[c#] LINQ Aggregate algorithm explained

A picture is worth a thousand words

Reminder:
Func<X, Y, R> is a function with two inputs of type X and Y, that returns a result of type R.

Enumerable.Aggregate has three overloads:


Overload 1:

A Aggregate<A>(IEnumerable<A> a, Func<A, A, A> f)

Aggregate1

Example:

new[]{1,2,3,4}.Aggregate((x, y) => x + y);  // 10


This overload is simple, but it has the following limitations:

  • the sequence must contain at least one element,
    otherwise the function will throw an InvalidOperationException.
  • elements and result must be of the same type.



Overload 2:

B Aggregate<A, B>(IEnumerable<A> a, B bIn, Func<B, A, B> f)

Aggregate2

Example:

var hayStack = new[] {"straw", "needle", "straw", "straw", "needle"};
var nNeedles = hayStack.Aggregate(0, (n, e) => e == "needle" ? n+1 : n);  // 2


This overload is more general:

  • a seed value must be provided (bIn).
  • the collection can be empty,
    in this case, the function will yield the seed value as result.
  • elements and result can have different types.



Overload 3:

C Aggregate<A,B,C>(IEnumerable<A> a, B bIn, Func<B,A,B> f, Func<B,C> f2)


The third overload is not very useful IMO.
The same can be written more succinctly by using overload 2 followed by a function that transforms its result.


The illustrations are adapted from this excellent blogpost.

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