[python] How to start a background process in Python?

Both capture output and run on background with threading

As mentioned on this answer, if you capture the output with stdout= and then try to read(), then the process blocks.

However, there are cases where you need this. For example, I wanted to launch two processes that talk over a port between them, and save their stdout to a log file and stdout.

The threading module allows us to do that.

First, have a look at how to do the output redirection part alone in this question: Python Popen: Write to stdout AND log file simultaneously

Then:

main.py

#!/usr/bin/env python3

import os
import subprocess
import sys
import threading

def output_reader(proc, file):
    while True:
        byte = proc.stdout.read(1)
        if byte:
            sys.stdout.buffer.write(byte)
            sys.stdout.flush()
            file.buffer.write(byte)
        else:
            break

with subprocess.Popen(['./sleep.py', '0'], stdout=subprocess.PIPE, stderr=subprocess.PIPE) as proc1, \
     subprocess.Popen(['./sleep.py', '10'], stdout=subprocess.PIPE, stderr=subprocess.PIPE) as proc2, \
     open('log1.log', 'w') as file1, \
     open('log2.log', 'w') as file2:
    t1 = threading.Thread(target=output_reader, args=(proc1, file1))
    t2 = threading.Thread(target=output_reader, args=(proc2, file2))
    t1.start()
    t2.start()
    t1.join()
    t2.join()

sleep.py

#!/usr/bin/env python3

import sys
import time

for i in range(4):
    print(i + int(sys.argv[1]))
    sys.stdout.flush()
    time.sleep(0.5)

After running:

./main.py

stdout get updated every 0.5 seconds for every two lines to contain:

0
10
1
11
2
12
3
13

and each log file contains the respective log for a given process.

Inspired by: https://eli.thegreenplace.net/2017/interacting-with-a-long-running-child-process-in-python/

Tested on Ubuntu 18.04, Python 3.6.7.

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