c array assignment of multiple values

Question

so when you initialize an array  you can assign multiple values to it in one spot   int array       1 3 34 5 6    but what if the array is already initialized and I want to completely replace the values of the elements in that array in one line  so   int array       1 3 34 5 6  array       34 2 4 5 6    doesn t seem to work     is there a way to do so

User · Answer

You have to replace the values one by one such as in a for-loop or copying another array over another such as using memcpy(..) or std::copy

e.g.

for (int i = 0; i < arrayLength; i++) {
    array[i] = newValue[i];
}

Take care to ensure proper bounds-checking and any other checking that needs to occur to prevent an out of bounds problem.

User · Answer

const static int newvals      34 2 4 5 6    std  copy newvals  newvals sizeof newvals  sizeof newvals 0    array

User · Answer

There is a difference between initialization and assignment  What you want to do is not initialization  but assignment  But such assignment to array is not possible in C     Here is what you can do    include  lt algorithm gt   int array       1 3 34 5 6   int newarr       34 2 4 5 6   std  copy newarr  newarr   5  array       However  in C  0x  you can do this   std  vector lt int gt  array    1 3 34 5 6   array    34 2 4 5 6     Of course  if you choose to use std  vector instead of raw array

[c++] c++ array assignment of multiple values

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