I'm trying to get (not print, that's easy) the list of files in a directory and its sub directories.
I've tried:
def folder = "C:\\DevEnv\\Projects\\Generic";
def baseDir = new File(folder);
files = baseDir.listFiles();
I only get the directories. I've also tried:
def files = [];
def processFileClosure = {
println "working on ${it.canonicalPath}: "
files.add (it.canonicalPath);
}
baseDir.eachFileRecurse(FileType.FILES, processFileClosure);
But "files" is not recognized in the scope of the closure.
How do I get the list?
This question is related to
file
groovy
directory-listing
This code works for me:
import groovy.io.FileType
def list = []
def dir = new File("path_to_parent_dir")
dir.eachFileRecurse (FileType.FILES) { file ->
list << file
}
Afterwards the list variable contains all files (java.io.File) of the given directory and its subdirectories:
list.each {
println it.path
}
The following works for me in Gradle / Groovy for build.gradle for an Android project, without having to import groovy.io.FileType (NOTE: Does not recurse subdirectories, but when I found this solution I no longer cared about recursion, so you may not either):
FileCollection proGuardFileCollection = files { file('./proguard').listFiles() }
proGuardFileCollection.each {
println "Proguard file located and processed: " + it
}
Newer versions of Groovy (1.7.2+) offer a JDK extension to more easily traverse over files in a directory, for example:
import static groovy.io.FileType.FILES
def dir = new File(".");
def files = [];
dir.traverse(type: FILES, maxDepth: 0) { files.add(it) };
See also [1] for more examples.
[1] http://mrhaki.blogspot.nl/2010/04/groovy-goodness-traversing-directory.html
This is what I came up with for a gradle build script:
task doLast {
ext.FindFile = { list, curPath ->
def files = file(curPath).listFiles().sort()
files.each { File file ->
if (file.isFile()) {
list << file
}
else {
list << file // If you want the directories in the list
list = FindFile( list, file.path)
}
}
return list
}
def list = []
def theFile = FindFile(list, "${project.projectDir}")
list.each {
println it.path
}
}
Source: Stackoverflow.com