php - insert a variable in an echo string

Question

i   1 echo    lt p class  paragraph i  gt   lt  p gt      i   Trying to insert a variable into an echoed string  The above code doesn t work  How do I iterate a php variable into an echo string

User · Answer

Variable interpolation does not happen in single quotes  You need to use double quotes as    i   1 echo   lt p class   paragraph i   gt  lt  p gt      i

User · Answer

Single quotes will not parse PHP variables inside of them  Either use double quotes or use a dot to extend the echo    variableName    Ralph   echo  Hello    variableName        OR  echo  Hello  variableName      And in your case    i   1  echo   lt p class  paragraph   i    gt  lt  p gt      i    OR   i   1  echo   lt p class  paragraph i  gt  lt  p gt      i

User · Answer

echo   lt p class  paragraph   i    gt  lt  p gt     should do the trick

User · Answer

Here s the 3 best ways of doing this      Method One     x     3   echo  1 2 x     Double Quotes     allows you to just pass the variable directly inside it        Method Two     x     3   echo  1 2   x    When you don t want to use double quotes for whatever reason go with this  The     simply means  Add  basically  So if you were to want to add something like  1 2 3 4 5 and have your variable in the middle all you need to do is    x     3   echo  1 2   x   4 5          Method 3   Adding a variable directly inside the called variable     x     3    y     4    z     5   echo  1 2   x   y  z    Output  1 2 3 4 5   Here we are adding  y and  z to  x using the      The    prioritize s the work inside it before rendering the undefined variable   This personally is a very useful function for calling functions like     Add the Get request to a variable   x     GET  tool       Edit  If you want this if to contain multiple  xresult s change the if s   Conditon in the      to isset  get   Simple  Now just add  xresultprogram   or whatever  if  x     app          xresultapp    User requested tool  App        Somewhere down far in HTML maybe     echo    xresult   x      so this outputs   xresultapp s value    Note  doing    xresult    GET  tool    directly wont work    I believe this is because since some direct non-echo html was loaded   before we got to this php section it cant load cause it has already   Started loading client side HTML and JS    This would output  xresultapp s  User requested tool  App  if the url query is   example com tool app  You can modify with an else statement to define what happens when some value other than  app  is requested  Remember  everything is case-sensitive so if they request  App  in capitals it won t output  xresultapp

User · Answer

echo   lt p class  paragrah      i      gt

User · Answer

Always use double quotes when using a variable inside a string and backslash any other double quotes except the starting and ending ones  You could also use the brackets like below so it s easier to find your variables inside the strings and make them look cleaner    var    my variable   echo  I love   var      or    var    my variable   echo  I love   var      Above would return the following  I love my variable

User · Answer

Use double quotes    i   1  echo    lt p class   paragraph i   gt   lt  p gt       i

User · Answer

You can try this   i   1 echo   lt p class  paragraph   i    gt  lt  p gt      i

User · Answer

echo   lt p class  paragraph   i    gt  lt  p gt

User · Answer

i   1   echo  quot  lt p class  paragraph  i   gt  lt  p gt  quot      i

[php] php - insert a variable in an echo string

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