[java] Most efficient way to see if an ArrayList contains an object in Java

Is there any better way than just looping through and manually comparing the two fields for each object and then breaking when found? That just seems so messy, looking for a better way.

If your concern is maintainability you could do what Fabian Steeg suggest ( that's what I would do ) although it probably isn't the "most efficient" ( because you have to sort the array first and then perform the binary search ) but certainly the cleanest and better option.

If you're really concerned with efficiency, you can create a custom List implementation that uses the field in your object as the hash and use a HashMap as storage. But probably this would be too much.

Then you have to change the place where you fill the data from ArrayList to YourCustomList.

Like:

 List list = new ArrayList();

 fillFromSoap( list );

To:

 List list = new MyCustomSpecialList();

 fillFromSoap( list );

The implementation would be something like the following:

class MyCustomSpecialList extends AbstractList  { 
    private Map<Integer, YourObject> internalMap;

    public boolean add( YourObject o ) { 
         internalMap.put( o.getThatFieldYouKnow(), o );
    }

    public boolean contains( YourObject o ) { 
        return internalMap.containsKey( o.getThatFieldYouKnow() );
    }

}

Pretty much like a HashSet, the problem here is the HashSet relies on the good implementation of the hashCode method, which probably you don't have. Instead you use as the hash "that field you know" which is the one that makes one object equals to the other.

Of course implementing a List from the scratch lot more tricky than my snippet above, that's why I say the Fabian Steeg suggestion would be better and easier to implement ( although something like this would be more efficient )

Tell us what you did at the end.

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