How do I call a Django function on button click

Question

I am trying to write a Django application and I am stuck at how I can call a view function when a button is clicked   In my template  I have a link button as below  when clicked it takes you to a different webpage    lt a target   blank  href     column 3 item link for item     gt Check It Out lt  a gt    When the button is clicked  I also want to call a Django view function  along with re-direct to a target website   The view function increments the value in the database which stores the number of times the button is clicked   The column 3 item link for item is a link to an external website  e g  www google com   Right now when that button is clicked  it opens a new window which takes you to the google website   What I would like to do is to call a Django view function also when the button is clicked which updates the database without refreshing the page  How I can achieve this

User · Answer

There are 2 possible solutions that I personally use

1.without using form

 <button type="submit" value={{excel_path}} onclick="location.href='{% url 'downloadexcel' %}'" name='mybtn2'>Download Excel file</button>

2.Using Form

<form action="{% url 'downloadexcel' %}" method="post">
{% csrf_token %}


 <button type="submit" name='mybtn2' value={{excel_path}}>Download results in Excel</button>
 </form>

Where urls.py should have this

path('excel/',views1.downloadexcel,name="downloadexcel"),

User · Answer

here is a pure-javascript  minimalistic approach  I use JQuery but you can use any library  or even no libraries at all     lt html gt       lt head gt           lt title gt An example lt  title gt           lt script src  http   ajax googleapis com ajax libs jquery 1 9 1 jquery min js  gt  lt  script gt           lt script gt              function call counter url  pk                    window open url                     get  YOUR VIEW HERE   pk      function  data                        alert  counter updated                                                lt  script gt       lt  head gt       lt body gt           lt button onclick  call counter  http   www google com   12345    gt              I update object 12345          lt  button gt           lt button onclick  call counter  http   www yahoo com   999    gt              I update object 999          lt  button gt       lt  body gt   lt  html gt      Alternative approach  Instead of placing the JavaScript code  you can change your link in this way    lt a target   blank       class  btn btn-info pull-right       href     url YOUR VIEW column 3 item pk     next   column 3 item link for item urlencode       gt      Check It Out  lt  a gt    and in your views py   def YOUR VIEW DEF request  pk       YOUR OBJECT objects filter pk pk  update views F  views   1      return HttpResponseRedirect request GET get  next

User · Answer

The following answer could be helpful for the first part of your question   Django  How can I call a view function from template

[python] How do I call a Django function on button click?

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