As stated (or at least alluded to) in many of the wonderful answers already given, this problem is easily solved once you have a set of numbers to work with.
Note: The following is T-SQL but it's simply my particular implementation of general concepts already mentioned here and on the internet at large. It should be relatively simple to convert the code to your dialect of choice.
How? Consider this query:
SELECT DATEADD(d, N, '0001-01-22')
FROM Numbers -- A table containing the numbers 0 through N
WHERE N <= 5;
The above produces the date range 1/22/0001 - 1/27/0001 and is extremely trivial. There are 2 key pieces of information in the above query: the start date of 0001-01-22 and the offset of 5. If we combine these two pieces of information then we obviously have our end date. Thus, given two dates, generating a range can be broken down like so:
Find the difference between two given dates (the offset), easy:
-- Returns 125
SELECT ABS(DATEDIFF(d, '2014-08-22', '2014-12-25'))
Using ABS() here ensures that the date order is irrelevant.
Generate a limited set of numbers, also easy:
-- Returns the numbers 0-2
SELECT N = ROW_NUMBER() OVER(ORDER BY (SELECT NULL)) - 1
FROM(SELECT 'A' AS S UNION ALL SELECT 'A' UNION ALL SELECT 'A')
Notice we don't actually care what we're selecting FROM here. We just need a set to work with so that we count the number of rows in it. I personally use a TVF, some use a CTE, others use a numbers table instead, you get the idea. I advocate for using the most performant solution that you also understand.
Combining these two methods will solve our problem:
DECLARE @date1 DATE = '9001-11-21';
DECLARE @date2 DATE = '9001-11-23';
SELECT D = DATEADD(d, N, @date1)
FROM (
SELECT N = ROW_NUMBER() OVER(ORDER BY (SELECT NULL)) - 1
FROM (SELECT 'A' AS S UNION ALL SELECT 'A' UNION ALL SELECT 'A') S
) Numbers
WHERE N <= ABS(DATEDIFF(d, @date1, @date2));
The above example is horrible code but demonstrates how everything comes together.
More Fun
I need to do this kind of thing a lot so I encapsulated the logic into two TVFs. The first generates a range of numbers and the second uses this functionality to generate a range of dates. The math is to ensure that input order doesn't matter and because I wanted to use the full range of numbers available in GenerateRangeSmallInt.
The following function takes ~16ms of CPU time to return the maximum range of 65536 dates.
CREATE FUNCTION dbo.GenerateRangeDate (
@date1 DATE,
@date2 DATE
)
RETURNS TABLE
WITH SCHEMABINDING
AS
RETURN (
SELECT D = DATEADD(d, N + 32768, CASE WHEN @date1 <= @date2 THEN @date1 ELSE @date2 END)
FROM dbo.GenerateRangeSmallInt(-32768, ABS(DATEDIFF(d, @date1, @date2)) - 32768)
);
GO
CREATE FUNCTION dbo.GenerateRangeSmallInt (
@num1 SMALLINT = -32768
, @num2 SMALLINT = 32767
)
RETURNS TABLE
WITH SCHEMABINDING
AS
RETURN (
WITH Numbers(N) AS (
SELECT N FROM(VALUES
(1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1) -- 16
, (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1) -- 32
, (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1) -- 48
, (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1) -- 64
, (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1) -- 80
, (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1) -- 96
, (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1) -- 112
, (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1) -- 128
, (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1) -- 144
, (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1) -- 160
, (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1) -- 176
, (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1) -- 192
, (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1) -- 208
, (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1) -- 224
, (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1) -- 240
, (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1), (1) -- 256
) V (N)
)
SELECT TOP(ABS(CAST(@num1 AS INT) - CAST(@num2 AS INT)) + 1)
N = ROW_NUMBER() OVER(ORDER BY (SELECT NULL)) + CASE WHEN @num1 <= @num2 THEN @num1 ELSE @num2 END - 1
FROM Numbers A
, Numbers B
);
if you will ever need more then a couple days, you need a table.
then,
select from days.day, count(mytable.field) as fields from days left join mytable on day=date where date between x and y;
You'd like to get the a date range.
In your example you'd like to get the dates between '2010-01-20' and '2010-01-24'
possible solution:
select date_add('2010-01-20', interval row day) from
(
SELECT @row := @row + 1 as row FROM
(select 0 union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 6 union all select 7 union all select 8 union all select 9) t,
(select 0 union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 6 union all select 7 union all select 8 union all select 9) t2,
(select 0 union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 6 union all select 7 union all select 8 union all select 9) t3,
(select 0 union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 6 union all select 7 union all select 8 union all select 9) t4,
(SELECT @row:=-1) r
) sequence
where date_add('2010-01-20', interval row day) <= '2010-01-24'
Explanation
MySQL has a date_add function so
select date_add('2010-01-20', interval 1 day)
will give you
2010-01-21
The datediff function would let you know often you'd have to repeat this
select datediff('2010-01-24', '2010-01-20')
which returns
4
Getting a list of dates in a date range boils down to creating a sequence of integer numbers see generate an integer sequence in MySQL
The most upvoted answer here has taken a similar approach as https://stackoverflow.com/a/2652051/1497139 as a basis:
SELECT @row := @row + 1 as row FROM
(select 0 union all select 1 union all select 3 union all select 4 union all select 5 union all select 6 union all select 6 union all select 7 union all select 8 union all select 9) t,
(select 0 union all select 1 union all select 3 union all select 4 union all select 5 union all select 6 union all select 6 union all select 7 union all select 8 union all select 9) t2,
(select 0 union all select 1 union all select 3 union all select 4 union all select 5 union all select 6 union all select 6 union all select 7 union all select 8 union all select 9) t3,
(select 0 union all select 1 union all select 3 union all select 4 union all select 5 union all select 6 union all select 6 union all select 7 union all select 8 union all select 9) t4,
(SELECT @row:=0) r
limit 4
which will result in
row
1.0
2.0
3.0
4.0
The rows can now be used to create a list of dates from the given start date. To include the start date we start with row -1;
select date_add('2010-01-20', interval row day) from
(
SELECT @row := @row + 1 as row FROM
(select 0 union all select 1 union all select 3 union all select 4 union all select 5 union all select 6 union all select 6 union all select 7 union all select 8 union all select 9) t,
(select 0 union all select 1 union all select 3 union all select 4 union all select 5 union all select 6 union all select 6 union all select 7 union all select 8 union all select 9) t2,
(select 0 union all select 1 union all select 3 union all select 4 union all select 5 union all select 6 union all select 6 union all select 7 union all select 8 union all select 9) t3,
(select 0 union all select 1 union all select 3 union all select 4 union all select 5 union all select 6 union all select 6 union all select 7 union all select 8 union all select 9) t4,
(SELECT @row:=-1) r
) sequence
where date_add('2010-01-20', interval row day) <= '2010-01-24'
The old school solution for doing this without a loop/cursor is to create a NUMBERS table, which has a single Integer column with values starting at 1.
CREATE TABLE `example`.`numbers` (
`id` int(10) unsigned NOT NULL auto_increment,
PRIMARY KEY (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1;
You need to populate the table with enough records to cover your needs:
INSERT INTO NUMBERS (id) VALUES (NULL);
Once you have the NUMBERS table, you can use:
SELECT x.start_date + INTERVAL n.id-1 DAY
FROM NUMBERS n
JOIN (SELECT STR_TO_DATE('2010-01-20', '%Y-%m-%d') AS start_date
FROM DUAL) x
WHERE x.start_date + INTERVAL n.id-1 DAY <= '2010-01-24'
The absolute low-tech solution would be:
SELECT STR_TO_DATE('2010-01-20', '%Y-%m-%d')
FROM DUAL
UNION ALL
SELECT STR_TO_DATE('2010-01-21', '%Y-%m-%d')
FROM DUAL
UNION ALL
SELECT STR_TO_DATE('2010-01-22', '%Y-%m-%d')
FROM DUAL
UNION ALL
SELECT STR_TO_DATE('2010-01-23', '%Y-%m-%d')
FROM DUAL
UNION ALL
SELECT STR_TO_DATE('2010-01-24', '%Y-%m-%d')
FROM DUAL
To generate lists of dates or numbers in order to LEFT JOIN on to. You would to this in order to see where there are gaps in the data, because you are LEFT JOINing onto a list of sequencial data - null values will make it obvious where gaps exist.
improved with weekday an joining a custom holiday table microsoft MSSQL 2012 for powerpivot date table https://gist.github.com/josy1024/cb1487d66d9e0ccbd420bc4a23b6e90e
with [dates] as (
select convert(datetime, '2016-01-01') as [date] --start
union all
select dateadd(day, 1, [date])
from [dates]
where [date] < '2018-01-01' --end
)
select [date]
, DATEPART (dw,[date]) as Wochentag
, (select holidayname from holidaytable
where holidaytable.hdate = [date])
as Feiertag
from [dates]
where [date] between '2016-01-01' and '2016-31-12'
option (maxrecursion 0)
For Access 2010 - multiple steps required; I followed the same pattern as posted above, but thought I could help someone in Access. Worked great for me, I didn't have to keep a seeded table of dates.
Create a table called DUAL (similar to how the Oracle DUAL table works)
Create a query named "ZeroThru9Q"; manually enter the following syntax:
SELECT 0 AS a
FROM dual
UNION ALL
SELECT 1
FROM dual
UNION ALL
SELECT 2
FROM dual
UNION ALL
SELECT 3
FROM dual
UNION ALL
SELECT 4
FROM dual
UNION ALL
SELECT 5
FROM dual
UNION ALL
SELECT 6
FROM dual
UNION ALL
SELECT 7
FROM dual
UNION ALL
SELECT 8
FROM dual
UNION ALL
SELECT 9
FROM dual;
Create a query named "TodayMinus1KQ" (for dates before today); manually enter the following syntax:
SELECT date() - (a.a + (10 * b.a) + (100 * c.a)) AS MyDate
FROM
(SELECT *
FROM ZeroThru9Q) AS a,
(SELECT *
FROM ZeroThru9Q) AS b,
(SELECT *
FROM ZeroThru9Q) AS c
Create a query named "TodayPlus1KQ" (for dates after today); manually enter the following syntax:
SELECT date() + (a.a + (10 * b.a) + (100 * c.a)) AS MyDate
FROM
(SELECT *
FROM ZeroThru9Q) AS a,
(SELECT *
FROM ZeroThru9Q) AS b,
(SELECT *
FROM ZeroThru9Q) AS c;
Create a union query named "TodayPlusMinus1KQ" (for dates +/- 1000 days):
SELECT MyDate
FROM TodayMinus1KQ
UNION
SELECT MyDate
FROM TodayPlus1KQ;
Now you can use the query:
SELECT MyDate
FROM TodayPlusMinus1KQ
WHERE MyDate BETWEEN #05/01/2014# and #05/30/2014#
WITH
Digits AS (SELECT 0 D UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9),
Dates AS (SELECT adddate('1970-01-01',t4.d*10000 + t3.d*1000 + t2.d*100 + t1.d*10 +t0.d) AS date FROM Digits AS t0, Digits AS t1, Digits AS t2, Digits AS t3, Digits AS t4)
SELECT * FROM Dates WHERE date BETWEEN '2017-01-01' AND '2017-12-31'
Shorter than accepted answer, same idea:
(SELECT TRIM('2016-01-05' + INTERVAL a + b DAY) date
FROM
(SELECT 0 a UNION SELECT 1 a UNION SELECT 2 UNION SELECT 3
UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7
UNION SELECT 8 UNION SELECT 9 ) d,
(SELECT 0 b UNION SELECT 10 UNION SELECT 20
UNION SELECT 30 UNION SELECT 40) m
WHERE '2016-01-05' + INTERVAL a + b DAY <= '2016-01-21')
One more solution for mysql 8.0.1 and mariadb 10.2.2 using recursive common table expressions:
with recursive dates as (
select '2010-01-20' as date
union all
select date + interval 1 day from dates where date < '2010-01-24'
)
select * from dates;
Elegant solution using new recursive (Common Table Expressions) functionality in MariaDB >= 10.3 and MySQL >= 8.0.
WITH RECURSIVE t as (
select '2019-01-01' as dt
UNION
SELECT DATE_ADD(t.dt, INTERVAL 1 DAY) FROM t WHERE DATE_ADD(t.dt, INTERVAL 1 DAY) <= '2019-04-30'
)
select * FROM t;
The above returns a table of dates between '2019-01-01' and '2019-04-30'. It is also decently fast. Returning 1000 years worth of dates (~365,000 days) takes about 400ms on my machine.
set language 'SPANISH'
DECLARE @table table(fechaDesde datetime , fechaHasta datetime )
INSERT @table VALUES('20151231' , '20161231');
WITH x AS
(
SELECT DATEADD( m , 1 ,fechaDesde ) as fecha FROM @table
UNION ALL
SELECT DATEADD( m , 1 ,fecha )
FROM @table t INNER JOIN x ON DATEADD( m , 1 ,x.fecha ) <= t.fechaHasta
)
SELECT LEFT( CONVERT( VARCHAR, fecha , 112 ) , 6 ) as Periodo_Id
,DATEPART ( dd, DATEADD(dd,-(DAY(fecha)-1),fecha)) Num_Dia_Inicio
,DATEADD(dd,-(DAY(fecha)-1),fecha) Fecha_Inicio
,DATEPART ( mm , fecha ) Mes_Id
,DATEPART ( yy , fecha ) Anio
,DATEPART ( dd, DATEADD(dd,-(DAY(DATEADD(mm,1,fecha))),DATEADD(mm,1,fecha))) Num_Dia_Fin
,DATEADD(dd,-(DAY(DATEADD(mm,1,fecha))),DATEADD(mm,1,fecha)) ultimoDia
,datename(MONTH, fecha) mes
,'Q' + convert(varchar(10), DATEPART(QUARTER, fecha)) Trimestre_Name
FROM x
OPTION(MAXRECURSION 0)
SQLite version of RedFilters top solution
select d.Date
from (
select
date(julianday('2010-01-20') + (a.a + (10 * b.a) + (100 * c.a))) as Date
from (select 0 as a union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) as a
cross join (select 0 as a union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) as b
cross join (select 0 as a union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) as c
) d
where
d.Date between '2010-01-20' and '2010-01-24'
order by d.Date
if you want the list of dates between two dates:
create table #dates ([date] smalldatetime)
while @since < @to
begin
insert into #dates(dateadd(day,1,@since))
set @since = dateadd(day,1,@since)
end
select [date] from #dates
*fiddle here: http://sqlfiddle.com/#!6/9eecb/3469
It's a good idea with generating these dates on the fly. However, I do not feel myself comfortable to do this with quite large range so I've ended up with the following solution:
CREATE TABLE DatesNumbers (
i MEDIUMINT NOT NULL,
PRIMARY KEY (i)
)
COMMENT='Used by Dates view'
;
INSERT INTO DatesNumbers
SELECT
a.i + (10 * b.i) + (100 * c.i) + (1000 * d.i) + (10000 * e.i) - 59999 AS i
FROM
(SELECT 0 AS i UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) AS a,
(SELECT 0 AS i UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) AS b,
(SELECT 0 AS i UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) AS c,
(SELECT 0 AS i UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) AS d,
(SELECT 0 AS i UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) AS e
;
SELECT
i,
CURRENT_DATE() + INTERVAL i DAY AS Date
FROM
DatesNumbers
That's it.
WHERE i < 0 or WHERE i > 0 (PK)thx Pentium10 - you made me join stackoverflow :) - this is my porting to msaccess - think it'll work on any version:
SELECT date_value
FROM (SELECT a.espr1+(10*b.espr1)+(100*c.espr1) AS integer_value,
dateadd("d",integer_value,dateserial([start_year], [start_month], [start_day])) as date_value
FROM (select * from
(
select top 1 "0" as espr1 from MSysObjects
union all
select top 1 "1" as espr2 from MSysObjects
union all
select top 1 "2" as espr3 from MSysObjects
union all
select top 1 "3" as espr4 from MSysObjects
union all
select top 1 "4" as espr5 from MSysObjects
union all
select top 1 "5" as espr6 from MSysObjects
union all
select top 1 "6" as espr7 from MSysObjects
union all
select top 1 "7" as espr8 from MSysObjects
union all
select top 1 "8" as espr9 from MSysObjects
union all
select top 1 "9" as espr9 from MSysObjects
) as a,
(
select top 1 "0" as espr1 from MSysObjects
union all
select top 1 "1" as espr2 from MSysObjects
union all
select top 1 "2" as espr3 from MSysObjects
union all
select top 1 "3" as espr4 from MSysObjects
union all
select top 1 "4" as espr5 from MSysObjects
union all
select top 1 "5" as espr6 from MSysObjects
union all
select top 1 "6" as espr7 from MSysObjects
union all
select top 1 "7" as espr8 from MSysObjects
union all
select top 1 "8" as espr9 from MSysObjects
union all
select top 1 "9" as espr9 from MSysObjects
) as b,
(
select top 1 "0" as espr1 from MSysObjects
union all
select top 1 "1" as espr2 from MSysObjects
union all
select top 1 "2" as espr3 from MSysObjects
union all
select top 1 "3" as espr4 from MSysObjects
union all
select top 1 "4" as espr5 from MSysObjects
union all
select top 1 "5" as espr6 from MSysObjects
union all
select top 1 "6" as espr7 from MSysObjects
union all
select top 1 "7" as espr8 from MSysObjects
union all
select top 1 "8" as espr9 from MSysObjects
union all
select top 1 "9" as espr9 from MSysObjects
) as c
) as d)
WHERE date_value
between dateserial([start_year], [start_month], [start_day])
and dateserial([end_year], [end_month], [end_day]);
referenced MSysObjects just 'cause access need a table countin' at least 1 record, in a from clause - any table with at least 1 record would do.
Alright.. Try this:
http://www.devshed.com/c/a/MySQL/Delving-Deeper-into-MySQL-50/
http://dev.mysql.com/doc/refman/5.0/en/loop-statement.html
http://www.roseindia.net/sql/mysql-example/mysql-loop.shtml
Use that to, say, generate a temp table, and then do a select * on the temp table. Or output the results one at a time.
What you say you want to do can't be done with a SELECT statement, but it might be doable with things specific to MySQL.
Then again, maybe you need cursors: http://dev.mysql.com/doc/refman/5.0/en/cursors.html
Accepted answer didn't work for PostgreSQL (syntax error at or near "a").
The way you do this in PostgreSQL is by using generate_series function, i.e.:
SELECT day::date
FROM generate_series('2010-01-20', '2010-01-24', INTERVAL '1 day') day;
day
------------
2010-01-20
2010-01-21
2010-01-22
2010-01-23
2010-01-24
(5 rows)
Procedure + temporary table:
DELIMITER $$
CREATE DEFINER=`root`@`localhost` PROCEDURE `days`(IN dateStart DATE, IN dateEnd DATE)
BEGIN
CREATE TEMPORARY TABLE IF NOT EXISTS date_range (day DATE);
WHILE dateStart <= dateEnd DO
INSERT INTO date_range VALUES (dateStart);
SET dateStart = DATE_ADD(dateStart, INTERVAL 1 DAY);
END WHILE;
SELECT * FROM date_range;
DROP TEMPORARY TABLE IF EXISTS date_range;
END
A more generic answer that works in AWS MySQL.
select datetable.Date
from (
select date_format(adddate(now(),-(a.a + (10 * b.a) + (100 * c.a))),'%Y-%m-%d') AS Date
from (select 0 as a union all select 1 union all select 2 union all select 3 union all select 4
union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) as a
cross join (select 0 as a union all select 1 union all select 2 union all select 3 union all select 4
union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) as b
cross join (select 0 as a union all select 1 union all select 2 union all select 3 union all select 4
union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) as c
) datetable
where datetable.Date between now() - INTERVAL 14 Day and Now()
order by datetable.Date DESC
For anyone who wants this as a saved view (MySQL doesn't support nested select statements in views):
create view zero_to_nine as
select 0 as n union all
select 1 union all
select 2 union all
select 3 union all
select 4 union all
select 5 union all
select 6 union all
select 7 union all
select 8 union all
select 9;
create view date_range as
select curdate() - INTERVAL (a.n + (10 * b.n) + (100 * c.n)) DAY as date
from zero_to_nine as a
cross join zero_to_nine as b
cross join zero_to_nine as c;
You can then do
select * from date_range
to get
date
---
2017-06-06
2017-06-05
2017-06-04
2017-06-03
2017-06-02
...
For Oracle, my solution is:
select trunc(sysdate-dayincrement, 'DD')
from dual, (select level as dayincrement
from dual connect by level <= 30)
Sysdate can be changed to specific date and level number can be changed to give more dates.
DELIMITER $$
CREATE PROCEDURE GenerateRangeDates(IN dateStart DATE, IN dateEnd DATE)
BEGIN
CREATE TEMPORARY TABLE IF NOT EXISTS dates (day DATE);
loopDate: LOOP
INSERT INTO dates(day) VALUES (dateStart);
SET dateStart = DATE_ADD(dateStart, INTERVAL 1 DAY);
IF dateStart <= dateEnd
THEN ITERATE loopDate;
ELSE LEAVE loopDate;
END IF;
END LOOP loopDate;
SELECT day FROM dates;
DROP TEMPORARY TABLE IF EXISTS dates;
END
$$
-- Call procedure
call GenerateRangeDates(
now() - INTERVAL 40 DAY,
now()
);
Can create a procedure also to create calendar table with timestmap different from day. If you want a table for each quarter
e.g.
2019-01-22 08:45:00
2019-01-22 09:00:00
2019-01-22 09:15:00
2019-01-22 09:30:00
2019-01-22 09:45:00
2019-01-22 10:00:00
you can use
CREATE DEFINER=`root`@`localhost` PROCEDURE `generate_calendar_table`()
BEGIN
select unix_timestamp('2014-01-01 00:00:00') into @startts;
select unix_timestamp('2025-01-01 00:00:00') into @endts;
if ( @startts < @endts ) then
DROP TEMPORARY TABLE IF EXISTS calendar_table_tmp;
CREATE TEMPORARY TABLE calendar_table_tmp (ts int, dt datetime);
WHILE ( @startts < @endts)
DO
SET @startts = @startts + 900;
INSERT calendar_table_tmp VALUES (@startts, from_unixtime(@startts));
END WHILE;
END if;
END
and then manipulate through
select ts, dt from calendar_table_tmp;
that give you also ts
'1548143100', '2019-01-22 08:45:00'
'1548144000', '2019-01-22 09:00:00'
'1548144900', '2019-01-22 09:15:00'
'1548145800', '2019-01-22 09:30:00'
'1548146700', '2019-01-22 09:45:00'
'1548147600', '2019-01-22 10:00:00'
from here you can start to add other information such as
select ts, dt, weekday(dt) as wd from calendar_table_tmp;
or create a real table with create table statement
Here is another variation using views:
CREATE VIEW digits AS
SELECT 0 AS digit UNION ALL
SELECT 1 UNION ALL
SELECT 2 UNION ALL
SELECT 3 UNION ALL
SELECT 4 UNION ALL
SELECT 5 UNION ALL
SELECT 6 UNION ALL
SELECT 7 UNION ALL
SELECT 8 UNION ALL
SELECT 9;
CREATE VIEW numbers AS
SELECT
ones.digit + tens.digit * 10 + hundreds.digit * 100 + thousands.digit * 1000 AS number
FROM
digits as ones,
digits as tens,
digits as hundreds,
digits as thousands;
CREATE VIEW dates AS
SELECT
SUBDATE(CURRENT_DATE(), number) AS date
FROM
numbers;
And then you can simply do (see how elegant it is?):
SELECT
date
FROM
dates
WHERE
date BETWEEN '2010-01-20' AND '2010-01-24'
ORDER BY
date
Update
It is worth noting that you will only be able to generate past dates starting from the current date. If you want to generate any kind of dates range (past, future, and in between), you will have to use this view instead:
CREATE VIEW dates AS
SELECT
SUBDATE(CURRENT_DATE(), number) AS date
FROM
numbers
UNION ALL
SELECT
ADDDATE(CURRENT_DATE(), number + 1) AS date
FROM
numbers;
try this.
SELECT TO_DATE('20160210','yyyymmdd') - 1 + LEVEL AS start_day
from DUAL
connect by level <= (TO_DATE('20160228','yyyymmdd') + 1) - TO_DATE('20160210','yyyymmdd') ;
MSSQL Query
select datetable.Date
from (
select DATEADD(day,-(a.a + (10 * b.a) + (100 * c.a)),getdate()) AS Date
from (select 0 as a union all select 1 union all select 2 union all select 3 union all select 4
union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) as a
cross join (select 0 as a union all select 1 union all select 2 union all select 3 union all select 4
union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) as b
cross join (select 0 as a union all select 1 union all select 2 union all select 3 union all select 4
union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) as c
) datetable
where datetable.Date between '2014-01-20' and '2014-01-24'
order by datetable.Date DESC
Output
Date
-----
2014-01-23 12:35:25.250
2014-01-22 12:35:25.250
2014-01-21 12:35:25.250
2014-01-20 12:35:25.250
Here is example
We have dates in one table
Table Name: “testdate”
STARTDATE ENDDATE
10/24/2012 10/24/2012
10/27/2012 10/29/2012
10/30/2012 10/30/2012
Require Result:
STARTDATE
10/24/2012
10/27/2012
10/28/2012
10/29/2012
10/30/2012
Solution:
WITH CTE AS
(SELECT DISTINCT convert(varchar(10),StartTime, 101) AS StartTime,
datediff(dd,StartTime, endTime) AS diff
FROM dbo.testdate
UNION ALL SELECT StartTime,
diff - 1 AS diff
FROM CTE
WHERE diff<> 0)
SELECT DISTINCT DateAdd(dd,diff, StartTime) AS StartTime
FROM CTE
Explanation: CTE Recursive query explanation
First part of query:
SELECT DISTINCT convert(varchar(10), StartTime, 101) AS StartTime, datediff(dd, StartTime, endTime) AS diff FROM dbo.testdate
Explanation: firstcolumn is “startdate”, second column is difference of start and end
date in days and it will be consider as “diff” column
Second part of query:
UNION ALL SELECT StartTime, diff-1 AS diff FROM CTE WHERE diff<>0
Explanation: Union all will inherit result of above query until result goes null,
So “StartTime” result is inherit from generated CTE query, and from diff, decrease - 1, so its looks like 3, 2, and 1 until 0
For example
STARTDATE DIFF
10/24/2012 0
10/27/2012 0
10/27/2012 1
10/27/2012 2
10/30/2012 0
Result Specification
STARTDATE Specification
10/24/2012 --> From Record 1
10/27/2012 --> From Record 2
10/27/2012 --> From Record 2
10/27/2012 --> From Record 2
10/30/2012 --> From Record 3
3rd Part of Query
SELECT DISTINCT DateAdd(dd,diff, StartTime) AS StartTime FROM CTE
It will add day “diff” in “startdate” so result should be as below
Result
STARTDATE
10/24/2012
10/27/2012
10/28/2012
10/29/2012
10/30/2012
Using a recursive Common Table Expression (CTE), you can generate a list of dates, then select from it. Obviously you normally wouldn't want to create three million dates, so this just illustrates the possibilities. You could simply limit the date range inside the CTE and omit the where clause from the select statement using the CTE.
with [dates] as (
select convert(datetime, '1753-01-01') as [date] --start
union all
select dateadd(day, 1, [date])
from [dates]
where [date] < '9999-12-31' --end
)
select [date]
from [dates]
where [date] between '2013-01-01' and '2013-12-31'
option (maxrecursion 0)
On Microsoft SQL Server 2005, generating the CTE list of all possible dates took 1:08. Generating one hundred years took less than a second.
Source: Stackoverflow.com