I am stuck in my code, I need to send data from the form to the check.php page and then process it.
This is my code:
The AJAX part:
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<script>
$(document).ready(function(){
var form=$("#myForm");
$("#smt").click(function(){
$.ajax({
type:"POST",
url:form.attr("action"),
data:form.serialize(),
success: function(response){
console.log(response);
}
});
});
});
</script>
The form:
<form action="check.php" method="post" name="myForm" id="myForm">
<input type="text" name="user" id="user" />
<input type="text" name="pass" id="pass" />
<input type="button" name="smt" value="Submit" id="smt" />
</form>
<div id="err"></div>
the php part:
$user=$_POST['user'];
$pass=$_POST['pass'];
if($user=="tony")
{
echo "HI ".$user;
}
else
{
echo "I dont know you.";
}
Change your code as follows -
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<script>
$(document).ready(function(){
var form=$("#myForm");
$("#smt").click(function(){
$.ajax({
type:"POST",
url:form.attr("action"),
data:form.serialize(),
success: function(response){
if(response == 1){
$("#err").html("Hi Tony");//updated
} else {
$("#err").html("I dont know you.");//updated
}
}
});
});
});
</script>
PHP -
<?php
$user=$_POST['user'];
$pass=$_POST['pass'];
if($user=="tony")
{
echo 1;
}
else
{
echo 0;
}
?>
I just had the same problem: You have to unserialize the data on the php side.
Add to the beginning of your php file (Attention this short version would replace all other post variables):
parse_str($_POST["data"], $_POST);
Try this its working..
<script>
$(function () {
$('form').on('submit', function (e) {
e.preventDefault();
$.ajax({
type: 'post',
url: '<?php echo base_url();?>student_ajax/insert',
data: $('form').serialize(),
success: function (response) {
alert('form was submitted');
}
error:function() {
alert('fail');
}
});
});
});
</script>
<form method="post" name="myForm" id="myForm">
replace with above form tag remove action from form tag. and set url : "check.php" in ajax in your case first it goes to jQuery ajax then submit again the form. that's why it's creating issue.
i know i'm too late for this reply but i think it would help.
Try this
$(document).ready(function(){
var form=$("#myForm");
$("#smt").click(function(){
$.ajax({
type:"POST",
url:form.attr("action"),
data:$("#myForm input").serialize(),//only input
success: function(response){
console.log(response);
}
});
});
});
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>_x000D_
<script>_x000D_
$(document).ready(function(){_x000D_
var form=$("#myForm");_x000D_
$("#smt").click(function(){_x000D_
$.ajax({_x000D_
type:"POST",_x000D_
url:form.attr("action"),_x000D_
data:form.serialize(),_x000D_
success: function(response){_x000D_
console.log(response); _x000D_
}_x000D_
});_x000D_
});_x000D_
});_x000D_
</script>
_x000D_
This is perfect code , there is no problem.. You have to check that in php script.
try it , but first be sure what is you response console.log(response) on ajax success from server
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<script>
$(document).ready(function(){
var form=$("#myForm");
$("#smt").click(function(){
$.ajax({
type:"POST",
url:form.attr("action"),
data:form.serialize(),
success: function(response){
if(response === 1){
//load chech.php file
} else {
//show error
}
}
});
});
});
Your problem is in your php file. When you use jquery serialize()
method you are sending a string, so you can not treat it like an array. Make a var_dump($_post)
and you will see what I am talking about.
Source: Stackoverflow.com