Java RegEx meta character and ordinary dot

Question

In Java RegEx  how to find out the difference between   dot  the meta character and the normal dot as we using in any sentence  How to handle this kind of situation for other meta characters too like       d

User · Answer

If you want to end check whether your sentence ends with     then you have to add        to the end of your pattern

User · Answer

Escape special characters with a backslash                d  and so on  If you are unsure  you may escape any non-alphabetical character whether it is special or not  See the javadoc for java util regex Pattern for further information

User · Answer

Solutions proposed by the other members don t work for me   But I found this     to escape a dot in java regexp write

User · Answer

I wanted to match a string that ends with      For this I had to use the following                  Kinda silly if you think about it  D Heres what it means  At the start of the string there can be any character zero or more times followed by a dot     followed by a star     at the end of the string   I hope this comes in handy for someone  Thanks for the backslash thing to Fabian

User · Answer

If you want the dot or other characters with a special meaning in regexes to be a normal character  you have to escape it with a backslash  Since regexes in Java are normal Java strings  you need to escape the backslash itself  so you need two backslashes e g

User · Answer

I am doing some basic array in JGrasp and found that with an accessor method for a char     array to use       to place a single dot

User · Answer

Here is code you can directly copy paste     String imageName    picture1 jpg   String    imageNameArray   imageName split         for int i  0  i lt  imageNameArray length   i         system out println imageNameArray i        And what if mistakenly there are spaces left before or after     in such cases  It s always best practice to consider those spaces also   String imageName    picture1    jpg   String    imageNameArray   imageName split    s    s         for int i  0  i lt  imageNameArray length   i                 system out println imageNameArray i            Here    s  is there to consider the spaces and give you only required splitted strings

User · Answer

Perl-style regular expressions  which the Java regex engine is more or less based upon  treat the following characters as special characters                have special meaning outside of character classes     -  have special meaning inside of character classes           So you need to escape those  and only those  symbols depending on context  or  in the case of character classes  place them in positions where they can t be misinterpreted     Needlessly escaping other characters  may work  but some regex engines will treat this as syntax errors  for example    will cause an error in  NET   Some others will lead to false results  for example   lt  is interpreted as a literal  lt  in Perl  but in egrep it means  word boundary    So write -  d    d    to match 1 50   -2 00  etc  and           for a character class that matches all kinds of brackets braces parentheses   If you need to transform a user input string into a regex-safe form  use java util regex Pattern quote   Further reading  Jan Goyvaert s blog RegexGuru on escaping metacharacters

[java] Java RegEx meta character (.) and ordinary dot?

Examples related to java

Examples related to regex