Convert dataframe column to 1 or 0 for true false values and assign to dataframe

Question

In the R cli I am able to do the following on a character column in a data frame    gt  data frame column name  data frame column name     true    lt - 1  gt  data frame column name  data frame column name     false    lt - 0  gt  data frame column name  lt - as integer data frame column name    I would like to do this as a function and I tried the following code  inputing data frame column name as arg1   I see that it is working when I return arg1  but how do I return the operation to the original data frame   boolean integer  lt - function arg1      arg1  arg1     true    lt - 1   arg1  arg1     false    lt - 0   arg1  lt - as integer arg1

User · Accepted Answer

chappers solution  in the comments  works as integer as logical data frame column name

User · Answer

Even when you asked finally for the opposite  to reform 0s and 1s into Trues and Falses  however  I post an answer about how to transform falses and trues into ones and zeros  1s and 0s   for a whole dataframe  in a single line   Example given   df  lt - structure list p1 1   c TRUE  FALSE  FALSE  NA  TRUE  FALSE                   NA   p1 2   c FALSE  TRUE  FALSE  NA  FALSE  NA                   TRUE   p1 3   c TRUE                   TRUE  FALSE  NA  NA  FALSE  TRUE   p1 4   c FALSE  NA                   FALSE   FALSE  TRUE  FALSE  NA   p1 5   c TRUE  NA                   FALSE  TRUE  FALSE  NA  TRUE   p1 6   c TRUE  NA                   FALSE  TRUE  FALSE  NA  TRUE   p1 7   c TRUE  NA                   FALSE  TRUE  NA  FALSE  TRUE   p1 8   c FALSE                   FALSE  NA  FALSE  TRUE  FALSE  NA   p1 9   c TRUE                   FALSE   NA  FALSE  FALSE  NA  TRUE   p1 10   c TRUE                   FALSE  NA  FALSE  FALSE  NA  TRUE   p1 11   c FALSE                   FALSE  NA  FALSE  NA  FALSE  TRUE     Names                    c  p1 1    p1 2    p1 3    p1 4    p1 5    p1 6                     p1 7    p1 8    p1 9    p1 10    p1 11    row names                     c NA  -7L   class    data frame       p1 1  p1 2  p1 3  p1 4  p1 5  p1 6  p1 7  p1 8  p1 9 p1 10 p1 11 1  TRUE FALSE  TRUE FALSE  TRUE  TRUE  TRUE FALSE  TRUE  TRUE FALSE 2 FALSE  TRUE  TRUE    NA    NA    NA    NA FALSE FALSE FALSE FALSE 3 FALSE FALSE FALSE FALSE FALSE FALSE FALSE    NA    NA    NA    NA 4    NA    NA    NA FALSE  TRUE  TRUE  TRUE FALSE FALSE FALSE FALSE 5  TRUE FALSE    NA  TRUE FALSE FALSE    NA  TRUE FALSE FALSE    NA 6 FALSE    NA FALSE FALSE    NA    NA FALSE FALSE    NA    NA FALSE 7    NA  TRUE  TRUE    NA  TRUE  TRUE  TRUE    NA  TRUE  TRUE  TRUE   Then by running that  df   1 all Falses and Trues are trasnformed into 1s and 0s  At least  this was happen in the R version that I have  R version 3 4 4  2018-03-15        gt  df 1   p1 1 p1 2 p1 3 p1 4 p1 5 p1 6 p1 7 p1 8 p1 9 p1 10 p1 11 1    1    0    1    0    1    1    1    0    1     1     0 2    0    1    1   NA   NA   NA   NA    0    0     0     0 3    0    0    0    0    0    0    0   NA   NA    NA    NA 4   NA   NA   NA    0    1    1    1    0    0     0     0 5    1    0   NA    1    0    0   NA    1    0     0    NA 6    0   NA    0    0   NA   NA    0    0   NA    NA     0 7   NA    1    1   NA    1    1    1   NA    1     1     1   I do not know if it a total  safe  command  under all different conditions   dfs

User · Answer

can you try if else   gt  col2 ifelse df1 col   true  1 0   gt  df1  col  1   true    false    gt  cbind df1 col         1      1    true    2    false   gt  cbind df1 col col2               col2  1    true    1    2    false   0

User · Answer

Try this  it will convert True into 1 and False into 0  data frame column name num   lt - as numeric data frame column name   Then you can convert into factor if you want  data frame column name num factor  lt - as  factor data frame column name num

User · Answer

Since you re dealing with values that are just supposed to be boolean anyway  just use    and convert the logical response to as integer   df  lt - data frame col   c  true    true    false    df       col   1  true   2  true   3 false df col  lt - as integer df col     true   df     col   1   1   2   1   3   0

[r] Convert dataframe column to 1 or 0 for "true"/"false" values and assign to dataframe

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