[python] How to print current date on python3?

From what I gather, here (for example), this should print the current year in two digits

print (datetime.strftime("%y"))

However, I get this error

TypeError: descriptor 'strftime' requires a 'datetime.date' object but received a 'str'

So I tried to this

print (datetime.strftime(datetime.date()))

to get

TypeError: descriptor 'date' of 'datetime.datetime' object needs an argument

so I placed "%y" inside of thr date() above to get

TypeError: descriptor 'date' requires a 'datetime.datetime' object but received a 'str'

Which start to seem really loopy and fishy to me.

What am I missing?

I always use this code, which print the year to second in a tuple

import datetime

now = datetime.datetime.now()

time_now = (now.year, now.month, now.day, now.hour, now.minute, now.second)

print(time_now)

I use this which is standard for every time

import datetime
now = datetime.datetime.now()
print ("Current date and time : ")
print (now.strftime("%Y-%m-%d %H:%M:%S"))

This function allows you to get the date and time in lots of formats (see the bottom of this post).

# Get the current date or time
def getdatetime(timedateformat='complete'):
    from datetime import datetime
    timedateformat = timedateformat.lower()
    if timedateformat == 'day':
        return ((str(datetime.now())).split(' ')[0]).split('-')[2]
    elif timedateformat == 'month':
        return ((str(datetime.now())).split(' ')[0]).split('-')[1]
    elif timedateformat == 'year':
        return ((str(datetime.now())).split(' ')[0]).split('-')[0]
    elif timedateformat == 'hour':
        return (((str(datetime.now())).split(' ')[1]).split('.')[0]).split(':')[0]
    elif timedateformat == 'minute':
        return (((str(datetime.now())).split(' ')[1]).split('.')[0]).split(':')[1]
    elif timedateformat == 'second':
        return (((str(datetime.now())).split(' ')[1]).split('.')[0]).split(':')[2]
    elif timedateformat == 'millisecond':
        return (str(datetime.now())).split('.')[1]
    elif timedateformat == 'yearmonthday':
        return (str(datetime.now())).split(' ')[0]
    elif timedateformat == 'daymonthyear':
        return ((str(datetime.now())).split(' ')[0]).split('-')[2] + '-' + ((str(datetime.now())).split(' ')[0]).split('-')[1] + '-' + ((str(datetime.now())).split(' ')[0]).split('-')[0]
    elif timedateformat == 'hourminutesecond':
        return ((str(datetime.now())).split(' ')[1]).split('.')[0]
    elif timedateformat == 'secondminutehour':
        return (((str(datetime.now())).split(' ')[1]).split('.')[0]).split(':')[2] + ':' + (((str(datetime.now())).split(' ')[1]).split('.')[0]).split(':')[1] + ':' + (((str(datetime.now())).split(' ')[1]).split('.')[0]).split(':')[0]
    elif timedateformat == 'complete':
        return str(datetime.now())
    elif timedateformat == 'datetime':
        return (str(datetime.now())).split('.')[0]
    elif timedateformat == 'timedate':
        return ((str(datetime.now())).split('.')[0]).split(' ')[1] + ' ' + ((str(datetime.now())).split('.')[0]).split(' ')[0]

To obtain the time or date, just use getdatetime("<TYPE>"), replacing <TYPE> with one of the following arguments:

All example outputs use this model information: 25-11-2017 03:23:56.477017

The following seems to work:

import datetime
print (datetime.datetime.now().strftime("%y"))

The datetime.data object that it wants is on the "left" of the dot rather than the right. You need an instance of the datetime to call the method on, which you get through now()

Please try the below lines in order to get the current date.

import datetime

now = datetime.datetime.now()

print (now.strftime("%Y-%m-%d %H:%M:%S"))

Output:
2020-02-26 21:15:32

Refer : https://beginnersbug.com/how-to-get-the-current-date-in-pyspark-with-example/