[c] null terminating a string

gcc 4.4.4 c89

What is the standard way to null terminate a string? When I use the NULL I get a warning message.

*dest++ = 0; 
*dest++ = '\0'; 
*dest++ = NULL; /* Warning: Assignment takes integer from pointer without a cast */

Source code:

size_t s_strscpy(char *dest, const char *src, const size_t len)
{
    /* Copy the contents from src to dest */
    size_t i = 0;
    for(i = 0; i < len; i++)
    *dest++ = *src++;

    /* Null terminate dest */
     *dest++ = 0; 

    return i;
}

Another question: I deliberately commented out the line that null terminates. However, it still correctly printed out the contents of the dest. The caller of this function would send the length of the string by either included the NULL or not. i.e. strlen(src) + 1 or stlen(src).

size_t s_strscpy(char *dest, const char *src, const size_t len)
{
    /* Copy the contents from src to dest */
    size_t i = 0;
    /* Don't copy the null terminator */
    for(i = 0; i < len - 1; i++)
    *dest++ = *src++;

    /* Don't add the Null terminator */
    /* *dest++ = 0; */

    return i;
}

'\0' is the way to go. It's a character, which is what's wanted in a string and has the null value.

When we say null terminated string in C/C++, it really means 'zero terminated string'. The NULL macro isn't intended for use in terminating strings.

From the comp.lang.c FAQ: http://c-faq.com/null/varieties.html

In essence: NULL (the preprocessor macro for the null pointer) is not the same as NUL (the null character).

Be very careful: NULL is a macro used mainly for pointers. The standard way of terminating a string is:

char *buffer;
...
buffer[end_position] = '\0';

This (below) works also but it is not a big difference between assigning an integer value to a int/short/long array and assigning a character value. This is why the first version is preferred and personally I like it better.

buffer[end_position] = 0;