How to get address of a pointer in c c

Question

How to get address of a pointer in c c     Eg  I have below code   int a  10  int  p    amp a    So how do I get address of pointer p  Now I want to print address of p  what should I do   print   s       what I pass to

User · Answer

If you are trying to compile these codes from a Linux terminal, you might get an error saying

expects argument type int

Its because, when you try to get the memory address by printf, you cannot specify it as %d as its shown in the video. Instead of that try to put %p.

Example:

// this might works fine since the out put is an integer as its expected.
printf("%d\n", *p); 

// but to get the address:
printf("%p\n", p);

User · Answer

amp a gives address of a -  amp p gives address of p   int     p to p    amp p

User · Answer

First  you should understand the pointer is not complex  A pointer is showing the address of the variable  Example  int a   10  int  p    amp a      This means giving a pointer of variable  quot a quot  to int pointer variable  quot p quot   And  you should understand  quot Pointer is an address quot  and  quot address is numerical value quot   So  you can get the address of variable as Integer  int a   10  unsigned long address    unsigned long  amp a      comparison printf  quot  p n quot    amp a   printf  quot  ld n quot   address    output is below 0x7fff1216619c 7fff1216619c  Note  If you use a 64-bit computer  you can t get pointer by the way below  int a   10  unsigned int address    unsigned int  amp a   Because pointer is 8 bytes  64 bit  on a 64-bit machine  but int is 4 bytes  So  you can t give an 8-byte memory address to 4 bytes variable  You have to use long long or long to get an address of the variable   long long is always 8 bytes  long is 4 bytes when code was compiled for a 32-bit machine  long is 8 bytes when code was compiled for a 64-bit machine   Therefore  you should use long to receive a pointer

User · Answer

You can use  p in C  In C   printf   p  p    In C     cout lt  lt  Address of pointer p is    lt  lt p

User · Answer

int a   10    To get the address of a  you do   amp a  address of a  which returns an int   pointer to int   int  p    amp a    Then you store the address of a in p which is of type int    Finally  if you do  amp p you get the address of p which is of type int    i e  pointer to pointer to int   int   p ptr    amp p    just seen your edit   to print out the pointer s address  you either need to convert it   printf  address of pointer is  0x 0X n    unsigned  amp p   printf  address of pointer to pointer is  0x 0X n    unsigned  amp p ptr     or if your printf supports it  use the  p   printf  address of pointer is   p n   p   printf  address of pointer to pointer is   p n   p ptr

User · Answer

you can use this  in C  int a  10  int  p    amp a       int   pp    amp p  printf   u   amp p     in C    cout lt  lt p

User · Answer

In C   you can do      Declaration and assign variable a int a   7     Declaration pointer b int  b     Assign address of variable a to pointer b b    amp a      Declaration pointer c int   c     Assign address of pointer b to pointer c c    amp b   std  cout  lt  lt   a     lt  lt  a  lt  lt    n            Print value of variable a std  cout  lt  lt    amp a     lt  lt   amp a  lt  lt    n          Print address of variable a  std  cout  lt  lt      lt  lt      lt  lt    n    std  cout  lt  lt   b     lt  lt  b  lt  lt    n            Print address of variable a std  cout  lt  lt    b     lt  lt   b  lt  lt    n          Print value of variable a std  cout  lt  lt    amp b     lt  lt   amp b  lt  lt    n          Print address of pointer b  std  cout  lt  lt      lt  lt      lt  lt    n    std  cout  lt  lt   c     lt  lt  c  lt  lt    n            Print address of pointer b std  cout  lt  lt     c     lt  lt    c  lt  lt    n        Print value of variable a std  cout  lt  lt    c     lt  lt   c  lt  lt    n          Print address of variable a std  cout  lt  lt    amp c     lt  lt   amp c  lt  lt    n          Print address of pointer c

User · Answer

Having this C source   int a   10  int   ptr    amp a    Use this  printf  The address of ptr is  p n    void     amp ptr     to print the address of ptr   Please note that the conversion specifier p is the only conversion specifier to print a pointer s value and it is defined to be used with void  typed pointers only   From man printf      p       The void   pointer argument is printed in hexadecimal  as if                 by   x or   lx

User · Answer

To get the address of p do   int   pp    amp p    and you can go on   int    ppp    amp pp  int     pppp    amp ppp        or  only in C  11  you can do   auto pp   std  addressof p     To print the address in C  most compilers support  p  so you can simply do   printf  addr   p   pp     otherwise you need to cast it  assuming a 32 bit platform   printf  addr  0x u    unsigned pp     In C   you can do   cout  lt  lt   addr     lt  lt  pp

User · Answer

You can use the  p formatter  It s always best practice cast your pointer void  before printing    The C standard says      The argument shall be a pointer to void  The value of the pointer is converted to a sequence of printing characters  in an implementation-defined manner    Here s how you do it   printf   p    void  p

[c++] How to get address of a pointer in c/c++?

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