operator in verilog

Question

i have a verilog code in which there is a line as follows:

parameter ADDR_WIDTH = 8 ;
parameter RAM_DEPTH = 1 << ADDR_WIDTH;

here what will be stored in RAM_DEPTH and what does the << operator do here.

User · Answer

lt  lt  is the left-shift operator  as it is in many other languages    Here RAM DEPTH will be 1 left-shifted by 8 bits  which is equivalent to 2 8  or 256

User · Answer

lt  lt  is a binary shift  shifting 1 to the left 8 places   4 b0001  lt  lt  1   gt  4 b0010    gt  gt  is a binary right shift adding 0 s to the MSB   gt  gt  gt  is a signed shift which maintains the value of the MSB if the left input is signed   4 sb1011  gt  gt   1   gt  0101 4 sb1011  gt  gt  gt  1   gt  1101   Three ways to indicate left operand is signed   module shift    logic         3 0  test1   4 b1000    logic signed  3 0  test2   4 b1000     initial begin      display   b    signed test1   gt  gt  gt  1      Explicitly set as signed      display   b   test2           gt  gt  gt  1      Declared as signed type      display   b   4 sb1000        gt  gt  gt  1      Signed constant      finish    end endmodule

User · Answer

1  lt  lt  ADDR WIDTH means 1 will be shifted 8 bits to the left and will be assigned as the value for RAM DEPTH   In addition  1  lt  lt  ADDR WIDTH also means 2 ADDR WIDTH   Given ADDR WIDTH   8  then 2 8   256 and that will be the value for RAM DEPTH

[operator-keyword] ' << ' operator in verilog

The answer is

Examples related to operator-keyword

Examples related to verilog

Tags