I have a UILabel that displays some chars. Like "x", "y" or "rpm". How can I calculate the width of the text in the label (it does not ues the whole available space)? This is for automatic layouting, where another view will have a bigger frame rectangle if that UILabel has a smaller text inside. Are there methods to calculate that width of the text when a UIFont and font size is specified? There's also no line-break and just one single line.
This question is related to
iphone
cocoa-touch
uikit
This simple extension in Swift works well.
extension String {
func size(OfFont font: UIFont) -> CGSize {
return (self as NSString).size(attributes: [NSFontAttributeName: font])
}
}
Usage:
let string = "hello world!"
let font = UIFont.systemFont(ofSize: 12)
let width = string.size(OfFont: font).width // size: {w: 98.912 h: 14.32}
Not sure how efficient this is, but I wrote this function that returns the point size that will fit a string to a given width:
func fontSizeThatFits(targetWidth: CGFloat, maxFontSize: CGFloat, font: UIFont) -> CGFloat {
var variableFont = font.withSize(maxFontSize)
var currentWidth = self.size(withAttributes: [NSAttributedString.Key.font:variableFont]).width
while currentWidth > targetWidth {
variableFont = variableFont.withSize(variableFont.pointSize - 1)
currentWidth = self.size(withAttributes: [NSAttributedString.Key.font:variableFont]).width
}
return variableFont.pointSize
}
And it would be used like this:
textView.font = textView.font!.withSize(textView.text!.fontSizeThatFits(targetWidth: view.frame.width, maxFontSize: 50, font: textView.font!))
Swift 4
extension String {
func SizeOf(_ font: UIFont) -> CGSize {
return self.size(withAttributes: [NSAttributedStringKey.font: font])
}
}
This answer is a much cleaner way to do it using new syntax.
Based on Glenn Howes' excellent answer, I created an extension to calculate the width of a string. If you're doing something like setting the width of a UISegmentedControl
, this can set the width based on the segment's title string.
extension String {
func widthOfString(usingFont font: UIFont) -> CGFloat {
let fontAttributes = [NSAttributedString.Key.font: font]
let size = self.size(withAttributes: fontAttributes)
return size.width
}
func heightOfString(usingFont font: UIFont) -> CGFloat {
let fontAttributes = [NSAttributedString.Key.font: font]
let size = self.size(withAttributes: fontAttributes)
return size.height
}
func sizeOfString(usingFont font: UIFont) -> CGSize {
let fontAttributes = [NSAttributedString.Key.font: font]
return self.size(withAttributes: fontAttributes)
}
}
usage:
// Set width of segmentedControl
let starString = "??"
let starWidth = starString.widthOfString(usingFont: UIFont.systemFont(ofSize: 14)) + 16
segmentedController.setWidth(starWidth, forSegmentAt: 3)
The way I am doing it my code is to make an extension of UIFont: (This is Swift 4.1)
extension UIFont {
public func textWidth(s: String) -> CGFloat
{
return s.size(withAttributes: [NSAttributedString.Key.font: self]).width
}
} // extension UIFont
This is for swift 2.3 Version. You can get the width of string.
var sizeOfString = CGSize()
if let font = UIFont(name: "Helvetica", size: 14.0)
{
let finalDate = "Your Text Here"
let fontAttributes = [NSFontAttributeName: font] // it says name, but a UIFont works
sizeOfString = (finalDate as NSString).sizeWithAttributes(fontAttributes)
}
If you're struggling to get text width with multiline support, so you can use the next code (Swift 5):
func width(text: String, height: CGFloat) -> CGFloat {
let attributes: [NSAttributedString.Key: Any] = [
.font: UIFont.systemFont(ofSize: 17)
]
let attributedText = NSAttributedString(string: text, attributes: attributes)
let constraintBox = CGSize(width: .greatestFiniteMagnitude, height: height)
let textWidth = attributedText.boundingRect(with: constraintBox, options: [.usesLineFragmentOrigin, .usesFontLeading], context: nil).width.rounded(.up)
return textWidth
}
And the same way you could find text height if you need to (just switch the constraintBox implementation):
let constraintBox = CGSize(width: maxWidth, height: .greatestFiniteMagnitude)
Or here's a unified function to get text size with multiline support:
func labelSize(for text: String, maxWidth: CGFloat, maxHeight: CGFloat) -> CGSize {
let attributes: [NSAttributedString.Key: Any] = [
.font: UIFont.systemFont(ofSize: 17)
]
let attributedText = NSAttributedString(string: text, attributes: attributes)
let constraintBox = CGSize(width: maxWidth, height: maxHeight)
let rect = attributedText.boundingRect(with: constraintBox, options: [.usesLineFragmentOrigin, .usesFontLeading], context: nil).integral
return rect.size
}
Usage:
let textSize = labelSize(for: "SomeText", maxWidth: contentView.bounds.width, maxHeight: .greatestFiniteMagnitude)
let textHeight = textSize.height.rounded(.up)
let textWidth = textSize.width.rounded(.up)
Use intrinsicContentSize to find the text height and width.
yourLabel.intrinsicContentSize.width
This will work even you have custom spacing between your string like "T E X T"
Since sizeWithFont
is deprecated, I'm just going to update my original answer to using Swift 4 and .size
//: Playground - noun: a place where people can play
import UIKit
if let font = UIFont(name: "Helvetica", size: 24) {
let fontAttributes = [NSAttributedStringKey.font: font]
let myText = "Your Text Here"
let size = (myText as NSString).size(withAttributes: fontAttributes)
}
The size should be the onscreen size of "Your Text Here" in points.
let size = text.size(withAttributes:[.font: UIFont.systemFont(ofSize:18.0)])
sizeWithFont:
is now deprecated, use sizeWithAttributes:
instead:
UIFont *font = [UIFont fontWithName:@"Helvetica" size:30];
NSDictionary *userAttributes = @{NSFontAttributeName: font,
NSForegroundColorAttributeName: [UIColor blackColor]};
NSString *text = @"hello";
...
const CGSize textSize = [text sizeWithAttributes: userAttributes];
For Swift 3.0+
extension String {
func SizeOf_String( font: UIFont) -> CGSize {
let fontAttribute = [NSFontAttributeName: font]
let size = self.size(attributes: fontAttribute) // for Single Line
return size;
}
}
Use it like...
let Str = "ABCDEF"
let Font = UIFont.systemFontOfSize(19.0)
let SizeOfString = Str.SizeOfString(font: Font!)
Source: Stackoverflow.com