[bash] Using sed to mass rename files

Objective

Change these filenames:

• F00001-0708-RG-biasliuyda
• F00001-0708-CS-akgdlaul
• F00001-0708-VF-hioulgigl

to these filenames:

• F0001-0708-RG-biasliuyda
• F0001-0708-CS-akgdlaul
• F0001-0708-VF-hioulgigl

Shell Code

To test:

ls F00001-0708-*|sed 's/\(.\).\(.*\)/mv & \1\2/'

To perform:

ls F00001-0708-*|sed 's/\(.\).\(.*\)/mv & \1\2/' | sh

My Question

I don't understand the sed code. I understand what the substitution command

$ sed 's/something/mv'

means. And I understand regular expressions somewhat. But I don't understand what's happening here:

\(.\).\(.*\)

or here:

& \1\2/

The former, to me, just looks like it means: "a single character, followed by a single character, followed by any length sequence of a single character"--but surely there's more to it than that. As far as the latter part:

& \1\2/

I have no idea.

Using perl rename (a must have in the toolbox):

rename -n 's/0000/000/' F0000*

Remove -n switch when the output looks good to rename for real.

There are other tools with the same name which may or may not be able to do this, so be careful.

The rename command that is part of the util-linux package, won't.

If you run the following command (GNU)

$ rename

and you see perlexpr, then this seems to be the right tool.

If not, to make it the default (usually already the case) on Debian and derivative like Ubuntu :

$ sudo apt install rename
$ sudo update-alternatives --set rename /usr/bin/file-rename

For archlinux:

pacman -S perl-rename

For RedHat-family distros:

yum install prename

The 'prename' package is in the EPEL repository.

For Gentoo:

emerge dev-perl/rename

For *BSD:

pkg install gprename

or p5-File-Rename

For Mac users:

brew install rename

If you don't have this command with another distro, search your package manager to install it or do it manually:

cpan -i File::Rename

Old standalone version can be found here

man rename

_{^{This tool was originally written by Larry Wall, the Perl's dad.}}

If all you're really doing is removing the second character, regardless of what it is, you can do this:

s/.//2

but your command is building a mv command and piping it to the shell for execution.

This is no more readable than your version:

find -type f | sed -n 'h;s/.//4;x;s/^/mv /;G;s/\n/ /g;p' | sh

The fourth character is removed because find is prepending each filename with "./".

for i in *; do mv $i $(echo $i|sed 's/AAA/BBB/'); done

The easiest way would be:

for i in F00001*; do mv "$i" "${i/F00001/F0001}"; done

or, portably,

for i in F00001*; do mv "$i" "F0001${i#F00001}"; done

This replaces the F00001 prefix in the filenames with F0001. credits to mahesh here: http://www.debian-administration.org/articles/150

The sed command

s/\(.\).\(.*\)/mv & \1\2/

means to replace:

\(.\).\(.*\)

with:

mv & \1\2

just like a regular sed command. However, the parentheses, & and \n markers change it a little.

The search string matches (and remembers as pattern 1) the single character at the start, followed by a single character, follwed by the rest of the string (remembered as pattern 2).

In the replacement string, you can refer to these matched patterns to use them as part of the replacement. You can also refer to the whole matched portion as &.

So what that sed command is doing is creating a mv command based on the original file (for the source) and character 1 and 3 onwards, effectively removing character 2 (for the destination). It will give you a series of lines along the following format:

mv F00001-0708-RG-biasliuyda F0001-0708-RG-biasliuyda
mv abcdef acdef

and so on.

Some examples that work for me:

$ tree -L 1 -F .
.
+-- A.Show.2020.1400MB.txt
+-- Some Show S01E01 the Loreming.txt

0 directories, 2 files

## remove "1400MB" (I: ignore case) ...

$ for f in *; do mv 2>/dev/null -v "$f" "`echo $f | sed -r 's/.[0-9]{1,}mb//I'`"; done;
renamed 'A.Show.2020.1400MB.txt' -> 'A.Show.2020.txt'

## change "S01E01 the" to "S01E01 The"
## \U& : change (here: regex-selected) text to uppercase;
##       note also: no need here for `\1` in that regex expression

$ for f in *; do mv 2>/dev/null "$f" "`echo $f | sed -r "s/([0-9] [a-z])/\U&/"`"; done

$ tree -L 1 -F .
.
+-- A.Show.2020.txt
+-- Some Show S01E01 The Loreming.txt

0 directories, 2 files
$ 

• 2>/dev/null suppresses extraneous output (warnings ...)

• reference [this thread]: https://stackoverflow.com/a/2372808/1904943

• change case: https://www.networkworld.com/article/3529409/converting-between-uppercase-and-lowercase-on-the-linux-command-line.html

The backslash-paren stuff means, "while matching the pattern, hold on to the stuff that matches in here." Later, on the replacement text side, you can get those remembered fragments back with "\1" (first parenthesized block), "\2" (second block), and so on.

 ls F00001-0708-*|sed 's|^F0000\(.*\)|mv & F000\1|' | bash

Here's what I would do:

for file in *.[Jj][Pp][Gg] ;do 
    echo mv -vi \"$file\" `jhead $file|
                           grep Date|
                           cut -b 16-|
                           sed -e 's/:/-/g' -e 's/ /_/g' -e 's/$/.jpg/g'` ;
done

Then if that looks ok, add | sh to the end. So:

for file in *.[Jj][Pp][Gg] ;do 
    echo mv -vi \"$file\" `jhead $file|
                           grep Date|
                           cut -b 16-|
                           sed -e 's/:/-/g' -e 's/ /_/g' -e 's/$/.jpg/g'` ;
done | sh

you've had your sed explanation, now you can use just the shell, no need external commands

for file in F0000*
do
    echo mv "$file" "${file/#F0000/F000}"
    # ${file/#F0000/F000} means replace the pattern that starts at beginning of string
done

The parentheses capture particular strings for use by the backslashed numbers.

I wrote a small post with examples on batch renaming using sed couple of years ago:

http://www.guyrutenberg.com/2009/01/12/batch-renaming-using-sed/

For example:

for i in *; do
  mv "$i" "`echo $i | sed "s/regex/replace_text/"`";
done

If the regex contains groups (e.g. \(subregex\) then you can use them in the replacement text as \1\,\2 etc.