Shell script How to cut part of a string

Question

I have following string            eGalax Inc  USB TouchController          id 9     slave  pointer   2             eGalax Inc  USB TouchController          id 10    slave  pointer   2     and would like to get the list of id   How this can be done using sed or something else

User · Answer

You can have awk do it all without using cut   awk   print substr  7 index  7      1    inputfile   You could use split   instead of substr index

User · Answer

ruby -ne  puts    scan  id   d      file 9 10

User · Answer

A perl-solution   perl -nE  say  1 if  id   d     filename

User · Answer

I pasted the contents of your example into a file named so txt     cat so txt   awk    print  7      cut -f2 -d    9 10   Explanation    cat so txt will print the contents of the file to stdout   awk    print  7    will print the seventh column  i e  the one containing id n  cut -f2 -d    will cut the output of step  2 using   as the delimiter and get the second column  -f2    If you d rather get id  also  then     cat so txt   awk    print  7     id 9 id 10

User · Answer

Assuming input of   Anything id  ID  space  Anything    Anything id  ID  space  Anything    --      bin sh while read s  do    rhs   s   id      id   rhs         echo  id   Do what you will with  id here done  lt so txt    Or if it s always the 7th field      bin sh while read f1 f2 f3 f4 f5 f6 f7 rest do echo   f7  id   done  lt so txt   See Also  Shell Parameter Expansion

User · Answer

Use a regular expression to catch the id number and replace the whole line with the number  Something like this should do it  match everything up to  id    then match any number of digits  then match the rest of the line    sed -e  s   id    0-9         1 g    Do this for every line and you get the list of ids

[linux] Shell script : How to cut part of a string

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