[java] Extract time from date String

How can I format the "2010-07-14 09:00:02" date string to depict just "9:00"?

This question is related to java string date time

The answer is


If you have date in integers, you could use like here:

Date date = new Date();
date.setYear(2010);
date.setMonth(07);
date.setDate(14)
date.setHours(9);
date.setMinutes(0);
date.setSeconds(0);
String time = new SimpleDateFormat("HH:mm:ss").format(date);

A very simple way is to use Formatter (see date time conversions) or more directly String.format as in

String.format("%tR", new Date())

Date date = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss").parse("2010-07-14 09:00:02");
String time = new SimpleDateFormat("H:mm").format(date);

http://download.oracle.com/javase/1.4.2/docs/api/java/text/SimpleDateFormat.html


The other answers were good answers when the question was asked. Time moves on, Date and SimpleDateFormat get replaced by newer and better classes and go out of use. In 2017, use the classes in the java.time package:

    String timeString = LocalDateTime.parse(dateString, DateTimeFormatter.ofPattern("uuuu-MM-dd HH:mm:ss"))
            .format(DateTimeFormatter.ofPattern("H:mm"));

The result is the desired, 9:00.


let datestring = "2017-02-14 02:16:28"

let formatter = DateFormatter()
formatter.dateStyle = DateFormatter.Style.full
formatter.timeStyle = DateFormatter.Style.full

formatter.dateFormat = "yyyy-MM-dd hh:mm:ss"

let date = formatter.date(from: datestring)
let date2 = formatter.String(from: date)

I'm assuming your first string is an actual Date object, please correct me if I'm wrong. If so, use the SimpleDateFormat object: http://download.oracle.com/javase/6/docs/api/java/text/SimpleDateFormat.html. The format string "h:mm" should take care of it.


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