without extension     param url string     return file name     public static String getFileName String url        String fileName      int slashIndex   url lastIndexOf           int qIndex   url lastIndexOf           if  qIndex  gt  slashIndex     if has parameters         fileName   url substring slashIndex   1  qIndex         else           fileName   url substring slashIndex   1             if  fileName contains                 fileName   fileName substring 0  fileName lastIndexOf                   return fileName

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String fileName   url substring  url lastIndexOf      1  url length       String fileNameWithoutExtn   fileName substring 0  fileName lastIndexOf

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If you don t need to get rid of the file extension  here s a way to do it without resorting to error-prone String manipulation and without using external libraries  Works with Java 1 7    import java net URI import java nio file Paths  String url    http   example org file p foo amp q bar  String filename   Paths get new URI url  getPath    getFileName   toString

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create a new file with string image path      String imagePath      File test   new File imagePath       test getName        test getPath        getExtension test getName           public static String getExtension String uri                if  uri    null                    return null                             int dot   uri lastIndexOf                   if  dot  gt   0                    return uri substring dot                 else                      No extension                  return

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If you want to get only the filename from a java net URL  not including any query parameters   you could use the following function   public static String getFilenameFromURL URL url        return new File url getPath   toString    getName        For example  this input URL    http   example com image png version 2 amp amp modificationDate 1449846324000    Would be translated to this output String   image png

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In order to return filename without extension and without parameters use the following   String filenameWithParams   FilenameUtils getBaseName urlStr      may hold params if http   example com a param yes return filenameWithParams split        0      removing parameters from url if they exist   In order to return filename with extension without params use this       Parses a URL and extracts the filename from it or returns an empty string  if filename is non existent in the url   lt br  gt     This method will work in win unix formats  will work with mixed case of slashes  forward and backward   lt br  gt     This method will remove parameters after the extension        param urlStr original url string from which we will extract the filename     return filename from the url if it exists  or an empty string in all other cases    private String getFileNameFromUrl String urlStr        String baseName   FilenameUtils getBaseName urlStr       String extension   FilenameUtils getExtension urlStr        try           extension   extension split        0      removing parameters from url if they exist         return baseName isEmpty          baseName         extension        catch  NullPointerException npe            return

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import java io     import java net     public class ConvertURLToFileName       public static void main String   args throws IOException     BufferedReader in   new BufferedReader new InputStreamReader System in       System out print  Please enter the URL           String str   in readLine         try        URL url   new URL str         System out println  File      url getFile          System out println  Converting process Successfully               catch  MalformedURLException me          System out println  Converting process error          I hope this will help you

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I ve come up with this   String url    http   www example com some path to a file xml   String file   url substring url lastIndexOf      1  url lastIndexOf

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I have the same problem  with yours  I solved it by this   var URL   window location pathname     Gets page name var page   URL substring URL lastIndexOf        1    console info page

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Create an URL object from the String   When first you have an URL object there are methods to easily pull out just about any snippet of information you need   I can strongly recommend the Javaalmanac web site which has tons of examples  but which has since moved   You might find http   exampledepot 8waytrips com egs java io File2Uri html interesting      Create a file object File file   new File  filename        Convert the file object to a URL URL url   null  try          The file need not exist  It is made into an absolute path        by prefixing the current working directory     url   file toURL                file  d  almanac1 4 java io filename   catch  MalformedURLException e          Convert the URL to a file object file   new File url getFile         d  almanac1 4 java io filename     Read the file contents using the URL try          Open an input stream     InputStream is   url openStream            Read from is      is close      catch  IOException e           Could not open the file

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public static String getFileName URL extUrl              URL   http   photosaaaaa net photos-ak-snc1 v315 224 13 659629384 s659629384 752969 4472 jpg          String filename                 PATH   photos-ak-snc1 v315 224 13 659629384 s659629384 752969 4472 jpg         String path   extUrl getPath              Checks for both forward and or backslash            NOTE   While backslashes are not supported in URL s            most browsers will autoreplace them with forward slashes           So technically if you re parsing an html page you could run into            a backslash   so i m accounting for them here          String   pathContents   path split                     if pathContents    null               int pathContentsLength   pathContents length              System out println  Path Contents Length      pathContentsLength               for  int i   0  i  lt  pathContents length  i                      System out println  Path     i          pathContents i                                lastPart  s659629384 752969 4472 jpg             String lastPart   pathContents pathContentsLength-1               String   lastPartContents   lastPart split                     if lastPartContents    null  amp  amp  lastPartContents length  gt  1                   int lastPartContentLength   lastPartContents length                  System out println  Last Part Length      lastPartContentLength                     filenames can contain     so we assume everything before                   the last   is the name  everything after the last   is the                    extension                 String name                       for  int i   0  i  lt  lastPartContentLength  i                          System out println  Last Part     i         lastPartContents i                        if i  lt   lastPartContents length -1                            name    lastPartContents i                            if i  lt   lastPartContentLength -2                                name                                                                                           String extension   lastPartContents lastPartContentLength -1                   filename   name        extension                  System out println  Name      name                   System out println  Extension      extension                   System out println  Filename      filename                                   return filename

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String fileName   url substring url lastIndexOf        1

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public String getFileNameWithoutExtension URL url        String path   url getPath         if  StringUtils isBlank path             return null            if  StringUtils endsWith path                    is a directory            return null             File file   new File url getPath         String fileNameWithExt   file getName         int sepPosition   fileNameWithExt lastIndexOf           String fileNameWithOutExt   null      if  sepPosition  gt   0            fileNameWithOutExt   fileNameWithExt substring 0 sepPosition        else          fileNameWithOutExt   fileNameWithExt             return fileNameWithOutExt

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Instead of reinventing the wheel  how about using Apache commons-io   import org apache commons io FilenameUtils   public class FilenameUtilTest        public static void main String   args  throws Exception           URL url   new URL  http   www example com some path to a file xml foo bar test             System out println FilenameUtils getBaseName url getPath         - gt  file         System out println FilenameUtils getExtension url getPath         - gt  xml         System out println FilenameUtils getName url getPath         - gt  file xml

[java] Get file name from URL

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