[bash] Check number of arguments passed to a Bash script

There is a lot of good information here, but I wanted to add a simple snippet that I find useful.

How does it differ from some above?

  • Prints usage to stderr, which is more proper than printing to stdout
  • Return with exit code mentioned in this other answer
  • Does not make it into a one liner...
_usage(){
    _echoerr "Usage: $0 <args>"
}

_echoerr(){
    echo "$*" >&2
}

if [ "$#" -eq 0 ]; then # NOTE: May need to customize this conditional
    _usage
    exit 2
fi
main "$@"

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