Using url in django templates

Question

I have looked a lot on google for answers of how to use the  url  tag in templates only to find many responses saying  You just insert it into your template and point it at the view you want the url for   Well no joy for me    I have tried every permutation possible and have resorted to posting here as a last resort   So here it is  My urls py looks like this   from django conf urls defaults import   from login views import   from mainapp views import   import settings    Uncomment the next two lines to enable the admin  from django contrib import admin admin autodiscover    urlpatterns   patterns           Example         r  weclaim    include  weclaim foo urls          r  login    login view        r  logout    logout view              main view          Uncomment the admin doc line below and add  django contrib admindocs         to INSTALLED APPS to enable admin documentation         r  admin doc    include  django contrib admindocs urls            Uncomment the next line to enable the admin       r  admin    include admin site urls          r  static   P lt path gt         django views static serve    document root     home arthur Software django weclaim templates static          r  static   P lt path gt         django views static serve    document root   settings MEDIA ROOT        My  views py  in my  login  directory looks like   from django shortcuts import render to response  redirect from django template import RequestContext from django contrib import auth  def login view request       if request method     POST           uname   request POST get  username               psword   request POST get  password               user   auth authenticate username uname  password psword            if the user logs in and is active         if user is not None and user is active              auth login request  user              return render to response  main main html       context instance RequestContext request                return redirect main view          else              return render to response  loginpage html     box width    402    login failed    1     context instance RequestContext request       else          return render to response  loginpage html     box width    400     context instance RequestContext request    def logout view request       auth logout request      return render to response  loginpage html     box width    402    logged out    1     context instance RequestContext request     and finally the main html to which the login view points looks like    lt html gt   lt body gt  test   lt a href     url logout view     gt logout lt  a gt   lt  body gt   lt  html gt    So why do I get  NoReverseMatch  every time     on a slightly different note I had to use  context instance RequestContext request   at the end of all my render-to-response s because otherwise it would not recognise    MEDIA URL    in my templates and I couldn t reference any css or js files  I m not to sure why this is  Doesn t seem right to me

User · Answer

The url template tag will pass the parameter as a string and not as a function reference to reverse    The simplest way to get this working is adding a name to the view   url r   logout     logout view  name  logout view

User · Answer

Make sure  django 1 5 and beyond  that you put the url name in quotes  and if your url takes parameters they should be outside of the quotes  I spent hours figuring out this mistake        url  namespace view name  arg1 value1 arg2 value2 as the url     lt a href     the url     gt  link name  lt  a gt

User · Answer

Judging from your example  shouldn t it be    url myproject login views login view    and end of story   replace myproject with your actual project name

User · Answer

Instead of importing the logout view function  you should provide a string in your urls py file   So not  r  login    login view    but  r  login     login views login view     That is the standard way of doing things  Then you can access the URL in your templates using      url login views login view

User · Answer

The selected answer is out of date and no others worked for me  Django 1 6 and  apparantly  no registered namespace   For Django 1 5 and later  from the docs   Warning Don   t forget to put quotes around the function path or pattern name   With a named URL you could do   r  login    login view  name  login         lt a href  quot    url  login     quot  gt logout lt  a gt   Just as easy if the view takes another parameter def login request  extra param        lt a href  quot    url  login   some string containing relevant data     quot  gt login lt  a gt

User · Answer

I run into same problem   What I found from documentation  we should use namedspace   in your case    url login login view

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