Django optional url parameters

Question

I have a Django URL like this   url      r  project config   P lt product gt  w     P lt project id gt  w            tool views ProjectConfig       name  project config       views py   def ProjectConfig request  product  project id None  template name  project html                  do stuff   The problem is that I want the project id parameter to be optional   I want  project config  and  project config 12345abdce  to be equally valid URL patterns  so that if project id is passed  then I can use it   As it stands at the moment  I get a 404 when I access the URL without the project id parameter

User · Answer

Django   2 2  urlpatterns         re path r  project config      P lt product gt  w        P lt project id gt  w           tool views ProjectConfig  name  project config

User · Answer

You can use nested routes  Django  lt 1 8  urlpatterns   patterns        url r  project config    include patterns             url r      ProjectConfigView as view    name  project config           url r    P lt product gt  w      include patterns                 url r      ProductView as view    name  product                url r    P lt project id gt  w      ProjectDetailView as view    name  project detail                             Django   1 8  urlpatterns         url r  project config    include           url r      ProjectConfigView as view    name  project config           url r    P lt product gt  w      include               url r      ProductView as view    name  product                url r    P lt project id gt  w      ProjectDetailView as view    name  project detail                             This is a lot more DRY  Say you wanted to rename the product kwarg to product id  you only have to change line 4  and it will affect the below URLs   Edited for Django 1 8 and above

User · Answer

Django   2 0 version   The approach is essentially identical with the one given in Yuji  Tomita  Tomita s Answer  Affected  however  is the syntax     URLconf      urlpatterns         path           project config  lt product gt             views get product           name  project config             path           project config  lt product gt   lt project id gt             views get product          name  project config               View  in views py  def get product request  product  project id  None          Output the appropriate product           Using path   you can also pass extra arguments to a view with the optional argument kwargs that is of type dict  In this case your view would not need a default for the attribute project id               path           project config  lt product gt             views get product          kwargs   project id   None           name  project config                   For how this is done in the most recent Django version  see the official docs about URL dispatching

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Thought I d add a bit to the answer   If you have multiple URL definitions then you ll have to name each of them separately  So you lose the flexibility when calling reverse since one reverse will expect a parameter while the other won t   Another way to use regex to accommodate the optional parameter   r  project config   P lt product gt  w      P lt project id gt  w

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Use   work well  you can check on pythex  Remember to add the parameters  args and   kwargs in the definition of the view methods  url  project config   P lt product gt  w       P lt project id gt  w         tool views ProjectConfig  name  project config

User · Answer

There are several approaches   One is to use a non-capturing group in the regex           P lt title gt  a-zA-Z       Making a Regex Django URL Token Optional  Another  easier to follow way is to have multiple rules that matches your needs  all pointing to the same view   urlpatterns   patterns         url r  project config     views foo       url r  project config   P lt product gt  w       views foo       url r  project config   P lt product gt  w     P lt project id gt  w       views foo       Keep in mind that in your view you ll also need to set a default for the optional URL parameter  or you ll get an error   def foo request  optional parameter            Your code goes here

User · Answer

Even simpler is to use     P lt project id gt  w      The   a b   means a or b  so in your case it would be one or more word characters   w   or nothing   So it would look like   url      r  project config   P lt product gt  w     P lt project id gt  w             tool views ProjectConfig       name  project config

[python] Django optional url parameters

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