How do you round UP a number in Python

Question

This problem is killing me  How does one roundup a number UP in Python   I tried round number  but it round the number down  Example   round 2 3    2 0 and not 3  what I would like   The I tried int number    5  but it round the number down again  Example   int 2 3    5    2   Then I tried round number    5  but it won t work in edge cases  Example   WAIT  THIS WORKED    Please advise

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The above answers are correct  however  importing the math module just for this one function usually feels like a bit of an overkill for me  Luckily  there is another way to do it   g   7 5 g   int g     not g is integer      True and False are interpreted as 1 and 0 in a statement involving numbers in python  g is interger   basically translates to g has no decimal   or g    int g   So the last statement in English reads round g down and add one if g has decimal

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I m surprised I haven t seen this answer yet round x   0 4999   so I m going to put it down  Note that this works with any Python version  Changes made to the Python rounding scheme has made things difficult  See this post   Without importing  I use   def roundUp num       return round num   0 49   testCases   list x 0 1 for x in range 0  50    print testCases  for test in testCases      print    5 2f   - gt    5 2f   format test  roundUp test      Why this works  From the docs     For the built-in types supporting round    values are rounded to the closest multiple of 10 to the power minus n  if two multiples are equally close  rounding is done toward the even choice   Therefore 2 5 gets rounded to 2 and 3 5 gets rounded to 4  If this was not the case then rounding up could be done by adding 0 5  but we want to avoid getting to the halfway point  So  if you add 0 4999 you will get close  but with enough margin to be rounded to what you would normally expect  Of course  this will fail if the x   0 4999 is equal to  n  5000  but that is unlikely

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Without importing math    using basic envionment   a  method   class method  def ceil fl      return int fl     1 if fl-int fl  else 0   def ceil self  fl      return int fl     1 if fl-int fl  else 0    b  lambda   ceil   lambda fl int fl   1 if fl-int fl  else 0

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If working with integers  one way of rounding up is to take advantage of the fact that    rounds down  Just do the division on the negative number  then negate the answer   No import  floating point  or conditional needed   rounded up   - -numerator    denominator    For example    gt  gt  gt  print - -101    5   21

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I know this answer is for a question from a while back  but if you don t want to import math and you just want to round up  this works for me    gt  gt  gt  int 21   5  4  gt  gt  gt  int 21   5     21   5  gt  0  5   The first part becomes 4 and the second part evaluates to  True  if there is a remainder  which in addition True   1  False   0  So if there is no remainder  then it stays the same integer  but if there is a remainder it adds 1

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To do it without any import    gt  gt  gt  round up   lambda num  int num   1  if int num     num else int num   gt  gt  gt  round up 2 0  2  gt  gt  gt  round up 2 1  3

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The syntax may not be as pythonic as one might like  but it is a powerful library   https   docs python org 2 library decimal html  from decimal import   print int Decimal 2 3  quantize Decimal  1     rounding ROUND UP

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Try this   a   211 0 print int a      int a  - a     0

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For those who doesn t want to use import  For a given list or any number  x    2  2 1  2 5  3  3 1  3 5  2 499 2 4999999999  3 4999999 3 99999999999   You must first evaluate if the number is equal to its integer  which always rounds down  If the result is True  you return the number  if is not  return the integer number    1  w   lambda x  x if x    int x  else int x  1  w i  for i in z   gt  gt  gt   2  3  3  3  4  4  3  3  4  4   Math logic   If the number has decimal part  round up - round down    1  always  If the number doens t have decimal part  round up - round down    0   So   round up    x   round down  With   x    1 if number    round down x    0 if number    round down  You are cutting the number in 2 parts  the integer and decimal  If decimal isn t 0  you add 1  PS I explained this in details since some comments above asked for that and I m still noob here  so I can t comment

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I know this is from quite a while back  but I found a quite interesting answer  so here goes   -round -x-0 5    This fixes the edges cases and works for both positive and negative numbers  and doesn t require any function import  Cheers

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The ceil  ceiling  function   import math print math ceil 4 2

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Interesting Python 2 x issue to keep in mind    gt  gt  gt  import math  gt  gt  gt  math ceil 4500 1000  4 0  gt  gt  gt  math ceil 4500 1000 0  5 0   The problem is that dividing two ints in python produces another int and that s truncated before the ceiling call  You have to make one value a float  or cast  to get a correct result   In javascript  the exact same code produces a different result   console log Math ceil 4500 1000    5

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Be shure rounded value should be float   a   8  b   21 print math ceil a   b   gt  gt  gt  0   but  print math ceil float a    b   gt  gt  gt  1 0

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gt  gt  gt  def roundup number           return round number  5   gt  gt  gt  roundup 2 3  3  gt  gt  gt  roundup 19 00000000001  20   This function requires no modules

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I am surprised nobody suggested   numerator   denominator - 1     denominator   for integer division with rounding up  Used to be the common way for C C   CUDA  cf  divup

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Use math ceil to round up    gt  gt  gt  import math  gt  gt  gt  math ceil 5 4  6 0   NOTE  The input should be float   If you need an integer  call int to convert it    gt  gt  gt  int math ceil 5 4   6   BTW  use math floor to round down and round to round to nearest integer    gt  gt  gt  math floor 4 4   math floor 4 5   math floor 5 4   math floor 5 5   4 0  4 0  5 0  5 0   gt  gt  gt  round 4 4   round 4 5   round 5 4   round 5 5   4 0  5 0  5 0  6 0   gt  gt  gt  math ceil 4 4   math ceil 4 5   math ceil 5 4   math ceil 5 5   5 0  5 0  6 0  6 0

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My share  I have tested  print - -101    5     21 given example above   Now for rounding  up    101   19    19 19   I can not use    so I spread the multiply to division    - -101    1 0 19      20

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If you don t want to import anything  you can always write your own simple function as  def RoundUP num       if num   int num           return num     return int num   1

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For those who want to round up a   b and get integer   Another variant using integer division is  def int ceil a  b       return  a - 1     b   1   gt  gt  gt  int ceil 19  5  4  gt  gt  gt  int ceil 20  5  4  gt  gt  gt  int ceil 21  5  5

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I m basically a beginner at Python  but if you re just trying to round up instead of down why not do   round integer    1

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You could use rond cost per person   round 150   2  2

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when you operate 4500 1000 in python  result will be 4  because for default python asume as integer the result  logically  4500 1000   4 5  --   int 4 5    4 and ceil of 4 obviouslly is 4  using 4500 1000 0 the result will be 4 5 and ceil of 4 5 --  5  Using javascript you will recieve 4 5 as result of 4500 1000  because javascript asume only the result as  numeric type  and return a result directly as float  Good Luck

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You might also like numpy    gt  gt  gt  import numpy as np  gt  gt  gt  np ceil 2 3  3 0   I m not saying it s better than math  but if you were already using numpy for other purposes  you can keep your code consistent    Anyway  just a detail I came across  I use numpy a lot and was surprised it didn t get mentioned  but of course the accepted answer works perfectly fine

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I think you are confusing the working mechanisms between int   and round     int   always truncates the decimal numbers if a floating number is given  whereas round    in case of 2 5 where 2 and 3 are both within equal distance from 2 5  Python returns whichever that is more away from the 0 point    round 2 5    3 int 2 5    2

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You can use floor devision and add 1 to it  2 3    2   1

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In case anyone is looking to round up to a specific decimal place   import math def round up n  decimals 0       multiplier   10    decimals     return math ceil n   multiplier    multiplier

[python] How do you round UP a number in Python?

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