[python] How do I pass a method as a parameter in Python

Is it possible to pass a method as a parameter to a method?

self.method2(self.method1)

def method1(self):
    return 'hello world'

def method2(self, methodToRun):
    result = methodToRun.call()
    return result

Yes; functions (and methods) are first class objects in Python. The following works:

def foo(f):
    print "Running parameter f()."
    f()

def bar():
    print "In bar()."

foo(bar)

Outputs:

Running parameter f().
In bar().

These sorts of questions are trivial to answer using the Python interpreter or, for more features, the IPython shell.

Methods are objects like any other. So you can pass them around, store them in lists and dicts, do whatever you like with them. The special thing about them is they are callable objects so you can invoke __call__ on them. __call__ gets called automatically when you invoke the method with or without arguments so you just need to write methodToRun().

Yes it is possible. Just call it:

class Foo(object):
    def method1(self):
        pass
    def method2(self, method):
        return method()

foo = Foo()
foo.method2(foo.method1)

Example: a simple function call wrapper:

def measure_cpu_time(f, *args):
    t_start = time.process_time()
    ret = f(*args)
    t_end = time.process_time()
    return t_end - t_start, ret

If you want to pass a method of a class as an argument but don't yet have the object on which you are going to call it, you can simply pass the object once you have it as the first argument (i.e. the "self" argument).

class FooBar:

    def __init__(self, prefix):
        self.prefix = prefix

    def foo(self, name):
        print "%s %s" % (self.prefix, name)


def bar(some_method):
    foobar = FooBar("Hello")
    some_method(foobar, "World")

bar(FooBar.foo)

This will print "Hello World"

Lots of good answers but strange that no one has mentioned using a lambda function.
So if you have no arguments, things become pretty trivial:

def method1():
    return 'hello world'

def method2(methodToRun):
    result = methodToRun()
    return result

method2(method1)

But say you have one (or more) arguments in method1:

def method1(param):
    return 'hello ' + str(param)

def method2(methodToRun):
    result = methodToRun()
    return result

Then you can simply invoke method2 as method2(lambda: method1('world')).

method2(lambda: method1('world'))
>>> hello world
method2(lambda: method1('reader'))
>>> hello reader

I find this much cleaner than the other answers mentioned here.

Here is your example re-written to show a stand-alone working example:

class Test:
    def method1(self):
        return 'hello world'

    def method2(self, methodToRun):
        result = methodToRun()
        return result

    def method3(self):
        return self.method2(self.method1)

test = Test()

print test.method3()

Not exactly what you want, but a related useful tool is getattr(), to use method's name as a parameter.

class MyClass:
   def __init__(self):
      pass
   def MyMethod(self):
      print("Method ran")

# Create an object
object = MyClass()
# Get all the methods of a class
method_list = [func for func in dir(MyClass) if callable(getattr(MyClass, func))]
# You can use any of the methods in method_list
# "MyMethod" is the one we want to use right now

# This is the same as running "object.MyMethod()"
getattr(object,'MyMethod')()