[php] jQuery AJAX form data serialize using PHP

I am stuck in my code, I need to send data from the form to the check.php page and then process it.

This is my code:

The AJAX part:

<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<script>
$(document).ready(function(){
var form=$("#myForm");
$("#smt").click(function(){
$.ajax({
        type:"POST",
        url:form.attr("action"),
        data:form.serialize(),
        success: function(response){
            console.log(response);  
        }
    });
});
});
</script>

The form:

<form action="check.php" method="post" name="myForm" id="myForm">
<input type="text" name="user" id="user" />
<input type="text" name="pass" id="pass" />
<input type="button" name="smt" value="Submit" id="smt" />
</form>
<div id="err"></div>

the php part:

$user=$_POST['user'];
$pass=$_POST['pass'];

if($user=="tony")
{
    echo "HI ".$user;   
}
else
{
    echo "I dont know you.";    
}

This question is related to php jquery ajax forms

The answer is


Change your code as follows -

<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<script>
$(document).ready(function(){
var form=$("#myForm");
$("#smt").click(function(){
$.ajax({
        type:"POST",
        url:form.attr("action"),
        data:form.serialize(),

        success: function(response){
        if(response == 1){
              $("#err").html("Hi Tony");//updated
        }  else {
            $("#err").html("I dont know you.");//updated
        }
        }
    });
});
});
</script>

PHP -

<?php
$user=$_POST['user'];
$pass=$_POST['pass'];

if($user=="tony")
{
    echo 1;   
}
else
{
    echo 0;    
}
?>

I just had the same problem: You have to unserialize the data on the php side.

Add to the beginning of your php file (Attention this short version would replace all other post variables):

parse_str($_POST["data"], $_POST);

Try this its working..

    <script>
      $(function () {
          $('form').on('submit', function (e) {
              e.preventDefault();
              $.ajax({
                  type: 'post',
                  url: '<?php echo base_url();?>student_ajax/insert',
                  data: $('form').serialize(),
                  success: function (response) {
                      alert('form was submitted');
                  }
                  error:function() {
                      alert('fail');
                  }
              });
          });
      });
    </script>

<form method="post" name="myForm" id="myForm">

replace with above form tag remove action from form tag. and set url : "check.php" in ajax in your case first it goes to jQuery ajax then submit again the form. that's why it's creating issue.

i know i'm too late for this reply but i think it would help.


Try this

 $(document).ready(function(){
    var form=$("#myForm");
    $("#smt").click(function(){
    $.ajax({
            type:"POST",
            url:form.attr("action"),
            data:$("#myForm input").serialize(),//only input
            success: function(response){
                console.log(response);  
            }
        });
    });
    });

_x000D_
_x000D_
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>_x000D_
<script>_x000D_
$(document).ready(function(){_x000D_
    var form=$("#myForm");_x000D_
    $("#smt").click(function(){_x000D_
        $.ajax({_x000D_
            type:"POST",_x000D_
            url:form.attr("action"),_x000D_
            data:form.serialize(),_x000D_
            success: function(response){_x000D_
                console.log(response);  _x000D_
            }_x000D_
        });_x000D_
    });_x000D_
});_x000D_
</script>
_x000D_
_x000D_
_x000D_

This is perfect code , there is no problem.. You have to check that in php script.


try it , but first be sure what is you response console.log(response) on ajax success from server

<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<script>
$(document).ready(function(){
var form=$("#myForm");
$("#smt").click(function(){
$.ajax({
        type:"POST",
        url:form.attr("action"),
        data:form.serialize(),

        success: function(response){
        if(response === 1){
            //load chech.php file  
        }  else {
            //show error
        }
        }
    });
});
});


Your problem is in your php file. When you use jquery serialize() method you are sending a string, so you can not treat it like an array. Make a var_dump($_post) and you will see what I am talking about.


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