PHP - cannot use a scalar as an array warning

Question

I have the following code     final   array        foreach   words as  word             query    SELECT Something            result    this- gt  db- gt fetchAll  query       word               foreach   result as  row                         id    row  page id                if   empty  final  id  0                                   final  id  0     final  id  0  3                            else                                final  id  0    3                   final  id   link          row  permalink                     final  id   title      row  title                                     The code SEEMS to work fine  but I get this warning   Warning  Cannot use a scalar value as an array in line X  Y  Z  the line with   final  id  0    3  and the next 2     Can anyone tell me how to fix this

User · Answer

A bit late  but to anyone who is wondering why they are getting the  Warning  Cannot use a scalar value as an array  message   the reason is because somewhere you have first declared your variable with a normal integer or string and then later you are trying to turn it into an array   hope that helps

User · Answer

Make sure that you don t declare it as a integer  float  string or boolean before  http   php net manual en function is-scalar php

User · Answer

The Other Issue I have seen on this is when nesting arrays this tends to throw the warning  consider the following    data      rs    gt  null     this above will work absolutely fine when used like    data  rs      5    But the  below will throw a warning      data          rs    gt            rs1    gt  null                      data rs  rs1    2     this will throw the warning unless assigned to an array

User · Answer

Also make sure that you don t declare it an array and then try to assign something else to the array like a string  float  integer   I had that problem   If you do some echos of output I was seeing what I wanted the first time  but not after another pass of the same code

User · Answer

You need to set final  id  to an array before adding elements to it  Intiialize it with either   final  id    array     final  id  0    3   final  id   link          row  permalink     final  id   title      row  title      or   final  id    array 0   gt  3    final  id   link          row  permalink     final  id   title      row  title

[php] PHP - cannot use a scalar as an array warning

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