How to print in C

Question

Very much a beginner to C  in fact this is my first tester program  I can t actually figure out how to print this number out to the terminal   include  lt stdio h gt   int addNumbers int a  int b        int sum   a   b      return sum     int main void        int a   4      int b   7       printf addNumbers a b        return 0     I am sure that in Java I could just replace the printf with System out and it would have worked  I tried searching the answer earlier but if you don t know what to search it s hard to find an answer

User · Answer

The first argument to printf   is always a string value  known as a format control string   This string may be regular text  such as  printf  Hello  World n        n indicates a newline character   or  char greeting      Hello  World n   printf greeting     This string may also contain one or more conversion specifiers  these conversion specifiers indicate that additional arguments have been passed to printf    and they specify how to format those arguments for output   For example  I can change the above to  char greeting      Hello  World   printf   s n   greeting     The   s  conversion specifier expects a pointer to a 0-terminated string  and formats it as text   For signed decimal integer output  use either the   d  or   i  conversion specifiers  such as  printf   d n   addNumber a b      You can mix regular text with conversion specifiers  like so   printf  The result of addNumber  d   d  is  d n   a  b  addNumber a b      Note that the conversion specifiers in the control string indicate the number and types of additional parameters   If the number or types of additional arguments passed to printf   don t match the conversion specifiers in the format string then the behavior is undefined   For example   printf  The result of addNumber  d   d  is  d n   addNumber a b      will result in anything from garbled output to an outright crash     There are a number of additional flags for conversion specifiers that control field width  precision  padding  justification  and types   Check your handy C reference manual for a complete listing

User · Answer

printf is a fair bit more complicated than that  You have to supply a format string  and then the variables to apply to the format string  If you just supply one variable  C will assume that is the format string and try to print out all the bytes it finds in it until it hits a terminating nul  0x0     So if you just give it an integer  it will merrily march through memory at the location your integer is stored  dumping whatever garbage is there to the screen  until it happens to come across a byte containing 0   For a Java programmer  I d imagine this is a rather rude introduction to C s lack of type checking  Believe me  this is only the tip of the iceberg  This is why  while I applaud your desire to expand your horizons by learning C  I highly suggest you do whatever you can to avoid writing real programs in it     This goes for everyone else reading this too

User · Answer

In C  unlike say C    you would need a format specifier that states the datatype of the variable you want to print-in this case  d as the data type is an integer   Try printf  quot  d quot  addNumbers a b

User · Answer

try this   printf   d   addNumber a b     Here s the documentation for printf

User · Answer

To print those numbers in C do the following   printf   d   addNumbers a b

[c] How to print in C

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