How can I find script s directory

Question

Consider the following Python code   import os print os getcwd     I use os getcwd   to get the script file s directory location  When I run the script from the command line it gives me the correct path whereas when I run it from a script run by code in a Django view it prints     How can I get the path to the script from within a script run by a Django view   UPDATE  Summing up the answers thus far - os getcwd   and os path abspath   both give the current working directory which may or may not be the directory where the script resides  In my web host setup   file   gives only the filename without the path   Isn t there any way in Python to  always  be able to receive the path in which the script resides

User · Answer

Try this   def get script path for file   None       path   os path dirname os path realpath sys argv 0  or  something        return path if not for file else os path join path  for file

User · Answer

Try sys path 0    To quote from the Python docs      As initialized upon program startup  the first item of this list  path 0   is the directory containing the script that was used to invoke the Python interpreter  If the script directory is not available  e g  if the interpreter is invoked interactively or if the script is read from standard input   path 0  is the empty string  which directs Python to search modules in the current directory first  Notice that the script directory is inserted before the entries inserted as a result of PYTHONPATH    Source  https   docs python org library sys html sys path

User · Answer

import os exec filepath   os path realpath   file    exec dirpath   exec filepath 0 len exec filepath -len os path basename   file

User · Answer

import os sys   Store current working directory pwd   os path dirname   file      Append current directory to the python path sys path append pwd

User · Answer

This is a pretty old thread but I ve been having this problem when trying to save files into the current directory the script is in when running a python script from a cron job  getcwd   and a lot of the other path come up with your home directory   to get an absolute path to the script i used  directory    os path abspath os path dirname   file

User · Answer

This worked for me  and I found it via the this stackoverflow question   os path realpath   file

User · Answer

This code   import os dn   os path dirname os path realpath   file       sets  dn  to the name of the directory containing the currently executing script  This code   fn   os path join dn  vcb init   fp   open fn  r     sets  fn  to  script dir vcb init   in a platform independent manner  and opens that file for reading by the currently executing script   Note that  the currently executing script  is somewhat ambiguous  If your whole program consists of 1 script  then that s the currently executing script and the  sys path 0   solution works fine  But if your app consists of script A  which imports some package  P  and then calls script  B   then  P B  is currently executing  If you need to get the directory containing  P B   you want the  os path realpath   file     solution      file    just gives the name of the currently executing  top-of-stack  script   x py   It doesn t give any path info  It s the  os path realpath  call that does the real work

User · Answer

Use os path abspath

User · Answer

import os script dir   os path dirname os path realpath   file       os sep

User · Answer

I use   import os import sys  def get script path        return os path dirname os path realpath sys argv 0      As aiham points out in a comment  you can define this function in a module and use it in different scripts

User · Answer

You need to call os path realpath on   file    so that when   file   is a filename without the path you still get the dir path   import os print os path dirname os path realpath   file

User · Answer

Here s what I ended up with  This works for me if I import my script in the interpreter  and also if I execute it as a script   import os import sys    Returns the directory the current script  or interpreter  is running in def get script directory        path   os path realpath sys argv 0       if os path isdir path           return path     else          return os path dirname path

[python] How can I find script's directory?

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