[arrays] How to declare and use 1D and 2D byte arrays in Verilog?

It is simple actually, like C programming you just need to pass the array indices on the right hand side while declaration. But yeah the syntax will be like [0:3] for 4 elements.

reg a[0:3]; 

This will create a 1D of array of single bit. Similarly 2D array can be created like this:

reg [0:3][0:2];

Now in C suppose you create a 2D array of int, then it will internally create a 2D array of 32 bits. But unfortunately Verilog is an HDL, so it thinks in bits rather then bunch of bits (though int datatype is there in Verilog), it can allow you to create any number of bits to be stored inside an element of array (which is not the case with C, you can't store 5-bits in every element of 2D array in C). So to create a 2D array, in which every individual element can hold 5 bit value, you should write this:

reg [0:4] a [0:3][0:2];