I tried this example:
/* itoa example */
#include <stdio.h>
#include <stdlib.h>
int main ()
{
int i;
char buffer [33];
printf ("Enter a number: ");
scanf ("%d",&i);
itoa (i,buffer,10);
printf ("decimal: %s\n",buffer);
itoa (i,buffer,16);
printf ("hexadecimal: %s\n",buffer);
itoa (i,buffer,2);
printf ("binary: %s\n",buffer);
return 0;
}
but the example there doesn't work (it says the function itoa
doesn't exist).
This question is related to
c
string
integer
type-conversion
Making your own itoa
is also easy, try this :
char* itoa(int i, char b[]){
char const digit[] = "0123456789";
char* p = b;
if(i<0){
*p++ = '-';
i *= -1;
}
int shifter = i;
do{ //Move to where representation ends
++p;
shifter = shifter/10;
}while(shifter);
*p = '\0';
do{ //Move back, inserting digits as u go
*--p = digit[i%10];
i = i/10;
}while(i);
return b;
}
or use the standard sprintf()
function.
That's because itoa
isn't a standard function. Try snprintf
instead.
char str[LEN];
snprintf(str, LEN, "%d", 42);
Source: Stackoverflow.com